MATHEMATICS HIGH SCHOOL

Two angles are complementary. If one angle measures 25 degrees, what is the measure of the second angle?A. 65 degrees
B. 75 degrees
C. 155 degrees
D. 165 degrees

Answers

Answer 1
Answer:

Answer:

i think its C also

Step-by-step explanation:
Answer 2
Answer: I believe it is c.155 degrees

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Fill in the blank to find the X intercept
(__,0)

Answers

Answer:

-2

Step-by-step explanation:

Answer:

(-2,0)

Step-by-step explanation:

The graph passes through -2 on the x axis

A GPA is usually an example of a.

Answers

the answer is grade point average (GPA)

The length of a rectangle is 5 centimeters less than 2 times the width.a. Write a polynomial expression that represents ( 2 points )
the area of the rectangle.Simplify the expression.

Answers

Given:

The length of a rectangle is 5 centimeters less than 2 times the width.

To find:

The polynomial expression that represents the area of the rectangle, then simplify the expression.

Solution:

Let x be the width of the rectangle.

The length of a rectangle is 5 centimeters less than 2 times the width.

2 times the width = 2x

5 centimeters less than 2 times the width = 2x-5

Length of the rectangle = 2x-5

We know that, the area of a rectangle is:

A=length * width

A=(2x-5)* x

A=2x^2-5x

Therefore, the required polynomial expression is A=(2x-5)* x and its simplified form is A=2x^2-5x.

Jill Barkely obtained a 25-year, $460,000 mortgage loan from University Savings and Loan Association with 6% interest. The monthly payment is $2,962.40. For the first payment, find the interest to the nearest cent.

Answers

Have you considered calculating it directly? $2,962.40*(0.06/12)
If you do that then your answer would be 14.81...
Hope this helps...  :)

I don't get this question​

Answers

Answer:

1/4

Step-by-step explanation:

Use the equation of a line from 2 points.

Let P(x) = F(x)G(x) and Q(x) = F(x)/G(x), where F and G are the functions whose graphs are shown.(a) Find P '(2). (b) Find Q'(7).

Answers

Hello,

Very nice like question!

a)
F(2)=3 ; G(2)=2
F'(2)=0; G'(2)=1/2
P'(x)=F'(x)*G(x)+F(x)*G'(x)

P'(2)=0*2+3*1/2=3/2

b)
F(7)=5; G(7)=1
F'(7)=1/4; G'(7)=-2/3

Q'(x)=(F'(x)*G(x)-F(x)*G'(x)) / G²(x)

Q'(7)=(1/4*1-5*(-2/3))/1²=1/4+5/3=23/12
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