A box contains five slips of paper. Each slip has one of the number 4, 6, 7, 8, or 9 written on it and all numbers are used. The first player reaches into the box and draws two slips and adds the two numbers. If the sum is even, the player wins. If the sum is odd, the player loses.

Answers

Answer 1

Answer:

Answer: 70% chance of winning

Step-by-step explanation: What is your question? Are you trying to ask the probability of winning? (I will assume this and answer)

The whole case of selecting to numbers : 5C2 = 5 X 4 / 2 = 10

the cases of getting a odd sum : select 1 odd number and 1 even number

=> select 1 odd number : 7 or 9 => 2 cases

=> select 1 even number: 4,6,8 => 3 cases

you multiply 2 and 3 and divide it by 2 because order doesn't matter

so the answer is 1 - (3/10) = 0.7

Answer 2

Answer:

Final answer:

The player in the game has an equal chance of winning or losing.

Explanation:

In this problem, we are given a box containing five slips of paper, each with a number written on it. The first player draws two slips and adds the two numbers together. To determine if the player wins or loses, we need to determine if the sum of the two numbers is even or odd.

To solve this problem, we can list all the possible pairs of numbers and find out if the sum of each pair is even or odd. If the sum is even, the player wins; if the sum is odd, the player loses. We can do this by considering the possible outcomes:

(4, 6) - sum is 10 (even)
(4, 7) - sum is 11 (odd)
(4, 8) - sum is 12 (even)
(4, 9) - sum is 13 (odd)
(6, 7) - sum is 13 (odd)
(6, 8) - sum is 14 (even)
(6, 9) - sum is 15 (odd)
(7, 8) - sum is 15 (odd)
(7, 9) - sum is 16 (even)
(8, 9) - sum is 17 (odd)

From the listed outcomes, we can see that there are 5 even sums and 5 odd sums.

Therefore, the player has an equal chance of winning or losing in this game.

Learn more about Game Probability here:

brainly.com/question/35420575

#SPJ2

Related Questions

Can someone help with this plz
The diameter of a soccer ball is 8.65 inches what is the volume of the ball rounded to nearest hundredth
What is the area of the triangle and perimeter of this triangle
ivan saves 20 percent of his monthly paycheck for music equipment. he earned $335 last month. how mush money did ivan save for music equimpet
What is the sum of 2/5 and 2/4?

What is the factoring quadratic expression for 27x^2-12=0

Answers

$27x^2-12=0\ /:3\n\n9x^2-4=0\ \ \ \Leftrightarrow\ \ \ (3x)^2-2^2=0\ \ \ \Leftrightarrow\ \ \ (3x-2)(3x+2)=0\n\n3x-2=0\ \ \ \ \ \ \ \ or\ \ \ \ \ \ 3x+2=0\n\n3x=2\ /:3\ \ \ \ \ \ \ or\ \ \ \ \ \ 3x=-2\ /:3\n\nx= (2)/(3) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ or\ \ \ \ \ \ x=- (2)/(3)$

$27x^2-12=0\n 3(9x^2-4)=0\n 3(3x-2)(3x+2)=0\n x=(2)/(3) \vee x=-(2)/(3)$

a rectangular field with a area of 8000m2 is enclosed by 400m of fencing. determine dimensions to nearest tenth of a metre

Answers

$field:x\ *\ y\n\n \left\{\begin{array}{ccc}x\cdot y=8000\n2x+2y=400&/:2\end{array}\right\n\left\{\begin{array}{ccc}x\cdot y=8000\nx+y=200&\to x=200-y\end{array}\right\n\nsubstitute\ to\ x\cdot y=8000\n\n(200-y)\cdot y=8000\n\n-y^2+200y-8000=0\n\n\Delta=b^2-4ac;\ \Delta=200^2-4\cdot(-1)\cdot(-8000)=40000-32000=8000\n\ny_1=(-b-\sqrt\Delta)/(2a);\ y_2=(-b+\sqrt\Delta)/(2a)$

$\sqrt\Delta=√(8000)=√(1600\cdot5)=40\sqrt5\n\ny_1=(-200-40\sqrt5)/(2\cdot(-1))=(-200-40\sqrt5)/(-2)=100+20\sqrt5\approx144.7\ (m)\n\ny_2=(-200+40\sqrt5)/(2\cdot(-1))=(-200+40\sqrt5)/(-2)=100-20\sqrt5\approx55.3\ (m)\n\nx_1\approx200-144.7=55.3\ (m)\n\nx_2\approx200-55.3=144.7\ (m)\n\nAnswer:Dimension of the field is:55.3m\ *\ 144.7m$

A class of 25 students took a math test. Ten students had an average of 88. The other students had an average of 76. What is the average of the whole class?A) 78.2
B) 80.8
C) 81.7
D) 82.5

Answers

Answer:

The average of the whole class is 80.8.

The correct answer is B)

Step-by-step explanation:

To solve this problem, it is very important to understand the phrase: "Ten students had an average of 88". Let's see an example.

Imagine that three students in the class took a test and their scores were: 80, 89 and 95. To calculate the average of they three we must divide the sum of the scores by the total number of scores.

$average=(80+89+95)/(3)=(264)/(3)=88$

The previous value is the average of the three students. Now, if we say that each student got 88, the average would be 88.

$average=(88+88+88)/(3)=(264)/(3)=88$

The previous expression could be simplified as:

$average=(88* 3)/(3)$

Where, the number 3 means the number of students.

With that in mind, the phrase "Ten students had an average of 88" could be written as:

$average_(10\, \, students)=(88+88+88+88+88+88+88+88+88+88)/(10)$

$average_(10\, \, students)=(88* 10)/(10)=88$

On the other hand, the phrase "The other students had an average of 76" means that from the 25 students, 15 students got 76 (25 - 10 = 15), and could be written as:

$average_(15\, \, students)=(76+76+76+76+76+76+76+76+76+76+76+76+76+76+76)/(15)$

$average_(15\, \, students)=(76* 15)/(15)=76$

Finally, to calculate the total average of the 25 students we must divide the sum of the scores of all students by the total number of scores. The sum would be: 88+88+88+88+88+88+88+88+88+88+76+76+76+76+76+76+76+76+76+76+76+76+76+76+76, which equals $88* 10+76* 15$ . The total number of scores would be: 25.

$average_(total)=(88* 10 + 76* 15)/(25)$

$average_(total)=(880 + 1140)/(25)$

$average_(total)=(2020)/(25)$

$average_(total)=80.8$

Thus, the average of the whole class is 80.8. The correct answer is B)

The answer is B. 80.8

The length of a football field is 100 yard and the width is 53 yard. In the fist game of the season, Jos catches the opening kickoff at the corner of the goal line and runs straight as a string the diagonal length of the field to score s touchdown. The next day, the local paper credits Jos for a 100 yard touchdown run, but how far did he actually run

Answers

Given:
Length = 100 yards
Width = 53 yards
Rectangle shape

Jos ran the diagonal length. So, he formed a right triangle. The length Jos ran would be they hypotenuse.

a² + b² = c² ² where c = hypotenuse

100² + 53² = c²
10,000 + 2809 = c²
12809 = c²
c = √12809
c = 113.18 yards.

If 3a - 2 = 10, what is the value of 8a + 1?

Answers

Answer:

8a+1=33

Step-by-step explanation:

you can solve 3a-2=10 by simplifying to 3a=12, so a=4. Then you replace the a in 8a+1 with 4 to get 32+1, which is 33

Answer:

Step-by-step explanation:

3a-2= 10

3a=12

a=4

in this equation a=4 so you substitute that value into the other equation

8(4) +1=33

Veronica is buying cubed cheese from Mr. Sands deli she asked for 1 3/4 pounds when Mr. Sand places some cheese in a container and weighs it the scale shows 1 1/4 pounds the container weighs 1/16 pound how many more pounds of cheese would Mr. Sand need to add to the scale to get the amount that veronica asked for? Explain how you solved the problem

Answers

Amount of cubed cheese that Veronica wants to buy = 1 3/4 pounds
   = 7/8 pounds
Weight of the container in which Mr. Sand places the cube = 1/16 pounds
Weight of the cubed cheese and container together = 1 1/4 pounds
      = 5/4 pounds
Then
Amount of cubed cheese placed by Mr. Sands = (5/4 - 1/16) pounds
      = (20 - 1)/16 pounds
      = 19/16 pounds
So
The quantity of more cheese that
Mr.Sands need to add to the scale = (7/4 - 19/16) pounds
   = (28 - 19)/16 pounds
   = 9/16 pounds.
From the above deduction we can easily conclude that Mr. Sand needs to add 9/16 pounds of cubed cheese to fullfil the order placed by Veronica.

Answer: 9/16

Step-by-step explanation:

First, we must find the answer to the hidden question: How much cheese did Mr. Sand put in the container without the weight of the container? We can rename 1 1/4 to 1 4/16, so 1 4/16 - 1/16 = 1 3/16

Now we must find the amount of cheese that needs to be added. We can rename 1 3/4 to 1 12/16 by multiplying it by 4/4. 1 12/16 - 1 3/16 = 9/16

9/16 pound of cheese should be added to get the amount Veronica asked for.

Other Questions

A field in the shape of a square has an area of 8,100 square feet. How can you determine the length of one side of the field?

In a circle an arc length 10 is intercepted by a central angle of 2/3 radius

A 1/2 gallon of paint covers 1/6 of a wall. How much paint is needed to cover the entire wall? Could u show me how to do this question?

3c - 9d + 5d simplify this