6.5 was added to a certain number. This sum was then divided by 13.6. Finally, the quotient was multiplied by 5. This product came out to 5. What was the number

Answers

Answer 1

Answer:

Answer:

7.1

Step-by-step explanation:

Here's how we have to set this up. We will start with the first statement, which algebraically looks like this:

x + 6.5 = y (since we don't know what x is, we don't know what the sum of x and 6.5 is. We will call that new number y.)

Next, we are dividing that sum, y, by 13.6:

$(y)/(13.6)=z$ (again, since we don't know what y is, we don't know what y divided by 13.6 is. We will call that new number z.)

Finally, the quotient, z, is multiplied by 5:

Now we work backwards, subbing in our unknowns, one at a time.

If z = $(y)/(13.6)$ , we sub it into the expression 5z:

$5((y)/(13.6))$ and

if y = x + 6.5 we plug that in for y:

$5((x+6.5)/(13.6))=5$ since we know that whole mess is equal to 5. NOw we solve for x, the original number. Begin by dividing both sides by 5 to get:

$(x+6.5)/(13.6)=1$

Now multiply both sides by 13.6 to get:

x + 6.5 = 13.6 so

x = 7.1

Check this if you'd like by plugging in the 7.1 for x in the intial equation to solve for y, then plug that into the next equation to solve for z, then see if they're equal (they are, but test it out for yourself).

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Which ordered pair is a solution to the system of inequalities?

Answers

Answer:

Option A

Step-by-step explanation:

System of the inequalities is,

y ≥ 2x

y < x + 4

By satisfying these inequalities with the points given in the options we can get the answer.

Option (A). (2, 5)

y ≥ 2x

5 ≥ 2(2)

5 ≥ 4

True.

y < x + 4

5 < 2 + 4

5 < 6

True

Therefore, Option (1) is the answer.

Option (B) (1, 6)

y ≥ 2x

6 ≥ 2(1)

6 ≥ 2

True.

y < x + 4

6 < 1 + 4

6 < 5

False.

Therefore, it's not the solution.

Option (C) (2, 3)

y ≥ 2x

3 ≥ 2(2)

3 ≥ 4

False.

y < x + 4

4 < 2 + 4

4 < 6

True.

Therefore, It's not the solution.

Option (D) (1, 5)

y ≥ 2x

5 ≥ 2(1)

5 ≥ 4

True.

y < x + 4

5 < 1 + 4

5 < 5

False.

Therefore, It's not the solution.

The cost is $2.66 and the percent of the markup is 50%. What is the selling price?

Answers

I googled how to do markup 50%... and it took me awhile but I think I got the answer, $2.66 + $1.33 (into $1.33 from 2.66 x0.5) and u get $3.99Sorry If I'm wrong but I hoped I helped!

In a sample of 50 households, the mean number of hours spent on social networking sites during the month of January was 45 hours. In a much larger study, the standard deviation was determined to be 8 hours. Assume the population standard deviation is the same. Which of the statement below best describes that there is a 95% confidence interval for the mean hours devoted to social networking in January? A. The 95% confidence interval ranges from 8 to 45 hours. B. The 95% confidence interval ranges from 40.13 to 45.78 hours. C. The 95% confidence interval ranges from 43.87 to 46.13 hours. D. The 95% confidence interval ranges from 42.78 to 47.22 hours.

Answers

Answer:

D. The 95% confidence interval ranges from 42.78 to 47.22 hours.

Step-by-step explanation:

Here,

n = sample size = 50,

μ = mean = 45,

σ = standard deviation = 8,

We know that, confidence interval will be,

$=\mu\ \pm\ z(\sigma )/(√(n))$

For a confidence interval of 95%, we use z = 1.96, putting the values

$=45\ \pm\ 1.96(8)/(√(50))$

$=42.78,47.22$

D. The 95% confidence interval ranges from 42.78 to 47.22 hours.

To solve the interval, we used the upper and lower limit formulas wherein:
xbar = 45
z = 1.96
s = 8
n = 50

Numbers 20 - 22 please

Answers

$(x+5)(x+2)=x^2+2x+5x+10=x^2+7x+10\n\n (x-1)(2x^2-4x+10)=2x^3-4x^2+10x-2x^2+4x-10=\n =2x^3-6x^2+14x-10\n\n (c^2-10)(4c+3)=4x^3+3c^2-40c-30$

The sum of the first and third of three consecutive even integers is 154. Find the three even integers.

Answers

x + (x+2) = 154
combine like terms
2x + 2 = 154
subtract 2
2x = 154
divide by 2
x = 76

so the two numbers are 76 and 78

Find the simplified form of (t^4/10y^4)^-4

Answers

The answer is [(10,000*y^16)/t^16]. At first, you have to distribute the exponent -4 to the numerator and denominator by virtue of the law of exponent, (a/b)^n = [(a^n)/(b^n)]. After distribution, you get (t^-16)/[(10^-4)*(y^-16)]. To simplify the negative exponent, follow the law of exponent: a^-m = 1/a^m. Thus, you now have [(10^4)*(y^16)]/(t^16). Hence, the answer is [(10,000*y^16)/t^16].

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