Mike has some money in his account. Every month, he uses the same amount of money from his account to pay for his aerobics classes. The table below shows the amount of money left in his account after a certain amount of time, in months:What is the value of the rate of change of the function for this table and what does it represent in this situation?
$50 per month; the initial amount of money in the account
−$50 per month; the amount of money withdrawn per month
−$280 per month; the amount of money withdrawn per month
$280 per month; the initial amount of money in the account

Answers

Answer 1

Answer: The correct answer is -$50 per month; the amount of money withdrawn per month. From one month to the next, Mike loses 50 dollars from his bank account, presumably because he's withdrawing it. To find this, just subtract each number from the number below it.

230 - 280 = -50
180 - 230 = -50
130 - 180 = -50

Therefore, the rate of change is -50, because Mike loses $50 each month. This means that he withdraws $50 from his bank account each month.

Hope this helps!

Answer 2

Answer:

Answer:

−$50 per month; the amount of money withdrawn per month

Step-by-step explanation:

I know ^^ that is correct because I just did the test!

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in a standard deck of t2 playing cards, there are 4 aces, 4 kings, 4 queens, and 4 Jacks. All other cards have number values. the kings, queens, and Jack's are called face cards. You are dealt 2 cards in a sequence. calculate the probability of being dealt a 3 and then a 10. write your answer as a decimal to the nearest hundredth

Answers

Answer:

0.01

Step-by-step explanation:

Assuming the deck is the national playing deck with 52 cards.

Your probability of getting a 3 from the entire deck is 4/52. This number is the same for 10.

To get the probability of pulling a 3 and a 10 afterwards, you must multiply these two fractions (you're expecting a lower percentage).

$4/52 * 4/52 = 0.0059$

52% of ______
days is 13 days.

Answers

25.

To find the answer, divide 13 by .52

So, 13/.52 = 25. Good luck!

In 2009, the life expectancy is about 80 years. Assume that, due to modern advances, life expectancy gains 5.5 years every decade. From 2009, in how many years would humanity achieve a life expectancy of 110 years?

Answers

Answer:

60 years

Step-by-step explanation:

2009 -> 80 years

+5.5

2019 -> 85.5 years

+5.5

2029 -> 91 years

+5.5

2039 -> 96.5 years

+5.5

2049 -> 102 years

+5.5

2059 -> 107.5 years

+5.5

2069 -> 113 years

Which postulate states if B is between A and C then AB+BC=AC?

Answers

The segment addition postulate states that if B is between A and C then AB+BC=AC.

Dwayne is selling hamburgers and cheeseburgers. He has 100 burger buns. Each hamburger sells for $3, and each cheeseburger sells for $3.50. Which system of inequalities represents the number of hamburgers, h, and the number of cheeseburgers, c, he must sell to have sales of at least $80? h + c ≤ 80 3h + 3.5c ≤ 100 h + c ≤ 80 3h + 3.5c ≥ 100 h + c ≤ 100 3h + 3.5c ≤ 80 h + c ≤ 100 3h + 3.5c ≥ 80

Answers

Given:
hamburger = h ; sells for 3
cheeseburger = c ; sells for 3.50
100 burger buns

h + c = 100

3h + 3.5c > 80 last option.

Answer:

Its D

Step-by-step explanation:

Find the mean, median, and interquartile for the data set below. Round your answer to the nearest tenth. 27,16,8,5,19,14,22,31,13,5,23,16,8

Answers

Answer:

Hence,

Mean=15.9

Median=16

Interquartile=14.5

Step-by-step explanation:

On arranging our data in the increasing order we get the data set as:

5 5 8 8 13 14 16 16 19 22 23 27 31

Now we find the mean as:

$Mean=(5+5+8+8+13+14+16+16+19+22+23+27+31)/(13)\n\nMean=(207)/(13)\n\nMean=15.92$

Now, we know that the median is the central tendency of the data and lie in the middle of the data.

Hence, by looking at the data we see that the middle value of the data is 16.

Hence, Median=16.

Now, the lower set of data is:

5 5 8 8 13 14

Now, the lower quartile is calculated as:

The middle value of the lower set of data is:

8 8

Hence, the lower quartile $]Q_1$ is middle of 8,8.

i.e. $(8+8)/(2)=8$

similarly the upper set of data is:

16 19 22 23 27 31.

Similarly the upper quartile is calculated as:

$Q_3=(22+23)/(2)=22.5$

Hence, interquartile range (IQR) is calculated as:

$Q_3-Q_1=22.5-8=14.5$

Hence,

Mean=15.9

Median=16

Interquartile=14.5

The mean is 15.92, the median is 16, and the interquartile range is 14.5