A rectangular parking lot has a perimeter of 820ft. The area of the Parking lot measures 42000 ft2. What is the width of the parking lot.

Answers

Answer 1

Answer: 2W + 2L = 820
LW = 42,000 or L = 42,000/W
substitute second equation into first equation:
2W + 2(42,000/W) = 820
2W + 84,000/W = 820
2W^2/W + 84,000/W = 820W/W
2W^2 - 820W + 84,000 = 0
quadratic formula:
W = [820 +/- SQR(672,400 - 4(2)(84,000))]/2(2)
W = [820 +/- 20]/4
W = 200, 210
using second equation:
L = 42,000/200, 42,000/210 = 210, 200
The dimensions of the parking lot are 200ft by 210ft.

Answer 2

Answer:

Answer:

Long story short, the answer is C.) 210

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How many solutions does the following equation have? -6(x+7)=-4x-2

Answers

Answer:

one solution

x=-20

Answer:

-20

Step-by-step explanation:

-6(x+7)=-4x - 2

-6x - 42 =-4x - 2

-6x +4x=-2+42

-2x=40

x=-40:2

x=-20

Divide the following polynomial, then place the answer in the proper location on the grid. (9x 4 + 3x 3y - 5x 2y 2 + xy 3) / (3x 3 + 2x 2y - xy 2)

Answers

The answer is -4+72/2y+9 when you solve using polynomial division :)

The sum of two numbers is 95, and their difference is 61. What are the two numbers?

Answers

Let's call:

$first\#=x$

$second\#=y$

then

when we have a SUM, we have PLUS and when we have a DIFFERENCE, we have MINUS... Let's go then...

$\begin{Bmatrix}x+y&=&95\nx-y&=&61\end{matrix}$

now we can sum all the rows then we got it... (This is the other way to solved this question)

$x+y+(x-y)=95+61$

$x+y+x-y=156$

$2x=156$

$\boxed{x=78}$

now we can replace this value at first or at second row, you just need to pick up one...

I'll choose the second one

$x-y=61$

$78-y=61$

$y=78-61$

$\boxed{y=17}$

$\boxed{\boxed{\begin{Bmatrix}x&=&78\ny&=&17\end{matrix}}}$

$\left \{ {x+y=95} \atop {x-y=61}} \right. \n \n2x=156\nx= (156)/(2) \n \nx=78\n \ny=95-y\ny=95-78\ny=17$

First number 78, and the second is 17 .

Identify the arc length of TV in terms of π. (image is attached)The answers for this question were:

≈0.67pi in., ≈1.83pi in., ≈3.67pi in., or ≈1.33pi in.

Answers

The arc length of TV is ≈ 3.67π in.

What is Arc length?

Arc length is the distance between two points along a section of a curve.

Given:

∠SMV = 48 and MT= 5 in

As, ∠SMV and ∠VMT are forms linear pair. So,

∠VMT + ∠SMV = 180∘

∠VMT= 180 - ∠SMV

∠VMT = 180∘ − 48∘

∠VMT =132∘

Now, length of arc will be,

= $\theta$ /360 2πr

=132/360*2*π*5

=132/360*10π

=33/9π

≈ 3.67π in.

Hence, the arc length of TV is ≈ 3.67π in.

Learn more about Arc length here:

brainly.com/question/16403495

#SPJ2

Answer: ≈ 3.67π in.

Step-by-step explanation:

∠SMV and ∠VMT are supplementary. Therefore,

m∠VMT = 180∘ − m∠SMV

It is given that m∠SMV = 48∘. Substitute the given value and simplify.

m∠VMT = 180∘ − 48∘

=132∘ Arc length is the distance along an arc measured in linear units. The formula for Arc Length is L= 2πr (m∘/360∘).

The length of the radius is given as 5 in. Substitute the known values into the formula.

L= 2π (5) (132/360)

Simplify.

L= 33/9π

Round to the nearest tenth.

L ≈ 3.67π in.

Therefore, the arc length of TV is ≈ 3.67π in.

Write down the inequality described by "half of x is no more than three", and solve for x.

Answers

Answer:

Inequality: $(x)/(2) \leq 3$

Solved: $x\leq 6$

Step-by-step explanation:

$(x)/(2) \leq 3$

$x\leq 6$

It took Jimena 89 minutes to run a 15-kilometer race last weekend. If you know that 1 kilometer equals 0.621 mile, how many minutes did it take Jimena to run 1 mile during the race? Round your answer to the nearest hundredth.3.68 minutes

9.55 minutes

9.88 minutes

24.15 minutes

Answers

89/15 = 5.9333
1 mile = 1.60934 km
5.9333 X 1.60934 = 9.5486
9.5486 rounded to the nearest hundredth is 9.55 minutes.

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