MATHEMATICS HIGH SCHOOL

In January, a bookstore sells 450 books, but in February, it sells only 300 books. What is the percent of change from January to February?66.7%
-33.3%
50%
-50%

Answers

Answer 1
Answer:

Answer:

- 33.33%

Step-by-step explanation:

Given,

The number of books sold  on January = 450,

While, the number of books sold on February = 300

Thus, the percent of change from January to February = \frac{\text{books sold on February-books sold on January}}{\text{books sold on January}}* 100

=(300-450)/(450)* 100

=-(15000)/(450)

\approx -33.33\%

Second option is correct.
Answer 2
Answer: January : 450 books
February : 300 books

the difference of Jan to Feb = 300 - 450 = -150
the percent of change = -150/450 x 100% = -33,3 %

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For today’s lunch, a school cafeteria’s budget allows it to purchase at most 60 cans of beans and 45 cans of corn. 1 can of beans feeds 5 students, and 1 can of corn feeds 6 students. Each student will have beans or corn, but not both, and there will be a maximum of 420 students at lunch. If a can of beans cost $2.00 and a can of corn cost $3.00, what is the maximum amount of money required to feed all of the students either beans or corn?A: $180

B: $195

C: $210

D: $225

Answers

Answer:

Option B.

Step-by-step explanation:

Let x be the number of cans of beans and y be the number of cans of corn.

Cafeteria’s budget allows it to purchase at most 60 cans of beans and 45 cans of corn.

x\leq 60

y\leq 45

1 can of beans feeds 5 students, and 1 can of corn feeds 6 students. Each student will have beans or corn, but not both, and there will be a maximum of 420 students at lunch.

5x+6y\leq 420

Can of beans cost $2.00 and a can of corn cost $3.00.

Objective function, Z=2x+3y

The required linear programming problem is

Objective function, Z=2x+3y

Subject to the constraints

x\leq 60

y\leq 45

5x+6y\leq 420

x\geq 0, y\geq 0       (Only 1st quadrant)

Draw the graph of these constraints as shown below.

The verities of common shaded region are (0,45), (30,45), (60,20), (60,0), (0,0).

Points            Z=2x+3y

(0,0)                    0

(0,45)                  135

(30,45)                195  

(60,20)                180

(60,0)                  120

The maximum amount of money required to feed all of the students either beans or corn is $195.

Number of cans of beans = 30

Number of cans of corn = 45

Therefore, the correct option is B.
I would go with B, one hundred ninety five dollars. Hope that this would help you..

There are 30 people in a class of which 30% are males. How many FEMALES are in the class?_____

Answers

To find the number of females in the class, we can start by calculating the number of males.

Given that 30% of the class are males, we can calculate it as follows:

Number of males = 30% of total number of people

              = 30% of 30

              = (30/100) * 30

              = 9

Since we know that the total number of people in the class is 30, we can find the number of females by subtracting the number of males from the total:

Number of females = Total number of people - Number of males

                = 30 - 9

                = 21

Therefore, there are 21 females in the class.  

(xa-b)/x=y
Make x the subject of the formula.

Answers

(xa-b)/x=y

xy=xa-b

xa-xy=b

x(a-y)=b

x=b/(a-y)
\frac{xa-b}x=y\nxa-b=xy\nxa-xy=b\nx(a-y)=b\nx=(b)/(a-y)

Eight over three times three over one

Answers

Answer: 8

Step-by-step explanation: 8/3 x 3/1 = 8

the measure of two complimentary angles is in the ratio 1:9. what are the degree measures of the two angles

Answers

x+9x=90\n10x=90\nx=9\n9x=9\cdot9=81

9 and 81.

in 2004, 510,000 acres of farmland in region were devoted to growing nuts. by 2011, the number of acres used to grow nuts had increased to 830,000. find the avarage rate of change in the number of acres in a region used to grow nuts from 2004 to 2011

Answers

Consider the (x, y) coordinates to be:  (2004, 510000) and (2011, 830000).

Average rate of change is another name for slope, So, use the slope formula: m = (y2 - y1)/(x2 - x1)

m = (830,000 - 510,000)/(2011 - 2004)

m = (320,000)/(7)

Answer: 320,000 acres every 7 years

Answer: 45714 per year.

Step-by-step explanation:

Given : In 2004, 510,000 acres of farmland in region were devoted to growing nuts. by 2011, the number of acres used to grow nuts had increased to 830,000.

Change in acres of farmland from 2004 to 2011 = 830000-510000=320,000

Change in year = 2011-2004=7

The average rate of change is given by :-

\frac{\text{Change in acres of farmland}}{\text{Change in year}}\n\n=(320000)/(7)=45714.2857143\approx45714 \text{[Rounded to the nearest integer.]}

Hence, the average rate of change in the number of acres in a region used to grow nuts from 2004 to 2011 is 45714 per year.
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