Hi Beck
The answer should be
Diffraction of light passing through a narrow opening
I hope that's help :)
Answer: h =1.22 m
Explanation:
from the question we were given the following
mass of performer ( M1 ) = 77 kg
length of cable ( R ) = 3.65 m
mass of costar ( M2 ) = 55 kg
maximum height (h) = ?
acceleration due to gravity (g) = 9.8 m/s^2 (constant value)
We first have to find the velocity of the performer. From the work energy theorem work done = change in kinetic energy
work done = 1/2 x mass x ( (final velocity)^2 - (initial velocity)^2 )
initial velocity is zero in this case because the performer was at rest before swinging, therefore
work done = 1/2 x 77 x ( v^2 - 0)
work done = 38.5 x ( v^2 ) ......equation 1
work done is also equal to m x g x distance ( the distance in this case is the length of the rope), hence equating the two equations we have
m x g x R = 38.5 x ( v^2 )
77 x 9.8 x 3.65 = 38.5 x ( v^2 )
2754.29 = 38.5 x ( v^2 )
( v^2 ) = 71.54
v = 8.4 m/s ( velocity of the performer)
After swinging, the performer picks up his costar and they move together, therefore we can apply the conservation of momentum formula which is
initial momentum of performer (P1) + initial momentum of costar (P2) = final momentum of costar and performer after pick up (Pf)
momentum = mass x velocity thereforethe equation above now becomes
(77 x 8.4) + (55 x 0) = (77 +55) x Vf
take note the the initial velocity of the costar is 0 before pick up because he is at rest
651.3 = 132 x Vf
Vf = 4.9 m/s
the performer and his costar is 4.9 m/s after pickup
to finally get their height we can use the energy conservation equation for from after pickup to their maximum height. Take note that their velocity at maximum height is 0
initial Kinetic energy + Initial potential energy = Final potential energy + Final Kinetic energy
where
kinetic energy = 1/2 x m x v^2
potential energy = m x g x h
after pickup they both will have kinetic energy and no potential energy, while at maximum height they will have potential energy and no kinetic energy. Therefore the equation now becomes
initial kinetic energy = final potential energy
(1/2 x (55 + 77) x 4.9^2) + 0 = ( (55 + 77) x 9.8 x h) + 0
1584.7 = 1293 x h
h =1.22 m
Answer:Damge buildings that fall down after a earthquake also After shock
Answer:
At focus.
Explanation:
When the object is placed at the focus of a concave mirror, the image will form at infinity. The formed image is real and inverted and its size is highly enlarged.
When the object is placed between the pole and the focus, the image will formed behind the mirror. The formed image is virtual and erect and its size is enlarged. This is the only case when the formed image is virtual and erect.