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A flat circular coil having a diameter of 25 cm is to produce a magnetic field at its center of magnitude, 1.0 mT. If the coil has 100 turns how much current must pass through the coil?

Answers

Answer 1

Answer:

Answer:

The current pass through the coil is 6.25 A

Explanation:

Given that,

Diameter = 25 cm

Magnetic field = 1.0 mT

Number of turns = 100

We need to calculate the current

Using the formula of magnetic field

$B =(\mu_(0)NI)/(2\pi r)$

$I=(B*2\pi r)/(\mu N)$

Where, N = number of turns

r = radius

I = current

Put the value into the formula

$I=(1.0*10^(-3)*2\pi*12.5*10^(-2))/(4\pi*10^(-7)100)$

$I=6.25\ A$

Hence, The current passes through the coil is 6.25 A

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The cart is initially at rest. ForceF is applied to the cart for time ? t, after which the car has speed v. Suppose the same force is applied for the same time to a second cart with twice the mass. Friction is negligible. Afterward, the second cart's speed will be
a) 2v
b) 1/2v
c) v
d) 4v
e) 1/4v

Answers

Answer:

$v'=(1)/(2)v$

Explanation:

Given that,

Initial speed of the cart, u = 0

Let F force is applied to the cart for time $\Delta t$ after which the car has speed v. The force on an object is given by :

F = ma

m is the mass of the cart

We need to find the speed of second cart, if the same force is applied for the same time to a second cart with twice the mass. Force becomes,

$F=(mv')/(t)$

$v'=(F t)/(2m)$

$v'=(1)/(2)v$

So, the speed of second cart is half of the initial speed of first cart. So, the correct option is (b).

If a charge is located at the center of a spherical volume and the electric flux through the surface of the sphere is φ o, what is the flux through the surface if the radius of the sphere doubles?

Answers

Answer:

The electric flux remains unchanged

Explanation:

From Gauss law the Electric flux is directly proportional to the number of electric field lines passing through a surface. The number of field lines passing through a surface become if the radius is doubled becomes 1/4th that is when radius of the Gaussian surface is doubled, but at the same time, the surface area has increased 4 times , so the electric flux remains unchanged

Two objects of equal mass are a distance of 5.0 m apart and attract each other with a gravitational force of 3.0 x 10^-7 N find their mass.A) 150 kg
B) 9.8 kg
C) 11.000 kg
D) 340 kg

Answers

Answer

I Think Its 150

As frequency increases in an electromagnetic wave, its photon energy decreases. A. True B. False

Answers

Answer:

False

Explanation:

Answer:

False

Explanation:

A P E X

A 750-kg automobile is moving at 26.2 m/s at a height of 5.00 m above the bottom of a hill when it runs out of gasoline. The car coasts down the hill and then continues coasting up the other side until it comes to rest. Ignoring frictional forces and air resistance, what is the value of h, the highest position the car reaches above the bottom of the hill?

Answers

To solve this problem it is necessary to apply to the concepts related to energy conservation. For this purpose we will consider potential energy and kinetic energy as the energies linked to the body. The final kinetic energy is null since everything is converted into potential energy, therefore

Potential Energy can be defined as,

$PE = mgh$

Kinetic Energy can be defined as,

$K= (1)/(2) mv^2$

Now for Conservation of Energy,

$KE_i+PE_i = PE_f$

$(1)/(2)mv_i^2+mgh_1 = mgh_2$

$(1)/(2) (750kg) (26.2m/s)^2 + (750)(9.8)(5) = (750)(9.8)h_2$

$h_2 = 40.0224m$

Therefore the highets position the car reaches above the bottom of the hill is 40.02m

A race car travels on a circular track at an average rate of 125 mi/h. The radius of the track is 0.320 miles. What is the centripetal acceleration of the car? 391 mi/h2 40.0 mi/h2 5,000 mi/h2 48,800 mi/h2

Answers

$a_(centrip)= (v^2)/(R)= (125^2 )/(0.32)=48828 (mi)/(h^2)$
The last one is the closest

48,800 mi/h2 is the right answer

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