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A long wire carries a current toward the south in a magnetic field that is directed vertically upward. What is the direction of the magnetic force on the wire?

Answers

Answer 1

Answer:

Answer:

the answer is it is going north

Explanation:

because its the opposite

Answer 2

Answer:

Final answer:

The magnetic force on a wire carrying current towards the south under a magnetic field directed vertically upwards will point towards the East. In order to determine this, use the right-hand rule.

Explanation:

The direction of the magnetic force on a current-carrying wire under a magnetic field can be deduced using the right-hand rule. In this case, with the current flowing towards the south and the magnetic field directed vertically upward, you would point your right thumb in the direction of the current (southwards) and curl your fingers in the direction of the magnetic field (upwards). The palm of your hand will then face toward the direction of the force. In this case, the force would be pointing toward the East.

The right-hand rule is a vital principle in the study of electromagnetism as it aids in identifying the direction of various quantities in magnetic fields. The magnetic force on a current-carrying wire represents the phenomenon underlying the working of many electric motors.

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A wheel 2.45 m in diameter lies in a vertical plane and rotates about its central axis with a constant angular acceleration of 4.30 rad/s2. The wheel starts at rest at t = 0, and the radius vector of a certain point P on the rim makes an angle of 57.3° with the horizontal at this time. At t = 2.00 s, find the following.a. the angular speed of the wheel and, for point P
b. the tangential speed.
c. the total acceleration.
d. the angular position.

Answers

(a) The angular speed of the wheel at point P is 8.6 rad/s.

(b) The tangential speed of the wheel is 10.54 m/s.

(d) The angular position of the wheel is 87 ⁰.

The given parameters;

diameter of the wheel, d = 2.45 m
radius of the wheel, r = 1.225 m
angular acceleration of the wheel, α = 4.3 rad/s²
angular displacement of the wheel, θ = 57.3⁰
time of motion, t = 2.0 s

The angular speed of the wheel at point P is calculated as follows;

$\omega_f = \omega _i + \alpha t\n\n\omega _f = 0 + 4.3 * 2\n\n\omega _f = 8.6 \ rad/s$

The tangential speed of the wheel is calculated as follows;

$v = \omega _f r\n\nv = 8.6 * 1.225 \n\nv = 10.54 \ m/s$

The centripetal acceleration of the wheel is calculated as follows;

$a_c = (v^2)/(r) \n\na_c = ((10.54)^2)/(1.225) \n\na_c = 90.69 \ m/s^2$

The total acceleration of the wheel is calculated as follows;

$a_t = √(a_c^2 + a_r^2) \n\na_t = √(90.69^2 + 4.3^2) \n\na_t = 90.8 \ m/s^2$

The angular position is calculated as follows;

$\theta = tan^(-1) ((a_c)/(a_r) )\n\n\theta = tan^(-1) ((90.69)/(4.3) )\n\n\theta = 87 \ ^0$

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Answer:

Explanation:

Radius of wheel R = 1.225 m

For angular motion of wheel

ω = ω ₀ + α t

= 0 + 4.3 x 2

= 8.6 rad / s

This is angular speed of wheel and point P .

b )

Tangential speed = ωR

8.6 x 1.225

= 10.535 m / s

c )

radial acceleration

a_r = v² / r

= 10.535² / 1.225

= 90.6 m / s²

tangential acceleration = radius x angular acceleration

a_t = 4.3 x 1.225

= 5.2675

Total acceleration = √ 90.6² + 5.2675²

= √ 8208.36 + 27.7465

= 90.75 m/s²

d ) angle of rotation

= 1/2 α t²

= .5 x 4.3 x 4

= 8.6 radian

= (8.6/3.14) x 180

= 499 degree

= 499 + 57.3

= 556.3

556.3 - 360

= 196.3 degree

Point p will rotate by 196.3 degree

A mass of 0.14 kg is attached to a spring and set into oscillation on a horizontal frictionless surface. The simple harmonic motion of the mass is described by x(t) = (0.28 m)cos[(8 rad/s)t]. Determine the following. (a) amplitude of oscillation for the oscillating mass .

Answers

Answer:

The amplitude of oscillation for the oscillating mass is 0.28 m.

Explanation:

Given that,

Mass = 0.14 kg

Equation of simple harmonic motion

$x(t)=(0.28\ m)\cos[(8\ rad/s)t]$ ....(I)

We need to calculate the amplitude

Using general equation of simple harmonic equation

$y=A\omega \cos\omega t$

Compare the equation (I) from general equation

The amplitude is 0.28 m.

Hence, The amplitude of oscillation for the oscillating mass is 0.28 m.

Consider a space shuttle which has a mass of about 1.0 x 105 kg and circles the Earth at an altitude of about 200.0 km. Calculate the force of gravity that the space shuttle experiences

Answers

Final answer:

The force of gravity that the space shuttle experiences is 9.8 x 10^5 Newtons.

Explanation:

To calculate the force of gravity that the space shuttle experiences, we can use the equation F = mg, where F represents the force of gravity, m is the mass of the object, and g is the acceleration due to gravity (approximately 9.8 m/s² on Earth). In this case, the mass of the space shuttle is given as 1.0 x 10^5 kg. However, we need to convert the altitude of the shuttle into meters, so 200.0 km becomes 200,000 meters.

Now we can calculate the force of gravity:

F = (1.0 x 10^5 kg)(9.8 m/s²)

F = 9.8 x 10^5 N

Therefore, the space shuttle experiences a force of gravity of 9.8 x 10^5 Newtons.

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1. Draw a quantitative motion map for the following description: A bicyclist speeds along a road at 10 m/s for 6 seconds. Then she stops for three seconds to make a 180˚ turn and then travels at 5 m/s for 3 seconds.

Answers

Answer:

Please find the attached file for the figure.

Explanation:

Given that a bicyclist speeds along a road at 10 m/s for 6 seconds.

Its acceleration = 10/6 = 1.667 m/s^2

The distance covered = 1/2 × 10 × 6

Distance covered = 30 m

That is, displacement = 30 m

Then she stops for three seconds to make a 180˚ turn and then travels at 5 m/s for 3 seconds.

The acceleration = 5/3 = 1.667 m/s^2

The displacement = 1/2 × 5 × 3

Displacement = 7.5 m

The resultant acceleration will be equal to zero.

While the resultant displacement will be:

Displacement = 30 - 7.5 = 22.5 m

Please find the attached file for the sketch.

What explains why a prism separates white light into a light spectrum?A. The white light, on encountering the prism, undergoes both reflection and refraction; some of the reflected rays re-enter the prism merging with refracted rays changing their frequencies.
B. The white light, on entering a prism, undergoes several internal reflections, forming different colors.
C. The different colors that make up a white light have different refractive indexes in glass.
D. The different colors that make up a white light are wavelengths that are invisible to the human eye until they pass through the prism.
E. The different rays of white light interfere in the prism, forming various colors.

Answers

Answer :

QUESTION①)

What explains why a prism separates white light into a light spectrum ?

C. The different colors that make up a white light have different refractive indexes in glass.

✔ Indeed, depending on the radiation (and therefore colors), which each have different wavelengths, the refraction index varies: the larger the wavelength (red) the less the reflection index is important and vice versa (purple).

✔ That's why purple is more deflected so is lower than red radiation.

Answer:

I think the answer probably be B

At one instant, a 17.0-kg sled is moving over a horizontal surface of snow at 4.10 m/s. After 6.15 s has elapsed, the sled stops. Use a momentum approach to find the magnitude of the average friction force acting on the sled while it was moving.