MATHEMATICS MIDDLE SCHOOL

Which of the following expressions results in 0 when evaluated at x = 4?O A. (x - 10)(x - 4)
OB. (x + 4)(x - 10)
O C.
(x + 6)(x - 2)
OD. 4x(x-6)

Answers

Answer 1

Answer:

Answer:

A. (x - 10)(x - 4)

Step-by-step explanation:

Let x=4

O A. (4 - 10)(4 - 4) = -6 * 0 = 0

OB. (4 + 4)(4 - 10) = 8* -6 = -48

O C.(4 + 6)(4 - 2) = 10 * 2 = 20

OD. 4*4(4-6)=16*-2 = -32

Answer 2

Answer:

Answer:

A. (x - 10)(x - 4)

Step-by-step explanation:

The product is 0 if one of the factors is 0.

(4 - 10)(4 - 4)

= (4 - 10)*0

= 0

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Solve algebraically:
Y = x^2 + 5x - 17
Y = x - 5

Answers

Answer:

Step-by-step explanation:

What you could do is fill in 2 for the equation and y would equal -3 so for the first one it's like

y= 2^2 + 5(2) -17

y= 4 + 10 - 17 which turns into y= -3

In the second y it would be something like

y= 2 - 5 which would equal y= -3

so x=2

A moving helper company gave Mike these two quotes. Use a system of equations todetermine the hourly rates for loading/unloading and packing/unpacking.

4 hours of

loading/unloading

7 hours of

loading/unloading

Answers

The hourly rates of loading/unloading = $100

The hourly rates of packing/unpacking = $90

Step-by-step explanation:

Here, the given table is MISSING.

The correct table for reference is attached.

Now, let us assume the hourly rates of loading/unloading = $ m

Assume the hourly rates of packing/unpacking = $ n

As given in the table:

3 hours of loading/unloading + 2 hours of packing/unpacking costs = $480

⇒ 3 m + 2 n = 480

⇒ 2 n = 480 - 3 m .... (1)

5 hours of loading/unloading + 2 hours of packing/unpacking costs = $680

⇒ 5 m + 2 n = 680

⇒ 2 n = 680 - 5 m .... (2)

Now, solving for the values of m and n, we get:

480 - 3 m = 680 - 5 m

⇒ 5 m - 3 m = 680 - 480

⇒ 2 m = 200

or, m = 100

Now, 2 n = 680 - 5 m = 680 - 5 (100) = 180

⇒ n = 90

Hence, the hourly rates of loading/unloading = $ m = $100

The hourly rates of packing/unpacking = $ n = $90

What is the solution to 48 - 3x) > 6x-8?

Answers

Answer:

Step-by-step explanation:

(48-3x)>6x-8

48-3x>6x-8

Collecting like terms, we have

-3x-6x>-8-48

Moving variables or numbers from one side to the other changes the sign it carries

-9x>-56

Divining both sides by -9 changes the inequality sign

x<56/9

x<6.22

What is 6 1/2 - 1 9/10

Answers

Find common denominator which is 10 then find the equivalent fraction for 6 1/2 = 6 5/10.
Now you have 6 5/10 - 1 9/10, but since first numerator is less than the second numerator you need to borrow from the whole number. 6 5/10 = 5 10/10 + 5/10 = 5 15/10. Now just subtract the whole numbers and the numerators.
5 15/10 - 1 9/10 = 4 6/10 simplify to 4 3/5.

The value of the solution after subtraction is,

⇒ 4 3/5

We have to give that,

An expression to solve,

⇒ 6 1/2 - 1 9/10

Now, change the fraction into an improper fraction,

⇒ 6 1/2 - 1 9/10

⇒ 13/2 - 19/10

⇒ 65/10 - 19/10

⇒ (65 - 19) / 10

⇒ 46/10

⇒ 23/5

⇒ 4 3/5

Hence, the Solution of the fraction is. 4 3/5

To learn more about the fraction visit:

brainly.com/question/5454147

#SPJ6

Need help with math

Answers

Answer:

what do you need help with?

Step-by-step explanation:

Answer:

3x4x9x21=

Step-by-step explanation:

A line has a slope of -4/5. Which ordered pairs could be points on a line that is perpendicular to this line? Select two options.(–2, 0) and (2, 5)

(–4, 5) and (4, –5)

(–3, 4) and (2, 0)

(1, –1) and (6, –5)

(2, –1) and (10, 9)

Answers

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{-\cfrac{4}{5}}\qquad \qquad \qquad \stackrel{reciprocal}{-\cfrac{5}{4}}\qquad \stackrel{negative~reciprocal}{+\cfrac{5}{4}\implies \cfrac{5}{4}}} \n\n[-0.35em] ~\dotfill$

$\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{5}) \n\n\n slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{5-0}{2-(-2)}\implies \cfrac{5}{2+2}\implies \cfrac{5}{4} \n\n[-0.35em] ~\dotfill$

$\bf (\stackrel{x_1}{2}~,~\stackrel{y_1}{-1})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{9}) \n\n\n slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{9-(-1)}{10-2}\implies \cfrac{9+1}{8}\implies \cfrac{10}{8}\implies \cfrac{5}{4}$