a rectangular lawn has a perimeter of 36 meters and a circular exercise run has a circumference of 36 meters which shape will give rico´s dog more area to run?

Answers

Answer 1

Answer: The shape is a rectangle lawn

Answer 2

Answer:

Final answer:

The circular exercise run provides more area for Rico's dog to run than the rectangular lawn. This is determined by calculating the maximum possible area for a rectangle with a perimeter of 36 meters and a circle with a circumference of 36 meters.

Explanation:

To answer which shape will give Rico's dog more area to run, we need to calculate the areas of the given shapes - a rectangle and a circle - using their respective perimeters/circumferences.

For a rectangle with a perimeter of 36 meters, one plausible dimension could be a rectangle with a length of 10 meters and a width of 8 meters, giving an area of 80 square meters assuming the shape is a square. (This gives the maximum area for a given perimeter).

The circumference of a circle is given by the formula 2πr, where r is the radius of the circle. If the circumference is 36 meters, then the radius would be 36/(2π) ≈ 5.73 meters. The area of this circle would then be πr², approximately 103.07 square meters.

In conclusion, the circle will offer more area for Rico's dog to run, despite the rectangular lawn and circular exercise run having the same perimeter and circumference lengths respectively.

Learn more about Area Comparison here:

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What is the median of the following numbers?
3.5.6.7,9,6,8

Answers

Ascending order= 3,5,6,6,7,8,

Total no of observations= 6 ( even no of observations)

Median= 3,5,6,6,7,8

= 6+6/2= 12/2 = 6

Median= 6

Hope You Understood

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In the diagram below, the top of each stair is parallel to the floor. What is the value of y?(Picture below.)

Answers

25°
as the stair is // to floor
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What is x+4/5=2/3- x-3/6

Answers

$x+(4)/(5)=(2)/(3)-x-(\not3^1)/(\not6_2)\n\nx+(4)/(5)=(2)/(3)-x-(1)/(2)\n\nfind\ LCD((4)/(5);\ (2)/(3);\ (1)/(2))=2*3*5=30\n\nmultiply\ both\ sides\ by\ LCD=30\n\n30x+30\cdot(4)/(5)=30\cdot(2)/(3)-30x-30\cdot(1)/(2)\n\n30x+6\cdot4=10\cdot2-30x-15\cdot1\n\n30x+24=20-30x-15$

$30x+24=5-30x\ \ \ \ |subtract\ 24\ from\ both\ sides\n\n30x=-19-30x\ \ \ \ \ |add\ 30x\ to\ both\ sides\n\n60x=-19\ \ \ \ \ |divide\ both\ sides\ by\ 60\n\n\boxed{x=-(19)/(60)}$

$(x+4)/(5)=(2)/(3)-(x-3)/(6)\n\n(x+4)/(5)=(2\cdot2)/(3\cdot2)-(x-3)/(6)\n\n(x+4)/(5)=(4)/(6)-(x-3)/(6)\n\n(x+4)/(5)=(4-(x-3))/(6)\n\n(x+4)/(5)=(4-x+3)/(6)\n\n(x+4)/(5)=(7-x)/(6)\ \ \ \ |cross\ multiply$

$6(x+4)=5(7-x)\n\n6(x)+6(4)=5(7)-5(x)\n\n6x+24=35-5x\ \ \ \ \ |subtract\ 24\ from\ both\ sides\n\n6x=11-5x\ \ \ \ \ |add\ 5x\ to\ both\ sides\n\n11x=11\ \ \ \ \ |divide\ both\ sides\ by\ 11\n\n\boxed{x=1}$

Meg started her trip with 11 1/2 gallons of gas in her car's tank. She bought an additional 6 4/5 gallons on her trip and arrived back home with 3 3/10 gallons left. How much gas did she use on the trip?

Answers

Answer:

Hence, the amount of gas she used on the trip is:

15 gallons.

Step-by-step explanation:

Meg started her trip with 11 1/2 gallons of gas in her car's tank.

i.e. we can represent the mixed fraction 11 1/2 in fraction as:

$11(1)/(2)=(23)/(2)gallons$

She bought an additional 6 4/5 gallons on her trip.

i.e. we can represent the mixed fraction 6 4/5 in fraction as:

$6(4)/(5)=(34)/(5)gallons$

Hence, the amount of gas filled in tank:

$=(23)/(2)+(34)/(5)\n\n=(23* 5+34* 2)/(10)\n\n=(115+68)/(10)\n\n=(183)/(10)gallons$

now after coming back home the amount of gas left in the car tank is:

3 3/10 gallons ; which could be represented in fraction as:

$3(3)/(10)=(33)/(10)$

Amount of gas used in the trip is:

=Amount of gas filled-gas remaining

$=(183)/(10)-(33)/(10)\n\n=(183-33)/(10)\n\n=(150)/(10)\n\n=15gallons$

Hence, the amount of gas she used on the trip is:

15 gallons.

Meg used 15 gallons. First you find the lowest common denominator to add 11 1/2 and 6 4/5, which is 10. What you do to the bottom you have to do to the top. You multiply 2 and 5, which gives you 10. 1 times 5 is 5... 11 5/10. 2 times 5 is 10, 4 times 2 is 8... 6 8/10. Add 11 5/10 and 6 8/10 and it gives you 18 3/10. To find out how much she used subtract the total amount she bought and how much she returned home with. The fractions cancel out since 3/10 minus 3/10 equals 0. You're just left with 18 minus 3, which is 15.

Larisa buys 5 hats for $9.99 each. how much does she spend

Answers

If you would like to know how much money does Larisa spend on the hats, you can calculate this using the following steps:

5 hats * $9.99 = 5 * 9.99 = $49.95

The correct result would be $49.95.

5 × $9.99 = $49.95 spent Larisa.

Can you draw an isosceles triangle with only one 80 degree angle. Is this the only possibility or can another triangle be drawn that will meet these conditions?

Answers

Answer:

The correct answer is yes, we can draw an isosceles triangle with only one 80° angle. NO this is not the only possibility.

Step-by-step explanation:

A triangle is a three sided figure. There are three types of triangles: Equilateral, Isosceles and Scalene triangle. The sum of angles in a triangle is 180°.

If all sides have equal length then it is an equilateral triangle. All angles of this triangle are equal.

If two sides are equal then it is an isosceles triangle. Two opposite angles are equal.

If none of the angles and sides are equal then we call it a scalene triangle.

Given one angle of the triangle is 80°.

There exists two possibilities. One, 80° is the equal angle and 80° is not the equal angle.

Required Case : 80° is not the equal angle, i.e. only one 80° angle.

We are to draw an isosceles triangle (say ABC) with one angle say ∠A as 80°.

Other two angles (∠B and ∠C) are 50° each as the other two angles are supposed to be equal. ( $(180-80)/(2)$ °).

Now let us consider side AB and AC be of length say a. These two sides are equal.

Thus now we have successfully constructed an isosceles triangle with only one 80° angle.

We can get infinitely many isosceles triangle by just varying the length of the equal side.

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