Sue graphed the formula for converting temperatures from Fahrenheit to Celsius. If the temperature is 50 degrees Fahrenheit, what is the temperature in Celsius? 5 degrees Celsius 10 degrees Celsius 15 degrees Celsius 20 degrees Celsius

Answers

Answer 1

Answer:

Answer:

Second Option (10° Celsius)

Step-by-step explanation:

There is a formula to convert the temperature which is in degree Celsius into degree Fahrenheit and vice versa. The formula to convert the temperature in degree Fahrenheit into degree Celsius is:

C° = (F° - 32) * 5/9.

It is given that the temperature is 50° Fahrenheit. Therefore, F° = 50°. Substituting F° = 50° in the formula gives:

C° = (50° - 32) * 5/9.

Further simplification results in:

C° = 18 * 5/9. Therefore, C° = 10°.

So the correct answer is 10° Celsius!!!

Answer 2

Answer:

Answer:

its b

Step-by-step explanation:

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Solve the equation. 20 = –d + 16A. 4

B. –10

C. –6

D. –4

Answers

Hello there
The correct answer to this question would be D: negative 4

This is because the negatives from negative 4 and negative d would cancel each other out, to make it a positive 4, resulting in the equation being: 20 = 4 + 16 , which is true

I hope this helped ^^

What is the prime factorization of 120? A.

22 • 3 • 5

B.

23 • 3 • 5

C.

23 • 5

D.

24 • 3

Answers

A is the answer hdndnbdbfb

he prime factorization of 120 is 2*2*2*3*5 .

4x+11<23 solve this equation

Answers

4x + 11 < 23

- 11 - 11

4x < 12

4x/4 < 12/4

x < 3

Which statement describes the behavior of the function f(x)=3x/4-x?a. The graph approaches –3 as x approaches infinity.
b. The graph approaches 0 as x approaches infinity.
c. The graph approaches 3 as x approaches infinity.
d. The graph approaches 4 as x approaches infinity.

Answers

Answer:

The graph approaches –3 as x approaches infinity. Option a is correct.

Step-by-step explanation:

The given function is

$f(x)=(3x)/(4-x)$

We have to find value of function as x approaches infinity. Take limit both sides as x approaches to infinity.

$\lim_(x\rightarrow \infty)f(x)=\lim_(x\rightarrow \infty)(3x)/(4-x)$

Taking x common from the denominator.

$\lim_(x\rightarrow \infty)f(x)=\lim_(x\rightarrow \infty)(3x)/(x((4)/(x)-1))$

Cancel out common factor x.

$\lim_(x\rightarrow \infty)f(x)=\lim_(x\rightarrow \infty)(3)/((4)/(x)-1)$

Apply limits.

$\lim_(x\rightarrow \infty)f(x)=(3)/((4)/(\infty)-1)$

$\lim_(x\rightarrow \infty)f(x)=(3)/(0-1)$

$\lim_(x\rightarrow \infty)f(x)=-3$

Therefore the graph approaches –3 as x approaches infinity.

a. The graph approaches –3 as x approaches infinity.

$f(x) = (3x)/(4-x) +3 -3 = (3x+12-3x)/(4-x) -3 = (12)/(4-x) -3$

Add and subtract functions

Answers

Answer: $3x^2+5x+3$

Step-by-step explanation:

For this exercise you need to remember the multiplication of signs:

$(+)(+)=+\n(-)(-)=+\n(-)(+)=-\n(+)(-)=-$

You know that the function f(x) is:

$f(x)=5x+3$

And the function g(x) is:

$g(x)=3x^2$

Then to find $(f+g)(x)$ you need to add the function f(x) and the function g(x) by adding (or combining) the like terms, you get that the sum is the following:

$(f+g)(x)=(5x+3)+(3x^2)$

$(f+g)(x)=5x+3+3x^2\n\n(f+g)(x)=3x^2+5x+3$

As you can notice, when you add the functions given in the exercise, you get a Quadratic function, which is a function whose highest exponent is 2 and has this form:

$f(x) = ax^2 + bx + c$

Where "a", "b", and "c" are numbers ( $a\neq 0$ )

how do I figure out the weight loss of tina? she lost 3 pounds on the first week of her diet. she gained a pound on the second week, and then lost 2 pounds a week during every week afterwards. she has been dieting for a total of 13 weeks. how many pounds has tina lost in all?

Answers

1st week - Lost 3 pounds = +3
2nd week - Gained 1 pound = -1
3+13 = + 22

So 22+3 = 25 25-1 = 24

So Tina lost 24 pounds in 13 weeks.

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