3. A postcard has an area of 24 square inches. Two enlargementsof the postcard have areas of 54 square inches and 96 square inches. In each postcard, the length is 1 1/2 times the width.Which of the following could be the dimensions of the postcardor one of the enlargements? Mark all that apply.A) 6 inches by 9 inchesD)6 inches by 12 inchesB)10 inches by 15 inches E) 4 inches by 6 inchesC)8 inches by 12 inches

-3 + x2 = -19 does x = 4

Jasmine decided to go hot air ballooning for her fourteen birthday. She launches 6ft above ground and then ascends 12 ft further. She didn’t want to leave her husband behind, so she descends 20 ft to meet him. Where does jasmine end up. Plz answer this I will give you 100 points olz

Choose a number from 111 to 120 . Write the number. Draw a picture to show it as tens and ones

Which of the following relations is not a function? Mark all that apply.O A. {(-3, 8), (9, -12), (4, -1), (3, 8)}
O B. {(4,5),(4, - 7),(4,2), (4,0)}
O C. {(0,0), (4,0), (0.5, 4), (-4,4)}
OD. {(-6, -1),(5, -1), (0, -1), (3, -1)}
O E. {(5, -1}, (4, -2), (3, -3), (5, 1)}

Plz help, I need answers to these questions ASAP, would appreciate a short step-by-step explanation with each! WILL MARK BRAINLIEST!!!You’ve been given $500.00 for your fencing. So first we are going to make as big of a rectangular field as we can with the money that we have for the fencing to surround it. The cost of premium fencing (only the best for your farm, of course) is $11.41 per metre. So with that, and the following equations:
A=l*w
P=2l+2w
Where A is the area, P is the perimeter, l is the length, and w is the width of a rectangle, we can find the maximum area that we can have for this field.

Perimeter of fence:

Area of farm:



Let’s say we have access to planting 2 different crops, Watermelons and Grapes. We can find the revenue of a crop by the equation:
R = (p0 + px)(n0 - nx)
Where R is the revenue, p0 is the starting price, n0 is the amount sold at the starting price, p is the price increase, n is the decrease in the amount sold per price increase, and x is the number of price increases.
Crop A: Watermelons have a starting price of $12.00 per m2 of area sold. At this price, you can sell 45 m2 worth. For every $2.00 increase, you will sell 1 m2 less. So the first task is to figure out how to put these values into the equation above and turn it into a quadratic function. Then you will need to find the value of x to make the revenue as large as possible. Once you know x, the number of price increases, you can then find what you should price your Watermelons per m2.


Equation: R =

Number of price increases: x =

Price of Watermelon per m^2 =



Okay, now we can do the same thing with the grapes, just to give you that extra practice with quadratic functions. The starting price of grapes per m² is $8.00, at which you can sell 60 m² worth. For every $3.00 increase in price, you sell 3 m² less. So use the same method you just used to find the price of grapes per m² of area to maximize revenue.

Equation: R =

Number of price increases: x =

Price of grape per m^2 =



Okay, so now, all in all, we have built our farm and found what to price each of our crops at. Now let’s find what amount of each crop to grow and find our profits. Getting right into it, we have the following cost equations:
CW = $20.00 * W + $50.00
CG = $10.00 * G + $40.00
Where CW is the total cost of planting and growing Watermelons, CG is the total cost of planting and growing Grapes, W is the area of Watermelons planted, and G is the area of Grapes planted. Now that we know our cost, we can finally find our profits. Profit is equal to the price per unit area, multiplied by the area sold, subtracted by the total cost planting and growing them, or, Profit = Price * Area - Cost. But at this point, we still don’t know the area of each crop in our field. But we do know a couple of things to figure it out. We know the total area of our farm, found in the first part. Which we can say is, Area = G + W And we were also only given $1590 to plant the crops. So, $1590.00= CW+CG I’ll help you simplify this a bit:
$1590.00=$20.00*W+$50.00+$10.00*G+$40.00 $1590.00=$20.00*W+$10.00*G+$90.00
So now we have enough information to solve for the areas of Watermelons and Grapes in your field. Here’s some room to do that. Hint: Use either substitution or graph the two equations to find an intersection.

Area of watermelon to plant:

Area of grapes to pant:

Profit of the crops:

What is equal to 75% of 1/2