MATHEMATICS HIGH SCHOOL

The long division below shows the first term of the quotient. Which polynomial should be subtracted from the dividend first?x^2
-----------------------------------
x + 2 ) x^3 + 3x^2 + x


A. x + 3
B. x^2 + x + 2
C. x^3 + 2x^2
D. x2 + 3x

Answers

Answer 1
Answer:

Answer:

Option C. x³ + 2x²

Step-by-step explanation:

In this long division x + 2 ) x³ + 3x² + x

when we divide the polynomial by (x + 2) then first quotient will be x². By the multiplication of (x + 2) and x² we get a polynomial which will be subtracted from the dividend.

(x + 2)×(x²) = x³ + 2x²

This is the polynomial to be subtracted.

Therefore option C is the correct answer.
Answer 2
Answer: Option C: x^3 + 2x^2

This is the result of the multiplication of the first term of the quotient (x^2) times the divisor (x + 2).

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What number must be added to the expression below to complete the square? x2 - 18x A. -81 B. -9 C. 81 D. 9
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Answers

im pretty sure it's y= 1.2x +6

The measure of an exterior angle at the vertex of a polygon equals the measure of the adjacent interior angle.Always, sometimes, or never

Answers

Answer:

Polygon: A polygon is a simple closed curve entirely made up of line segments.

1. As starting from triangle

Three kind of triangles: Isosceles, Scalene , and equilateral triangle

In none of these  measure of an exterior angle at the vertex of the triangle equals the measure of the adjacent interior angle.

2. Quadrilateral = Parallelogram, Rhombus, Rectangle, Square, Kite, Trpzm

Apart from Rectangle and Square none other quadrilateral have The measure of an exterior angle at the vertex of the quadrilateral equals the measure of the adjacent interior angle.

we can also consider other polygons also like pentagon,hexagon,heptagon.

Decagon and found that it is not always possible that measure of an exterior angle at the vertex of a polygon equals the measure of the adjacent interior angle.

So, the correct option is Sometimes.
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A sporting goods store sells triangular team pennants in two sizes. The base of one pennant is 18 in. and the length of the side is 9 in. The other pennant is similar to the larger pennant and has a base that is 6 in.What is the length of the side of the smaller pennant?

Answers

This is a proportion problem because the problem stated that the two team pennants are similar.

Pennant 1 = base = 18 in ; length = 9 inches
Pennant 2 = base =   6 in ; length = x ?

9/18 = x/6
9*6 = 18x
54 = 18x
54/18 = x
3 = x

The length of the  side of the smaller pennant is 3 inches.

Answer:the answer is 3inches

Step-by-step explanation:

Simplify
(1/81) to the 1/4 power

Answers

{ \left( \frac { 1 }{ 81 } \right) }^{ \frac { 1 }{ 4 } }\n \n =\sqrt [ 4 ]{ \frac { 1 }{ 81 } } \n \n =\frac { 1 }{ 3 }

This is because...

\frac { 1 }{ 3 } * \frac { 1 }{ 3 } * \frac { 1 }{ 3 } * \frac { 1 }{ 3 } =\frac { 1 }{ 81 }

$6300 is invested , part of it at 12%, and part at 6%.  For a certain year, the total yield is 564.00.  How much was invested at each rate?

Answers

x - first part of the investment (12% rate)
y - second part of the investment (6% rate)

Total investment: x + y = 6300
Total yield: 564 = x*0,12 + y*0,06

Based on that we can calculate x and y:
\left \{ {y=6300-x} \atop {0,12x+0,06(6300-x)=564}} \right.

\left \{ {y=6300-x} \atop {0,12x+378-0,06x=564}} \right.

\left \{ {y=6300-x} \atop {0,06x=186}} \right.

\left \{ {y=6300-x} \atop {x=3100}} \right.

\left \{ {y=3200} \atop {x=3100}} \right.

Answer: $3100 was invested at 12% and $3200 at 6%.

If you have any questions, please let me know!

3x-2(x+5)=14 then x
​

Answers

3x-2 (x+5) =14
3x -2x -10 = 14
x -10 =14
10. 10. add 10 to both sides
x = 24
:)

Answer:

x = 24

Step-by-step explanation:

3x-2(x-5)=14

remove the parentheses using distributive property

3x-2x-10=14

collect like terms

x-10=14

move constant to the right side and change the sign

x=14+10

calculate ( add the numbers together)

x = 24
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