Graph the functions and approximate an x-value in which the exponential function surpasses the polynomial function. f(x) = 4x
g(x) = 4x2
The 2 in the 2nd equation is supposed to be an exponent btw
Answers
Answer:
Hi,
The answer is (-0.383,1) and (2,∞).
Step-by-step explanation:
See the attachment.
g(x) is a parabolic function, and the Image is always ≥ 0.
f(x) is a exponential function, and the Image is always ≥ 0.
At x = -0.383 , g(x) = 0.588 and f(x) = 0.588.
For x=(-0.383, 1), g(x) is greater than f(x).
At x = 1, g(x) = 1 and f(x) = 1.
For x=(1, 2), f(x) is greater than g(x).
At x= 2, g(x) = 16 and f(x) = 16
For x=(2,∞), g(x) is greater than f(x)
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Answers
The glass needed to frame the poster is 1500 square inches.
Given,
Matt is framing his favorite poster.
The poster is 30 incheswide and 50 inches long.
We need to find out how many square inches of glass will he need toframe the poster.
What is the area of a rectangle?
It is given by:
Area = Length x Width
We have,
Length = 30 inches
Width = 50 inches
We see that it is a rectangle.
Area of rectangle:
= Length x Width
= 30 x 50
= 1500 square inches.
Thus the glasses needed to frame the poster is 1500 square inches.
Learn more about rectangles here:
#SPJ2
Answers
The cost of parking in a lot can be calculated as; Cost = cost rate x time. Let the time = t. When time, t = 1 hour, Cost = 3 x 1 = $3. When time, t = 2 hours, Cost = 3 x 2 = $6. When time, t = 3 hours, Cost = 3 x 3 = $9. When time, t = 4 hours, Cost = 3 x 4 = $12. When time, t = 5, Cost = 3 x 5 = $15 (notice, $15 has exceeded $12, but the maximum cost has to be $12). Thus, the cost of parking in a lot depends on the amount of time the car is parked and not vice versa. Therefore, the amount of time a car is parked is not a function of the parking cost because time is an independent variable and the cost of parking depends on the time the car is parked
Answers
2x=-8
x=-8/2
x=-4
4x - 2 - 2x = (2x - 10) - 2x
2x - 2 = -10
(2x - 2) + 2 = -10 + 2
2x = -8
2x / 2 = -8 / 2
x = -4
graph of 2 x minus 4, with discontinuity at 1, negative 2
graph of 2 x plus 2, with discontinuity at negative 1, 0
graph of 2 x plus 2, with discontinuity at 1, 4
please and thank you
Answers
Solution:
The given function is
f(x)=
f(x)=
f(x)= 2 x - 2 -
To find the points of Discontinuity
Put, f(x)=0
→ 2 x - 2 - =0
→2 x² - 2 x - 4=0×x
→2 (x²-x-2)=0
→ x² - x -2=0
Splitting the middle term
→ x² - 2 x + x -2=0
→ x×(x-2)+ 1 × (x-2)=0
→ (x+1) (x-2)=0
Gives, x= -1, and x=2.
So, the graph represented by f(x)= is equal to f(x)= 2 x - 2 -
with points of Discontinuity at -1 and 2.
B.0.501
C.0.015
D.0.15
I don't need an answer i need an explanation
Answers
-- Look at all the digits in the first place after the decimal point.
Find the smallest one. If more than one number has that digit
in the first place, then keep those, discard the others, and ...
-- Look at the digits in the second place after the decimal point.
Find the smallest one. If more than one number has that digit
in the second place, then keep those, discard the others, and ...
-- Look at the digits in the third place after the decimal point.
Find the smallest one. If more than one number has that digit
in the third place, then keep those, discard the others, and ...
-- Look at all the digits in the fourth place after the decimal point.
Find the smallest one. If more than one number has that digit in
the fourth place, then keep those, discard the others and ...
.
.
.
etc.
Keep going until you have only one number left. That's the smallest one,
out of the entire original list.
In the example you gave, the smallest digit in the first place after the decimal point
is the '0', and choice-'C' is the only one that has it. So choice-'C' is the least, and
you don't need to go any farther.
Here's another one to practice on. It needs the whole procedure that I wrote out,
but now it should be easy for you:
0.1234607
0.1234915
0.1234095
0.1234017
0.1234184
0.1234521