Ben earns $9 per hour and $6 for each delivery he makes. He wants to make $155 in an 8-hour workday. What is the least number of deliveries he must make to reach his goal?
Answers
we know he will earn 8 hours sofirst find how many he earns
9 per hour
8 hou
9*8=72
72+6*numberofdeliveries=155
minus 72
6*numberofdeliviers=83
divide by 6
number of delevieries=13.8
he can't make 13.8, round up to get 14
answer is 14 deliveries
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2-x=3x-10 what does x equal
Dorothy and her twin sister will split the cost of a car when they are 16. their parents have agreed to pay 10% of the cost of the car. if they buy a car for $7,500 how much will each Sister pay?
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Assuming the 3s in both 4x³ and x³ are exponents, those would be like terms.
-7x² = (leave it like that)
x= (leave it like that too lol)
5x³ -7x² +x
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24.9828 SINCE YOU HAVE TO CONVERT 3% INTO A DECIMAL, 0.03 AND THEN MULTIPLY THAT BY 832.76
Answers
The statements that the principal could make when comparing the goals each grade has set are: 7th-grade plan to raise double the 5th grade, 6th-grade plan to raise 5th grade.6th-grade plan to raise
of 8th grade.
How do we compare numbers?
A comparison statement is, in general, just a statement that compares two quantities or values. For instance, "If we add x apples to 3 apples, then the total number of apples is less than 10 apples" or "Mary's height is the same as Milly's height."
In the given question, we have:
The amount with 5th grade is 120 dollars
The amount with 6th grade is 180 dollars
The amount with 7th grade is 240 dollars
The amount with 8th grade is 300 dollars
So, When we double that with 5th grade will be 240 dollar
Hence, The first statement can be a 7th-grade plan to raise double the 5th-grade.
Similarly,
If we multiply by the amount of 5th grade, we get 180 dollars.
and, when we multiply two-thirds of the 8th-grade amount, we get 180 dollars.
Hence, The three statements that we can write are:
7th-grade plan to raise double the 5th grade.
6th-grade plan to raise 5th grade.
6th-grade plan to raise of 8th grade.
(b)The two statements that could use to compare the goal to 8th graders are:
6th-grade plan to raise of 8th grade.
8th-grade plan multiplied by gives 7th grade plan.
When we multiply 300 by the amount we get 240 dollars.
Hence, The statement that the principal could use to compare the goal to the 8th grader's goal is:
6th-grade plan to raise of 8th grade.
8th-grade plan multiplied by gives 7th grade plan.
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centimeters. What are the dimensions
of the ticket?
centimeters by
centimeters
Answers
Answer:8 cm by 10 cm
Step-by-step explanation:
8*2+10*2=36
8*10=80
Answers
Answer: 8
Step-by-step explanation: because 8•8=64
• The first (leftmost) digit plus the second digit is the third digit.
• The second digit plus the third digit is the fourth digit.
• The third digit plus the fourth digit is the fifth (rightmost) digit.
• All of the digits are different.
How many different addy numbers are possible?
Answers
Answer:
Three different addy numbers are possible. They are 12358, 21347 and 31459.
Step-by-step explanation:
Let the 1st two digits of the numebr be x and y
Given that, 1st digit = x
2nd digit = y
3rd digit = x + y
4th digit = x + 2y
5th digit = 2x + 3y
None of the diigts can be 0 because then x = y, also none of the digits can be more tan 9 which limits the possible first digits as 1,2 and 3
(i) consider x= 1,hence 2x + 3y < 10
2 + 3y < 10
3y < 8
which makes y < , since y cant be 1, it is 2
sub x = 1, y = 2 we get the number as 12358.
(ii) consider x= 2,hence 2x + 3y < 10
4 + 3y < 10
3y < 6
which makes y < 2,then y becomes 1
sub x = 2, y = 1 we get the number as 21347.
(iii) consider x= 3,hence 2x + 3y < 10
6 + 3y < 10
3y < 4
which makes y < , then y becomes 1
sub x = 3, y = 1 we get the number as 31459.
Final answer:
There are 26 unique addy numbers. The possible first digits for an addy number are only 1 through 4. The rest of the digits are deterministically found by the sums of adjacent digits and condition of each digit being unique.
Explanation:
An 'addy' number is a 5-digit number with specific addition rules between adjacent digits. To determine how many possible addy numbers there are, we need to analyze the rules and work out possible combinations.
Firstly, no digit can be zero because all digits must be a part of the sum which means the minimum value should be 1. And, as we move forward, since each number must be unique, it limits our possibilities of choosing values.
Consider the following: If the first digit is 1, the second could be any number from 2 to 9 (8 choices). The resulting third digit would be uniquely determined since it is the sum of the first two digits. This continues through the rest of the number, with each subsequent digit determined by the sum of the previous two digits. The only restriction is that a digit cannot be repeated, and thus the sum of two digits cannot go above 9.
By trying this approach with different starting numbers (1 through 4), we realize that the maximum number of unique addy numbers can be calculated as the sum of the series 8, 7, 6, 5 which is 26.
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