If 2.0 x 10^-4 C charge passes a point in 5.0 x 10^-5 s, what is the rate of current flow?4.0 x 10^-1 A
1.0 x 10^2 A
1.0 x 10^-10 A
4.0 x 10^0 A

Answers

Answer 1

Answer: Current is defined as the rate of charge flowing a point every second. Having a current of 1 Ampere signifies 1 Coulomb is flowing in a circuit every second. It is measured by the use of an ammeter which is positioned in series to the component to be measured. The current in the problem is calculated as follows:

I = 2.0 x 10^-4 C / 5.0 x 10^-5 s
I = 4 A or 4.0 x 10^0 A

Answer 2

Answer:

Answer:

Current is defined as the rate of charge flowing a point every second. Having a current of 1 Ampere signifies 1 Coulomb is flowing in a circuit every second. It is measured by the use of an ammeter which is positioned in series to the component to be measured. The current in the problem is calculated as follows:

Explanation:

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Locate the complete verbal phrase and identify its type.A boy named Robert won the high jump contest.
Verbal Phrase:
Type:

Answers

won
adjective

Verb phrases are verbs that may function as a predicate, adjective, or adverb.

(a) "That he said" is an adjective modifying "word". However, this contains the s ubject"he" and the verb "said". It is a clause and NOT a phrase. Phrases can only have either a verb or a noun.
(b) There's only one verb "was" but it does not come with a complement, object, modifier, or other verb. Hence, it's NOT a verb phrase.
(c) "Shall be" consists of the modal shall and the be-verb be. This is a perfect example of a verb phrase that functions as a VERB PHRASE.
(d) "Roared" and "charged" are two verbs referring to different subjects. They do not come with a complement, object, modifier, or another verb. Hence, they're NOT a verb phrase. "As the bull charged" is a clause and not a phrase.

The correct answer is:

Verbal Phrase: named Robert

Type: participial

A bicyclist bikes the 56 mi to a city averaging a certain speed. The return trip is made at a speed that is 6 mph slower. Total time for the round trip is 11 hr. Find the bicyclist's average speed on each part of the trip.

Answers

Answer:

Speed of the bicyclist when going to city = 14 miles per hour.

Speed while return trip = 8 miles per hour.

Explanation:

Let the speed of the bicyclist when going to city = x miles per hour.

Speed while return trip = x - 6 miles per hour.

Total time taken = 11 hrs = Time for the trip to city + time taken for return trip.

Also, Time = Distance / Time.

So,

56 / x + 56 / ( x -6) = 11

11x² -178x + 336 = 0

Solving for x we get:

Acceptable x = 14 miles per hour.

Speed while return trip = x - 6 miles per hour = 8 miles per hour.

Final answer:

To find the average speed on each part of the trip, use the formula Average speed = Total distance/Total time and set up an equation to solve for the unknown speeds.

Explanation:

To find the average speed on each part of the trip, we can use the formula Average speed = Total distance/Total time. Let's assume the average speed on the first part of the trip (56 miles) is x mph. Since the return trip is made at a speed that is 6 mph slower, the average speed on the second part of the trip is (x - 6) mph. We know that the total time for the round trip is 11 hours. So, we can set up the equation:

56/x + 56/(x - 6) = 11

Now, we can solve this equation to find the value of x, which represents the average speed on the first part of the trip. Once we have x, we can find the average speed on the second part of the trip by subtracting 6 from x.

Learn more about Average speed here:

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A ball of mass 0.120 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.600 m. What impulse was given to the ball by the floor?

Answers

Here are the given values:

mass (m) = 0.120kginitial velocity (Vo) = 0distance traveled (s) = 1.25 m

We first calculate for the final velocity of the ball:

Vf^2 = 2gs + Vo^2
Vf^2 = 2(9.8m/s2)(1.25m)
Vf = 4.95 m/s

Impulse = m(Vf−Vo)
Impulse = 0.120(4.95)
Impulse = 0.59 Ns

Before we find impulse, we need to find the initial and final momentum of the ball.

To find the momentum of the ball before it hit the floor, we need to figure out its final velocity using kinematics.

Values we know:
acceleration(a) - 9.81m/s^2 [down]
initial velocity(vi) - 0m/s
distance(d) - 1.25m [down]

This equation can be used to find final velocity:

Vf^2 = Vi^2 + 2ad

Vf^2 = (0)^2 + (2)(-9.81)(-1.25)

Vf^2 = 24.525

Vf = 4.95m/s [down]

Now we need to find the velocity the ball leaves the floor at using the same kinematics concept.

What we know:
a = 9.81m/s^2 [down]
d = 0.600m [up]
vf = 0m/s

Vf^2 = Vi^2 + 2ad

0^2 = Vi^2 + 2(-9.81)(0.6)

0 = Vi^2 + -11.772

Vi^2 = 11.772

Vi = 3.43m/s [up]

Now to find impulse given to the ball by the floor we find the change in momentum.

Impulse = Momentum final - momentum initial

Impulse = (0.120)(3.43) - (0.120)(-4.95)

Impulse = 1.01kgm/s [up]

What is an Atwood Machine?a. A double pulley system
c. A scale for measuring normal force
b. A suspended pulley
d. A simple lever

Answers

The best answer is letter (A) a double pulley system. Atwood Machine is normally used as a measurement in balancing to object to verify the mechanical law of motion with constant acceleration.

What's the measure of an arc with a central angle of 90°? question 20 options: 1) π° 2) 90° 3) 360° 4) 180°

Answers

The measure of an arc with a central angle of 90° is 90°. So the correct answer is 2) 90°.

A fault that is formed when compression causes the hanging wall to move over the foot wall is a(n) ______.

Answers

A fault that is formed when compression causes the hanging wall to move over to the foot wall is a : Reverse Fault
Reverse fault is exactly the opposite of the normal fault which will occur on the region/area undergoing the compression

hope this helps

It is Reverse or Reverse fault in other words - I just took the test this was the answer.

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