A poorly constructed room is suffering from a pipe leakage problem. The leaked pipes are continuously flooding the 90-m2 room such that the water level in the room increases at a steady rate of 1.2 cm/hr (a) How much water in L/min should be pumped out of the room to keep the water level cnstat (b) How much water in L/min should be pumped out of the room to reduce the water level by 4 cm/hr?

Answers

Answer 1
Answer:

Answer:

(a): should be pumped out of the room 18 L/min to keep the water level constant.

(b): should be pumped out of the room 78 L/min to reduce the water level by 4 cm/hr.

Explanation:

S= 90 m²

rate= 1.2 cm/hr = 0.012 m/hr = 0.0002 m/min

Water leak= S*rate= 90 m² * 0.0002 m/min

Water leak= 0.018 m³/min * 1000 L/m³

Water leak= 18 L/min   (a) Water should be pumped out to keep the level constant.

By the rule of 3:

1.2 cm/hr ------------- 18 L/min

(4+1.2) cm/hr --------  x= 78 L/min  (b) Water should be pumped out to reduce the level by 4 cm/hr.


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Answers

Answer:

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Explanation:

On December 26, 2004, a great earthquake occurred off the coast of Sumatra and triggered immense waves (tsunami) that killed some 200000 people. Satellites observing these waves from space measured 800 from one wave crest to the next and a period between waves of 1.0 hour.Part AWhat was the speed of these waves in m/s?Express your answer using two significant figures.=Part BWhat was the speed of these waves in km/h ?Express your answer using two significant figures.=

Answers

Answers:

a) 222.22 m/s

b) 800.00 km/h

Explanation:

The speed of a wave is given by the following equation:

v=f \lambda

Where:

v is the speed

f=(1)/(T) is the frequency, which has an inverse relation with the period T=1 h

\lambda=800 km is the wavelength

Solving with the given units:

v=(1)/(T)\lambda

v=(1)/(1 h)800 km

v=800.00 km/hThis is the speed of the wave in km/h

Transforming this speed to m/s:

v=800.00 (km)/(h) (1 h)/(3600 s) (1000 m)/(1 km)

v=222.22 m/sThis is the speed of the wave in m/s

In a physics laboratory experiment, a coil with 170 turns enclosing an area of 10.9 cm2 is rotated during the time interval 3.50×10−2 s from a position in which its plane is perpendicular to Earth's magnetic field to one in which its plane is parallel to the field. The magnitude of Earth's magnetic field at the lab location is 5.60×10−5 T. What is the total magnitude of the magnetic flux (initial) through the coil before it is rotated?

Answers

N= 170 turns\nA=10.9cm^2\nt=3.5*10^(-2)s \n\B = 5.6*10^(-5)T

The Magnetic flow \Phi_(initial) is given by the formula,

\Phi_(Initial)=BAsin\theta

Replacing the values

\Phi_(Initial) =(5.6*10^(-5))(10.9)((10^(-4)m^2)/(1cm^2)) sin90\°

\Phi_(Initial) =6.104*10^(-7) Wb

One end of a horizontal spring with force constant 130.0 Ni'm is attached to a vertical wall. A 4.00-kg block sitting on the floor is placed against the spring. The coefficient of kinetic friction between the block and the floor is uk = 0.400. You apply a constant force F to the block. F has magnitude F = 82.0 N and is directed toward the wall. At the instant that the spring is com-pressed 80.0 cm, what arc (a) the speed of the block, and (b) the magnitude and direction of the block's acceleration?

Answers

Answer:

Explanation:

When the spring is compressed by .80 m , restoring force by spring on block

= 130 x .80

= 104 N , acting away from wall

External force = 82 N , acting towards wall

Force of friction acting towards wall = μmg

= .4 x 4 x 9.8

= 15.68 N

Net force away from wall

= 104 -15.68 - 82

= 6.32 N

Acceleration

= 6.32 / 4

= 1.58 m / s²

It will be away from wall

Energy released by compressed spring = 1/2 k x²

= .5 x 130 x .8²

= 41.6 J

Energy lost in friction

= μmg x  .8

= .4 x 4 x 9.8 x .8

= 12.544 J

Energy available to block

= 41.6 - 12.544 J

= 29 J

Kinetic energy of block = 29

1/2 x 4 x v² = 29

v = 3.8 m / s

This will b speed of block as soon as spring relaxes. (x = 0 )

A Lincoln Continental is twice as long as a VW Beetle, when they are at rest. On a 2-lane road, the Continental driver passes the VW Beetle. Unfortunately for the Continental driver, a stationary policeman has set up a speed trap, and the policeman observes that the Continental and the Beetle have the same length. The VW is going at half the speed of light. How fast is the Lincoln going ? (Express your answer as a multiple of c).

Answers

Answer:

V(t) = √13/4c

Explanation:

See attachment

Find the speed of light in carbon tetrachlorideethyl alcohol. The refraction index is 1.461 using 3 x 10^8 m/s as the speed of light in vacuum. Answer in units of m/s.

Answers

Answer:

2.05 x 10^8 m /s

Explanation:

c = 3 x 10^8 m/s

μ = c / v

where, μ is the refractive index, c be the velocity of light in air and v be the velocity of light in the medium.

μ = 1.461

1.461 = 3 x 10^8 / v

v = 3 x 10^8 / 1.461

v = 2.05 x 10^8 m /s