Which of the following is an acceptable structure for 2,5,5-trimethylhept-3-yne (CH3CH2)CH(CH3)C≡CCH2CH(CH3)2 CH3CH2C(CH3)2C≡CC(CH3)3 (CH3CH2)2C(CH3)C≡CCH2CH3 (CH3CH2)C(CH3)2C≡CCH(CH3)2 (CH3CH2CH2)CH(CH3)C≡CC(CH3)3

Answers

Answer 1
Answer:

Answer:

D. CH₃CH₂C(CH₃)₂C≡CCH(CH₃)₂  

Explanation:

You start numbering from the end closest to the triple bond (on the right). The triple bond is between C3 and C4, and there is one methyl group on C3 and two on C5.

A. CH₃CH₂CH(CH₃)C≡CCH₂CH(CH₃)₂ is wrong. The longest chain has eight C atoms, so the compound is an octyne.

B. CH₃CH₂CH(CH₃)C≡CC(CH₃)₃ is wrong. This is a molecule of 2,2,5-trimethylhept-3-yne.

C. (CH₃CH₂)₂C≡CCH₂CH₃ is wrong. This is a molecule of 6-ethyl-5-methylhept-3-yne.

E. CH₃CH₂CH₂CH(CH₃)C≡CC(CH₃)₃ is wrong. The longest chain has eight C atoms, so the compound is an octyne.


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Using the following equation how many grams of water you would get from 886 g of glucose:C6H12O6 + 6O2 → 6CO2 + 6H2O + energy
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Which compound is classified as an electrolyte? a) C6H12O6
b)Ca(OH)2
c)C12H22O11
d)CH3OH

Answers

Answer:
            Option-B, Ca(OH)₂ is the correct answer.

Explanation:
                   By definition Electrolytes are those compounds which when poured in polar solvents dissociate into a positively charged specie called Cation and a negatively charged specie called an Anion. These ions have the potential to conduct electricity. 
                   So Ca(OH)₂ is dissolved in water it produces Ca⁺² cation and OH⁻ anions. So it acts as an Electrolyte.
                    While, C₆H₁₂O₆ (Glucose), C₁₂H₂₂O₁₁ (Table Sugar) and CH₃OH (Methanol) are covalent compounds and does not produce any positive or negative ions when dissolved in water.

Select all the true statements. Group of answer choices The +3 oxidation state is characteristic of the actinides. All actinides are radioactive. Cerium (Ce) rnakes 100th in abundance (by mass %). Valence-state electronegativity is when a metal with a positive oxidation state has a greater attraction for the bonded electrons (thus a higher electronegativity) than it does when it has a 0 oxidation state. The actinides are silvery and chemically reactive. The lanthanides are in Period 7.

Answers

In the periodic table,the The +3 oxidation state is characteristic of the actinides. All actinides are radioactive.The actinides are silvery and chemically reactive.

What is periodic table?

Periodic table is a tabular arrangement of elements in the form of a table. In the periodic table, elements are arranged according to the modern periodic law which states that the properties of elements are a periodic function of their atomic numbers.

It is called as periodic because properties repeat after regular intervals of atomic numbers . It is a tabular arrangement consisting of seven horizontal rows called periods and eighteen vertical columns called groups.

Elements present in the same group have same number of valence electrons and hence have similar properties while elements present in the same period show gradual variation in properties due to addition of one electron for each successive element in a period.

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Answer:

The +3 oxidation state is characteristic of the actinides.

All actinides are radioactive.

Cerium (Ce) rnakes 100th in abundance (by mass %).

The actinides are silvery and chemically reactive.

Refer to the following balance equation : 2c2h6 + 7o2 = 4co2 + 6 h20. How many moles of c2h6 will combust completely with 2.0 moles of oxygen gas. How many grams of water will be produced when 30.0 g of c2h6 reacts completely with oxygen?

Answers

1. From the balanced equation given above, the ratio of the number of moles of the hydrocarbon and oxygen is equal to 2/7. Given that there are 2 moles of oxygen,

    moles hydrocarbon = (2 moles O2)(2 moles HC / 7 moles oxygen)

Simplifying,
   moles HC = 4/7 or 0.57 moles HC

Answer: 0.57 moles HC

2. The calculation for the mass of water is shown below with the dimensional analysis and conversion factors,

  (30 g C2H6)1 mole C2H6/30 g C2H6)(6 molesH2O/2 moles C2H6)(18 g H2O/1 mole C2H6)


Simplifying,
     mass  = 54 grams of water

Question 16 Unsaved Which of the following diagrams represents the correct cycling of gases?A) Photosynthesis O2 Respiration CO2
B) Respiration O2 photosynthesis CO2
C) Photosynthesis H2 Respiration O2
D) Respiration CO2 photosynthesis H2

Answers

the answer is A:

Photosynthesis release O2 (oxygen)

then animals use oxygen for respiration and release Co2

Final answer:

The correct answer is A) Photosynthesis O2 Respiration CO2. Photosynthesis converts CO2 to O2, which is then used in respiration to be converted back into CO2. Both processes together create a continuous cycle.

Explanation:

The correct diagram that represents the cycling of gases between photosynthesis and respiration is A) Photosynthesis O2 Respiration CO2. Through the process of photosynthesis, plants convert carbon dioxide (CO2) and sunlight into oxygen (O2) and glucose. Organisms, including the plants themselves, then use that oxygen for respiration, during which they convert the oxygen back into carbon dioxide. The glucose is used for energy. This continuous cycling plays a critical role in life on Earth.

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Consider the titration of 25.0 mL of 0.340 M HCl with 0.160 M NaOH. What volume of NaOH is required to reach the equivalence point?

Answers

Answer:

53.1 mL NaOH

Explanation:

Calculate the mass of the air contained in a room that measures 2.50 m × 5.50 m × 3.00 m (density of air = 1.29 g/dm3 at 25°C).

Answers

The mass of air in room as per given density is 53.2 kg.

To calculate the mass of air contained in a room, we can use the formula:

mass = density x volume

Here, the given density of air is 1.29 g/dm³ at 25°C. We can convert the dimensions of the room to decimeters (dm) by multiplying by 10:

Length = 2.50 m × 10 = 25 dm

Width = 5.50 m × 10 = 55 dm

Height = 3.00 m × 10 = 30 dm

Now, we can calculate the volume of the room by multiplying the three dimensions:

Volume = length x width x height

Volume = 25 dm x 55 dm x 30 dm

Volume = 41,250 dm³

Finally, we can use the formula to calculate the mass of air:

mass = density x volume

mass = 1.29 g/dm³ x 41,250 dm³

mass = 53,212.5 g or 53.2 kg

Therefore, the mass of air contained in the room is approximately 53.2 kg.

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Explanation:

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