What's the answer to: divide £48 in the ratio 7:5 (please show your working, much appreciated)

Answers

Answer 1
Answer: I can see you come from outside the USA. No insults intended!!
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Anyways, we have to put one side of the ratio and match it to 48. 
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Or even better...
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MAKE!!
A!!
PROPORTION!!
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So... Let's say 7 is proportional to 48... so 7/5 = 48/x, where x is the number equivalent to ratio of 5.
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Cross multiply!!
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7x = 240.
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Divide 7 on both sides.
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x = 34 2/7.
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Hope I helped!!

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Help! please give steps :) thanks 20pts

Answers

26. 
period=4
max=3
min=-3

27:
p=8
max=5
min=0

28:
p=8
max= 4 (twice)
min=-4 (twice)

Hope this helps.
Hello,
26.
period=4
max=3
min=-3

27:
p=8
max=5
min=0

28:
p=8
max= 4 (twice)
min=-4 (twice)


Solve the following equations.X^2 + 5x + 6 = 0
(Factorise)

X^2 + 7x + 11 = 0
(Use the quadratic formula)

Answers

facotr
ax^2+bx+c=0
find what 2 number multiply to c and add to b
what 2 numbers multiply to 6 and add to 5
2 and 3
(x+2)(x+3)=0
set to zero
x+2=0
x=-2
x+3=0
x=-3
x=-2 or -3



other one
for ax^2+bx+c=0
x=\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}

we are given
x^2+7x+11=0
a=1
b=7
c=11

sub
x=\frac{-7+/- \sqrt{7^(2)-4(1)(11)} }{2(1)}
x=(-7+/- √(49-44) )/(2)
x=(-7+/- √(5) )/(2)
x=(-7+ √(5) )/(2) or (-7- √(5) )/(2)



McDonald's sell milkshakes in two sizes a small milkshake contains 300ml and a large milkshake contains 2/3 more, how much does a large milkshake contain?

Answers

1/3 is 3/3 so 300/3 is 100 so 2/3 is 200 ml more so it holds 500 ml

How is 60 divided by 9 = 6.66666667?

Answers

60/9=6 remainder 4
Some division problems that require decimals
can be repeated 
To simplify 6.6666667 also means 6.666666666...and so on
To simplify 6.6666...
u put a bar over the 6 in the tens place.


2x - y = 10 y = -x - 1 Solve the system of equations (3, -4) no solution (9, 8)

Answers

Answer:

(3, -4)

Step-by-step explanation:

2x-y=10

y=-x-1

2x-(-x-1)=10

2x+x+1=10

3x=9

x=3

y=-3-1

y=-4

Solution: (3, -4)

The product of c and 7 is greater than -27

Answers

hii, I think you forgot to add a question :)