Charge Q = +4.00 mC is distributed uniformly over the volume of an insulating sphere that has radius R = 5.00 cm. What is the potential difference between the center of the sphere and the surface of the sphere?
Answers
The potential difference between the center of the sphere and the surface of the sphere will be PD=3.6 x 10^8 V
What will be the potential difference?
It is given that:-
Charge Q = +4.00 mC or
insulating sphereradius R = 5.00 cm = 0.05 m
The formula for the potentialdifference at the surface of the sphere is given by
The formula for the potentialdifference at the center of the sphere
The difference between the potential difference will be
Thus the potential difference between the center of the sphere and the surface of the sphere will be PD=3.6 x 10^8 V
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Answer:
3.6 x 10^8 V
Explanation:
Q = 4 m C = 4 x 10^-3 C
r = 5 cm = 0.05 m
The formula for the potential at the surface is
Vs = K Q / r = (9 x 10^9 x 4 x 10^-3) / 0.05 = 7.2 x 10^8 V
The formula for the potential at the centre is
Vc = 3/2 Vs
Vc = 1.5 x 7.2 x 10^8 V = 10.8 x 10^8 V
The difference in potential is
V = Vc - Vs = 10.8 x 10^8 - 7.2 x 10^8 = 3.6 x 10^8 V
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Explanation:
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