Which substances can act as an arrhenius acid in aqueous solution(1) NaI
(2) HI
(3) LiH
(4) NH3

Answers

Answer 1

Answer:

An Arrhenius acid is a proton donor, hence among the following, HI is an Arrhenius acid in aqueous solution.

What is an acid?

Acids are defined as substances which on dissociation yield H+ ions , and these substances are sour in taste. Compounds such as HCl, H₂SO₄ and HNO₃ are acids as they yield H+ ions on dissociation.

According to the number of H+ ions which are generated on dissociation acids are classified as mono-protic , di-protic ,tri-protic and polyprotic acids depending on the number of protons which are liberated on dissociation.

Acids are widely used in industries for production of fertilizers, detergents batteries and dyes.They are used in chemical industries for production of chemical compounds like salts which are produced by neutralization reactions.

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Answer 2

Answer: HI acts as an arrhenius acid in solution. It will dissociate into H⁺ and I⁻ therefore being a proton donor. (HI is actually one of the 7 strong acids)
I hope this helps.

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Formula for sulfur tetrafluoride

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The answer is SFl4 tetra means four

Please answer immediatelyHow many grams of glucose, C6H12O6, are needed to make 100 mL of a 1.5 M solution?

Answers

THE ANSWER BOI:

27 g

HERE IS DA EXPLANATION FAM:

27 g

M(C6H12O6) = 6*12 + 12*1 + 6*16 = 180 g/mol

100 mL = 0.1 L solution

1.5 M = 1.5 mol/L

1.5 mol/L * 0.1 L = 0.15 mol C6H12O6

0.15 mol * 180 g/1 mol = 27 g C6H12O6

Final answer:

To find the needed grams of glucose for a 1.5 M solution in 100ml, you multiply the molarity by the molecular weight of glucose and the volume of the solution. The calculation is 1.5 mol/l * 180 g/mol * 0.1 l = 27 grams. Therefore, 27 grams of glucose is needed.

Explanation:

The problem in question requires you to make use of the formula M= mass (mol)/ Volume (L). To find the required grams of glucose, C6H12O6, for a 1.5 M solution in 100mL, you would multiply the molarity with the molecular weight of glucose - approximately 180g per mole - and the volume of the solution - 0.1L. Therefore, to solve the problem you would calculate it as: 1.5 mol/l X 180 g/mol x 0.1 l which equals 27g. Hence, you need 27 grams of glucose to make a 100ml, 1.5M solution.

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What is the minimum pressure in kPa that must be applied at 25 °C to obtain pure water by reverse osmosis from water that is 0.227 M in sodium chloride and 0.078 M in magnesium sulfate? Assume complete dissociation for electrolytes.

Answers

What we need to know is the molarity of all the particles of NaCl taking into account that NaCl = Na+ + Cl- and the ones of taking into account that MgSO4=Mg+2 + SO4-2. we are going to use a formula to get the molarity like this: M = 2(0.227 M) + 2(0.078 M)
M = 0.61 M
After that to get the atm we do it like this:
Π = (0.61 M)(0.08206 atm-L/mol-K)(25 + 273 K)
Π = 14.9 atm
and then we do this multyplication
(14.9 atm)(101.3 kPa/atm) = 1509.37 kPa

Rutherford’s gold foil experiment gave evidence that an atom is mostly empty space. true false

Answers

The given statement is true .

What is Rutherford’s gold foil experiment?

A piece of gold foil was hit with alpha particles, which have a favorable charge. Most alpha particles went right around. This showed that the gold particles were mostly space.

The Rutherford gold leaf investigation supposed that most (99%) of all the mass of an atom is in the middle of the atom, that the nucleus is very small (105 times small than the length of the atom) and that is positively captured.

For the distribution experiment, Rutherford enjoyed a metal sheet that could be as thin as practicable. Gold is the most malleable of all known metals. It can easily be converted into very thin sheets. Hence, Rutherford established a gold foil for his alpha-ray scattering experimentation.

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What is sublimation?

Answers

Sublimation is the transition from solid to gaseous.

hope this helps!

Solidsto gases without entering liquid state

Matt's cube, after 5 trials, had an average density of 7.40 g/cm3 . His group's cube was made ofA) aluminum.
B) gold.
C) nickel.
D) zinc.

Answers

The right answer for the question that is being asked and shown above is that: "B) gold." Matt's cube, after 5 trials, had an average density of 7.40 g/cm3 . His group's cube was made of B) gold.

its d zinc if your using usa test this dummy got me wrong trust me sis the answer is d

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