PHYSICS HIGH SCHOOL

Several teenagers swim toward a rectangular, wooden raft that is 2.00 m wide and 2.50 m long. If the raft is 9.80 cm thick, how many 75.0 kg teenage boys can stand on top of the raft without the raft becoming submerged? Assume the wood density is 650 kg/m3.

Answers

Answer 1

Answer:

Answer:

Explanation:

length of the raft, L = 2 m

Width of the raft, W = 2.5 m

height of the raft, H = 9.8 cm = 0.098 m

mass of each person, m = 75 kg

Density of wood = 650 kg/m^3

volume of raft, V = L x W x H = 2 x 2.5 x 0.098 = 0.49 m^3

let there are N persons

According to the principle of floatation

Buoyant force acting on the raft = True weight of the raft

Volume x density of water x g = volume x density of wood x g + N x mg

0.49 x 1000 x g = 0.49 x 650 x g + N x 75 x g

490 = 318.5 + N x 75

N = 2.28

So, the maximum number of person is 2.

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What is the biggest planet in our galaxy

Answers

We won't be able to answer that until we've seen all of them and
we know that there aren't any more that we haven't seen yet.

There are estimated to be between 200 billion and 400 billion stars
in our galaxy, and a large part of the stars in the galaxy aren't visible
to us. So you can see that it's going to take some time before we're
able to answer your question. Check back with us next Tuesday.

A small car and a large truck are driving down a highway, which statement would support the premise that the truck has more momentum? A)
A large truck has a much larger mass.

B)
A car has a smaller engine than a truck.

C)
A small car accelerate faster than a truck.

D)
A large truck can travel at close to the speed of the car

Answers

Answer:

A large truck has a much larger mass.

Explanation:

Since we know that momentum is defined as the product of mass and velocity

so here we can say

$P = mv$

so here more momentum will say that the product of mass and velocity will be more

so here as we compare the car and truck we can say that truck will have more momentum because the mass of the truck will always be greater than the mass of car

due to this huge difference in the mass of car and truck we can say that truck will always have more momentum than car.

im pretty sure its A i may be wrong

A car climbs 10.0 kilometers up a hill that inclines 8.0 degrees. What is the car's vertical displacement?

Answers

$s=10km\n\alpha=8^o\n\ny=?\n\\sin\alpha=(y)/(s)\Rightarrow y=s\sin\alpha\n\ny=10\sin8^o\n\ny=10\cdot 0,1392\n\n\y=1,392km$

A clever engineer designs a "sprong" that obeys the force law fx =−q(x−xe)3, where xe is the equilibrium position of the end of the sprong and q is the sprong constant. for simplicity, we'll let xe =0m. then fx =−qx3.

Answers

The unit of q is N/m³.While the potential energy of the compressed spring will be $\rm U(x)= -(qx^4)/(4)$ .

What is the potential energy of spring?

When a springdeviates from its mean position, it attempts to regain equilibrium by applying a force that is equivalent to but opposite to the external force.

Spring force has been used in bicycle carriers and launchingmechanisms, where the energy generated by disrupting the spring'sbalance is used as potential energy.

The given equation for the force law is;

$\rm f_x =-q(x-x_e)$

Where,

$\rm x_e$ is equilibrium position of the end of the spring

q is a spring constant

If at equilibriumposition;

$\rm x_e=0$

$\rm F_X= -qx^3 \n\n \rm q = (F_x)/(x^3) \n\n$

So the unit derived will be;

q = N/m³

The potential energy of the spring is found by;

$\rm F_x=- (du)/(dx) \n\n U(x)= -\int\limits^x_0 {F(x)} \, dx \n\n U(x)= -\int\limits^x_0 -qx^3 \, dx \n\n U(x)=- (qx^4)/(4)$

Hence the unit of q is N/m³.While the potentialenergy of the compressed spring will be $\rm U(x)= -(qx^4)/(4)$ .

To learn more about the potential energy of spring refer to the link;

brainly.com/question/2730954

The objective of this question is to compute the units of q and calculate the expression for the P.E of the compressed spring

Answer:

q = N/m³

$\mathbf{U(x) = -(qx^4)/(4)}$

Explanation:

Given that:

The equation for the force law is:

$F_x = -q (x -x_e)^3$

where;

$x_e$ e = equilibrium position of the end of the spring

i.e. $x_e$ = 0

q = is the spring constant

Also;

$F_x = -qx^3$

From above the units of q can be calculated by making q the subject of the formula :

$q = (F_x)/(x^3)$

where x is in meters and F is in Netwon;

Then :

q = N/m³

The Potential energy P.E of the compressed spring can be calculated by using the integral:

$F_x = -(dU)/(dx)$

$U(x) = - \int F_x dx$

$U(x) = - \int ^x_0 (-qx^3) \ dx$

$\mathbf{U(x) = -(qx^4)/(4)}$

Big bang theorists believe that the universe is expanding and will eventually contract.a. True
b. False

Answers

The statement ‘Big bang theorists believe that the universe is expanding and will eventually contract’ is false. The answer is letter B. The big bang theory suggests that the origin of the universe began with that exploded and expanded. It also states that the universe began in a single form of high condensed reactive matter and exploded forming the galaxies, planets, stars and other celestial bodies.

Answer:

FALSE

Explanation:

A boy throws a football horizontally from a window that is 2.8 m above the ground. If he throws the ball with a speed of 12 m/s, how far from the window does the ball land? A. 11.2 m B. 0.23 m C. 9.1 m D. 4.3 m

Answers

We need to know your component of velocity to find time taken by the ball to reach ground. So the correct answer is C. 9.1m. I forgot to approximate.

Answer:C. 9.1m

Explanation:

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