Calculate the pOH of a 0.410 M Ba(OH)2 solution.

Answers

Answer 1

Answer: The dissociation of this basic compound is: $Ba(OH)_2\ \to\ Ba^(2+) + 2OH^-$

There will be the double of $OH^-$ ions than molecules of $Ba(OH)_2$ , therefore, the concentration of $OH^-$ at the end will be 0.820 M.

$pOH = -log\ [OH^-] = - log (0.820) = \bf 0.09$

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Consider the following for the reaction at 300 K:3 ClO– (aq)  ClO3– (aq) + 2 Cl– (aq)ExperimentInitial [ClO–] (M)Initial Rate of Formation of ClO3– (aq)(M/min)10.4521.048 × 10–420.9034.183 × 10–4(7) (4 pts) What is the order of the reaction with respect to ClO– (aq)?A) 0B) 1C) 2(8) (4 pts) For experiment #2, what is the initial rate of consumption of ClO–

Answers

Answer:

Second order

Δ[ClO⁻]/Δt = - 4.183 x 10⁻⁴ M/min

Explanation:

Given the data:

Experiment # [ClO–] (M) Initial Rate of Formation of ClO3– (M/min)

1 10.452 1.048 x 10⁻⁴

2 20.903 4.183 x 10⁻⁴

we need to determine the order of the reaction with respect to ClO⁻.

We know the rate law for this reaction will have the form:

Rate = k [ClO⁻]^n

where n is the order of the reaction. Thus, what we need to do is to study the dependence of the initial rate on n for the experiment.

If the reaction were zeroth order the rate would not change, so we can eliminate n= 0

If the reaction were first order, doubling the concentration of [ClO–] , as it was done exactly in experiment # 2, the initial rate should have doubled, which is not the case.

If the reaction were second order n: 2, doubling the concentration of [ClO–] , should quadruple the initial rate of formation of ClO3–, which is what it is observed experimentally. Therefore the reaction is second order respect to ClO–.

The initial rate of consumption of ClO⁻ is the same as the rate of formation of ClO₃⁻ since:

Δ = - Δ[ClO⁻]/Δt = + Δ[ClO₃⁻]/Δt = + 1/2 [Cl⁻] /Δt

where t is the time.

from the coefficients of the balanced chemical equation.

- Δ[ClO⁻]/Δt = + Δ[ClO₃⁻]/Δt = + 1/2 [Cl⁻ ] = rate

Δ[ClO⁻]/Δt = - 4.183 x 10⁻⁴ M/min

Which chemical equation is correctly balanced?(1) H2(g) + O2(g)=> H2O(g)
(2) N2(g) + H2(g) =>NH3(g)
(3) 2NaCl(s)=>Na(s) + Cl2(g)
(4) 2KCl(s) => 2K(s) + Cl2(g)

Answers

2KCl(s) => 2K(s) + Cl2(g) is correctly balanced. Becuase 2 K, 2 Cl on the left, and 2 K, 2 Cl on the right.

The correct balanced chemicalequation is 2KCl(s) => 2K(s) + Cl2(g).

The correct balanced chemical equation from the options provided is (4) 2KCl(s) => 2K(s) + Cl2(g).

In this equation, two molecules of potassium chloride (KCl) react to form two molecules of potassium (K) and one molecule of chlorine gas (Cl2). This equation is balanced because the number of atoms of each element is equal on both sides of the equation.

For example, there are two atoms of potassium and two atoms of chlorine on both sides of the equation, ensuring the equation is balanced.

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Matt's cube, after 5 trials, had an average density of 7.40 g/cm3 . His group's cube was made ofA) aluminum.
B) gold.
C) nickel.
D) zinc.

Answers

The right answer for the question that is being asked and shown above is that: "B) gold." Matt's cube, after 5 trials, had an average density of 7.40 g/cm3 . His group's cube was made of B) gold.

its d zinc if your using usa test this dummy got me wrong trust me sis the answer is d

Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron falls from the n = 7 to the n = 4 principal energy level. Recall that the energy levels of the H atom are given by En = –2.18 × 10–18 J(1/n2)

Answers

Answer:

The wavelength of the light emitted by electron fall will be 216.62 nm.

Explanation:

The change in the energy state of the matter can be obtained from the principal quantum number of the shells.

Energy of 4th shell - Energy of 7th shell = $\rm \Delta$ E

$\Delta$ E = $\rm 2.18\;*\;10^-^1^8\;J\;\left ( (1)/(n_f^2) \;-\;(1)/(n_i^2) \right )$

$\rm \Delta\;E\;=\;-2.18\;*\;10^-^1^8\;\left ((1)/(4^2) \;-\;(1)/(7^2) \right )$

$\rm \Delta\;E\;=\;-2.18\;*\;10^-^1^8\;*\;0.0421$

$\rm \Delta\;E\;=\;0.0917\;*\;10^-^1^8$ J

The wavelength can be calculated as:

$\rm \Delta\;E\;=\;(hc)/(\lambda)$

where, h is Plank's constant,

c is speed of light

$\lambda$ is the wavelength

$\rm 0.0917\;*\;10^-^1^8\;J\;=\;(6.626\;*\;10^-^3^4\;J.s\;*\;2.998\;*\;10^8\;m/s)/(\lambda)$

$\rm\lambda\;=\;216.62nm$ .

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Answer:

The wavelength of the light emitted by a hydrogen atom for the given transition is 2166 nm.

Explanation:

The energy of nth energy levels of the H atom is given as:

$E_n = -2.18 * 10^(-18) * (1)/(n^2) J$

Energy of the seventh energy level = $E_7$

$E_7=-2.18 * 10^(-18) * (1)/(7^2) J$

$E_7=-2.18 * 10^(-18) * (1)/(7^2) J=-4.4490* 10^(-20) J$

Energy of the seventh energy level = $E_4$

$E_4=-2.18 * 10^(-18) * (1)/(4^2) J$

$E_4=-2.18 * 10^(-18) * (1)/(16) J=-1.3625* 10^(-19) J$

Energy of the light emitted will be equal to the energy difference of the both levels.

$E=E_7-E_4=-4.4490* 10^(-20) J-(-1.3625* 10^(-19) J)$

$E=9.176* 10^(-20) J$

Wavelength corresponding to energy E can be calculated by using Planck's equation:

$E=(hc)/(\lambda )$

$\lambda =(hc)/(E)=(6.626* 10^(-34) Js* 3* 10^8 m/s)/(9.176* 10^(-20) J)=2.166* 10^(-6) m=2166 nm$

The wavelength of the light emitted by a hydrogen atom for the given transition is 2166 nm.

Solar energy or energy from the sun is contained in

Answers

The solar energy is generated in the inner core of sun by nuclear fusion where hydrogen isotopes fuse together to form helium nuclei. This process is associated with the release of greater amount of energy.

What is nuclear fusion ?

Nuclear fusion is the process of fusing of two light nuclei to form a heavy nuclei. Whereas, breaking of a heavy unstable radioactive isotope is called nuclear fission. Both nuclear processes release tremendous energy.

The source of heat and light energy in sun and other stars is nuclear fusion in their core. Sun and stars are abundant in hydrogen gas. One protons and deuteron fuses together to form a helium nuclei.

This process repeats for major part of the hydrogen gas present in stars make them globes of fire and heat. Fusion takes place in the inner core of these stars. That is inside the chromosphere.

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Solar energy or energy from the sun is contained in fossil fuels. Hope you found this helpful! Good luck!

Rita divides Avogadro’s number (approximately 6.022 mc002-1.jpg 1023) by 2.0550 to calculate the number of atoms in a sample. Which expression gives her result to the correct number of significant figures?

Answers

Here you have two numbers. Avogadro's number is given with four significant figures, while number 2.0550 is given with five significant figures. That means that your result must be shown with four significant figures. So, 6.022 * 10 ^ 23 / 2.0550 = 2.930 * 10 ^ 23, which has been rounded to four significant figures. Answer: 2.930 * 10 ^ 23

Answer:

Answer is B

Explanation: Trust

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