The information given represents lengths of sides of a right triangle with c the hypotenuse. Find the correct missing length to the nearest hundredth. A calculator may be helpful.a = 20, b = 28, c = ?

A.35.45

B.34.72

C.35.88

D.34.41

Answers

Answer 1

Answer: The answer is D. To solve for the third side we use the Pythagorean Theorem. It is expressed as the squared of the hypotenuse is equal to the sum of the squares of the two remaining sides, c^2 = a^2 + b^2.

We are given the sides of the triangle which were 20 and 28 thus we can solve for the hypotenuse.

c^2 = 20^2 + 28^2
c = √(20^2 + 28^2)
c = 34.41

Answer 2

Answer:

Answer:

34.41

Step-by-step explanation:

Using the Pythagorean Theorem:

a^2 + b^2 = c^2

20^2 + 28^2 = c^2

400 + 784 = c^2

1,184 = c^2

sqrt(1,184) = c

34.41 = c

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(I'll learn limits next year)
The function converges to 0.

3(x - 4) + 6 = 5(x - 1) + 1 solve for x and show work

Answers

Answer:

x= -1

Step-by-step explanation:

open brackets and calculate

3x - 12 + 6 = 5x -5 + 1

Calculate

3x - 6 = 5x - 4

transpose

3x - 5x = - 4 + 6

Calculate

- 2x = 2

x= 2/-2

x= -1

Answer:

X = -1

Step-by-step explanation:

3(x - 4) + 6 = 5(x - 1) + 1 -distribute

3x - 12 + 6 = 5x - 5 + 1 -combine like terms

3x - 6 = 5x - 4 -subtract 3x

-6 = 2x - 4 -add 4

-2 = 2x -divide by 2

-1 = x

Hope this helps. Pls give brainliest.

What is the equation of a circle with center (-2, 3) and radius 4?A.
B.
C.
D.

Answers

Hello,

(x+2)²+(y-3)²=16

Please help me with my question!!

Answers

Same with the other question we did, we are given the area of each tile which is 4 1/2in^2.

All we need to do it divide.

252 / 4.5 = 56

So, she would need 56 tiles in total.

Best of Luck!

Answer:

56 tiles

Step-by-step explanation:

$(252)/(4(1)/(2))= \n\n\n(252)/((9)/(2))= \n\n\n252* (2)/(9)= \n\n\n\boxed{56}$

Hope this helps!

Solve each system of equations using substitution. Show all work.1) y = 2x - 5
4x - y = 7

2) 2x - 3y = 12
x = 4y + 1

3) y = 5 - x
x - 4y = 10

Answers

1.
y=2x-5
sub that for y
4x-(2x-5)=7
distribute
4x-2x+5=7
2x+5=7
2x=2
x=1
sub back
y=2x-5
y=2(1)-5
y=2-5
y=-3

(1,-3)

2. x=4y+1
sub that for x
2(4y+1)-3y=12
8y+2-3y=12
5y+2=12
5y=10
y=2
sub back
x=4y+1
x=4(2)+1
x=8+1
x=9

(9,2)

3. y=5-x
sub that for y
x-4(5-x)=10
x-20+4x=10
5x-20=10
5x=30
x=6
sub back
y=5-x
y=5-6
y=-1
(6,-1)

soluitons

1. (1.-3)
2. (9,2)
3. (6,-1)

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