Answer:
a)
b)
Explanation:
Given:
The distance between two speakers (d) = 0.932 m
The distance of the microphone from the midpoint = 2.83 m
Thus, distance of microphone from the nearest speaker (L) = 2.83 - (0.932/2) = 2.364 m
also, the distance of the microphone from the farther speaker (L') = 2.83 + (0.932/2) = 3.296 m
Now,
The path difference is calculated as
L' - L = d = 0.932 m
Now,for a maxima to be produced at the microphone, the waves must constructively interfere.
for this to happen the path difference should be integral multiple of the wavelength.
thus,
hence, the largest wavelength will be for n = 1,
therefore,
0.932 = 1 × λ
or
λ = 0.932 m
now, the velocity of sound is given as c = 343 m/s
thus, the frequency will be
on substituting the values, we get
now, the 2nd largest wavelength will be for n = 2
0.932 = 2 × λ
or
λ = 0.466
thus, the frequency will be
hence, these are the lowest first two frequencies.
A. 2000 J
B. 75,000 J
C. 120,000 J
D. 300,000 J
The electrical energy used by a 400 W toaster that is operating for 5 minutes will be 120,000 J.Option C is correct.
The rate of the work done is called the power output. It is denoted by P.Its unit of a watt. It is the ratio of the work done or the enrgy to the time period.
The given data in the problem is;
E is the electrical energy
P is the power output = 400 W
t is the time period = 5 minutes
The power output is given as;
Hence the electrical energy used by a 400 W toaster that is operating for 5 minutes will be 120,000 J.Option C is correct.
To learn more about the power output refer to the link;
Answer:
The answer is C. 120,000 J.
Explanation:
Answer: 1.11 x 10⁸ Pa
Explanation:
At any deep, the absolute pressure is the same for all points located at the same level, and can be expressed as follows:
p = p₀ + δ. g . h, where p₀ = atmospheric pressure = 101, 325 Pa
Replacing by the values, we get:
p= 101,325 Pa + 1025 Kg/m³ . 9.8 m/s². 11,033 m = 1.11 x 10⁸ Pa.
Answer:
f = 113 Hz
Explanation:
In order to have maximum power transferred from the driving source, as the RMS voltage doesn´t depends on frequency, the current I must be maximum.
This condition is met when the circuit behaves a purely resistive, as the impedance is at a minimum.
Such condition is known as resonance, and it satisfies the following equation:
XL = XC ⇒ ω₀ * L = 1 / ω₀*C, where ω₀, is the angular frequency at resonance.
Solving for ω₀, we have:
ω₀ = 1/√LC = 1/√200*10⁻3 H* 10⁻6F = 707 rad/sec
As we need to find the frequency (in cycles/sec), we need to convert from angular frequency to frequency, as follows:
ω₀ = 2*π*f₀ ⇒ f₀ = ω₀ / 2*π = 707 rad/sec / 2*π rad = 113 Hz
study how seismic waves travel through different layers
drill deep mines to obtain samples from Earth's mantle and core
conduct experiments about how minerals change under high pressure
use X-rays to obtain a view of Earth's interior layers
Scientists can determine the characteristics of Earth's layers by studying seismic waves and drilling deep mines to obtain samples from the mantle and core.
The two correct techniques that scientists can use to determine the characteristics of Earth's layers are studying how seismic waves travel through different layers and drilling deep mines to obtain samples from Earth's mantle and core. By studying seismic waves, scientists can analyze their behavior and characteristics as they pass through different layers of the Earth, providing valuable information about their composition and structure. Additionally, drilling deep mines allows scientists to directly access and analyze samples from the Earth's deeper layers, providing insights into the composition and properties of the mantle and core.
#SPJ3
Answer:
C
Explanation:
Answer is C.
Answer:
Point motion will eventually stops due to action of g exactly perpendicular...
Explanation:
If ignoring the air resistance, the magnitude of gravitational acceleration is already strong enough to stops the acceleration. As we know that, the spring constant of a bungee spring cord will be F = -k/x, where x is the stretched length and k is the spring constant of bungee cord. If F = ma = w = mg, the g = -m k/x. Now we can clearly see that the value of g remains constant due to the fluctuating length of the cord as the motion progresses back and forth in SHM say from x1 to x2 and x2 to x1.