CHEMISTRY MIDDLE SCHOOL

What is a light-year? A.
the distance light travels in one earth year

B.
the distance light travels from the sun to the earth

C.
the distance light travels in one orbit of the moon

D.
the time it takes light to travel across the universe

Answers

Answer 1
Answer: The answer would be A. The distance light travels in one earth year. 
Answer 2
Answer: i think it is B the distance light travels from the sun to the earth 

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All of the following are true of metals exceptA. can conduct electricity B. have luster C. have low melting points ### D. are malleable is my answer right?
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Besides temperature and precipitation, which other factor does the Köppen climate classification system use todefine climate regions?
altitude
hemisphere
solar energy
vegetation?

Answers

Answer:

d

Explanation:

Answer:

D:vegetation

Explanation:

How many joules are needed to warm 675 grams of water (specific heat= 4.186 J/g degrees Celsius) from 12 degrees Celsius to 85 degrees Celsius?

Answers

Answer:

206,265.15 Joules are needed to warm 675 grams of water from 12 degrees Celsius to 85 degrees Celsius.

Explanation:

Between heat and temperature there is a direct proportionality relationship, where the constant of proportionality depends on the substance that constitutes the body. So, the equation that allows you to calculate heat exchanges is:

Q = c * m * ΔT

Where Q is the heat exchanged for a body of mass m, constituted by a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • Q=?
  • c=4.186 (J)/(g*degrees Celsius)
  • m=675 g
  • ΔT=Tfinal-Tinitial=85 degrees Celsius - 12 degrees Celsius= 73 degrees Celsius.

Replacing:

Q=4.186 (J)/(g*degrees Celsius)*675 g*73 degrees Celsius

Resolving you get:

Q=206,265.15 J

206,265.15 Joules are needed to warm 675 grams of water from 12 degrees Celsius to 85 degrees Celsius.
85-12 = 73 degrees needed
4.186 J/degree Celsius, so 
73 degrees * 4.186 J/degree = 305.578 J to raise 1 gram 73 degrees
there are 675 grams, so 305.578 * 675 = 206265.15 J

2.06 x 10^5 J are needed

What are some natural sources for cyanide

Answers

It can be found in cigarette smoke, plastic, cassava, Lima beans, and almonds
Cyanide is found in very many places, some we would never expect. Here's a list of what I know has traces of or has cyanide in it.

Paper.
Textiles.
Plastics.
Bug Killer (Cyanide gas is used to exterminate pests and vermin in ships and buildings)
Artificial Nail Remover. 
Any sort of acetonitrile-based products.
It is used to remove gold from it's ore.
It is present in the chemicals used to make photographs.
Cigarette Smoke
Vehicle Exhaust
Spinach.
Bamboo Shoots.
Almonds.
Lima Beans.
Miscellaneous Fruit Pits.
Tapioca.

These are just what I know of, I'm sure there's many more.

Hope this helped! :)

What is the Name of RbC2H3O2

Answers

Answer:

Rubidium Acetate

Explanation:

Rb is Rubidium C2H3O2 is acetate

Answer:

Rubidium Acetate-

Hope this helps ^-^* Sorry if I'm wrong.

Explanation:

What's something that is the measure of energy of motion of particles of matter

Answers

The measure of energy of motion of particles of matter is called Kinetic Energy and is measured in Joules.

I’m trying to learn molarity problems on my own (online schooling is terrible), I don’t need the answer for the following problem as much as I need the process of solving it explainedHow many L of solution are present if 100g NaCl has been dissolved in water to make a 2.50M solution?

Answers

Answer:

0.68L

Explanation:

First, let us calculate the number of mole in 100g of NaCl. This is illustrated below:

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl = 100g

Number of mole of NaCl =?

Number of mole = Mass/Molar Mass

Number of mole of NaCl = 100/58.5

Number of mole of NaCl = 1.709 mole

Now we can find the volume of the solution as follow:

Mole = 1.709 mole

Molarity = 2.50M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 1.709/2.5

Volume = 0.68L
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