Write the quadratic equation in factored form. Be sure to write the entire equation. x2 - 5x - 24 = 0

Answers

Answer 1
Answer: x² - 5x - 24 = 0

x² ⇒ x * x ⇒ (x + __) (x - __)
24 ⇒ 8 * 3 
-5 ⇒ - 8 + 3

(x - 8)(x + 3) = 0

x(x+3) - 8(x+3) = x² + 3x - 8x - 24 = x² - 5x - 24 

(x-8) = 0
x = 8

(x+3) = 0
x = -3
Answer 2
Answer:

Answer: (x-8)(x+3)=0


Step-by-step explanation:

The standard quadratic equation is ax^2+bx+c=0

Given quadratic equation:-x^2-5x-24=0, here a=1, b= -5, c= -24

Now, factorize given functions, first find two numbers that multiply to give ac and add to give b

ac=1×-24= -24

After checking factors of -24 we found -8 and 3 which multiply to give -24 and add to give -5

Rewrite the equation by writing -5 as sum of -8 and 3, we get

x^2+(-8+5)x-24=0\n\Rightarrow\ x^2-8x+3x-24=0\n\Rightarrow\ (x^2-8x)+(3x-24)=0\n\Rightarrow\ x(x-8)+3(x-8)=0\n\n[\text{Take (x-8) as common outside}]\n\Rightarrow\ (x-8)(x+3)=0



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Convert 79 oz to _____ g
Round answer to the nearest whole gram.

Answers

To convert 79 oz into grams, we need to begin with a conversion factor for ounces and grams.

1 ounce = 28.4 grams

Next, notice that we are going from a larger unit "ounces" to a smaller unit "grams." When we go from a larger unit to a smaller unit, we multiply.

79 oz × 28.4 ← Conversion factor

2243.6

Therefore, 5 oz = 2243.6 grams

2243.6 rounds to 2,440 grams

1 oz = 28.35 g.

thus, 79 oz = 2239.65 g

=  2240 g.

The coverage included in an automobile insurance policy that covers property damage is _______ insurance

Answers

Answer: The coverage included in an automobile insurance policy that covers property damage is Liability insurance

Step-by-step explanation:

The coverage included in an automobile insurance policy that covers property damage is liability insurance.

Liability insurance is a part of general insurance is also known as "Third party insurance", which is compulsory insurance without this insurance no vehicle can be plied on road , is a system of risk financing to prevent the customer from any lawsuits imposed for any accident.


This is liability insurance, and it covers the damage made by others to your property.

On a vertical line segment, point A is located at 50. Point B is located at 104. Point P is a point that divides segment AB in a ratio of 1:5 from A to B. Where is point P located?

Answers

Answer:

Step-by-step explanation:

Let the initial point on the line segment be O. If point A is located at 50 and point B is located at 104, then OA = 50 and OB = 104. Using the vector notation;

AO+OB = AB

(-OA)+OB = AB

-50+104 = AB

AB = 54

If point P divides the segment AB in a ratio 1:5, them AP:PB = 1:5

AP = 54/6

AP = 9

PB = 54-9

PB = 45

Hence the point P is located at 9 units from A and 45 units from B

Which of the following is NOT a characteristic of an inner planet? A. rocky B. solid surface C. near the sun D. made mostly of gas

Answers

it is D, made mostly of gas. that's an outer planet characteristc.

The correct answer is D. Made mostly of gas. Hope this helps! :)

Los Angeles Airport bears 140 degrees from San Francisco Airport and is 540 km away. A pilot is planning a direct flight from San Francisco Airport to Los Angeles Airport to leave at 2 P.M. The plane's air speed will be 640 km/h, and there will be a 60 km/hwind blowing from 290 degrees. What should the compass heading be,and what is the plane's estimated time of arrival (ETA) to the nearest minute?

Answers

Create a triangle starting with the length of 540 coming out of SF to LA bearing 140.
This looks like it leaves SF in IV quadrant and enters LA in II quadrant. The wind will take the plane more to the east (right).  Therefore the pilot must aim to the west (left) in order for the wind to push it to the intended destination of LA. The second side of the triangle should come out of LA from the II quadrant bearing 290.  The length of this side is 60t (60 km/h * t = time flying).  The third side of the triangle connects the first two.  There for it comes out of SF at some unknown angle > 140 and connects with the 60t side.  The length of this third leg is 640t. (640 km/h * t = time flying).  The angle between the 540 side and the 60t side is 30.  This is found because the 540 side enters LA in 2nd quadrant as 130 angle .  The 60t side enters LA in 2nd quadrant as 160 angle.  Using law of sin's: sin 30/640t = sin x/60t.  The t's cancel and you are left with sin x = 3/64.  When solving for the angle x you get x = 2.6867 degrees.  Adding this to the bearing of 140, the compass bearing should be 142.6867 or 142.7 degrees.  To find the value of t, you use the law of sin's to get sin 30/640t = (sin (180 - 30 - 2.6867))/540.  Solving for t gives you: t = .7811.  This is in hours.  To convert to minutes multiply by 60 to get t = 46.87 minutes.  Add this to the 2pm departure time to get 2:47 pm arrival time.

A balloon has a circumference of 28 in. Use the circumference to approximate the volume of the balloon to the nearest square inch.Answer choices:
3,659 in ^3
11,488 in ^3
2,964 in ^3
944 in ^3

Answers

the correct question is
a) A balloon has a circumference of 28 in. Use the circumference to approximate the volume of the balloon to the nearest cubic inch.

or

b) A balloon has a circumference of 28 in. Use the circumference to approximate the surface area of the balloon to the nearest square inch.

case a)
we know that
circumference=2*pi*r
clear variable r
r=circumference/(2*pi)
circumference=28 in
r=28/(2*pi)----> r=4.46 in

volume of a balloon=(4/3)*pi*r³-----> (4/3)*pi*4.46³----> 371.61 in³
Volume=372 in³

the answer is
372 in³


case b)
we know that
circumference=2*pi*r
clear variable r
r=circumference/(2*pi)
circumference=28 in
r=28/(2*pi)----> r=4.46 in

surface area of a balloon=4*pi*r²-----> 4*pi*4.46²---> 249.83 in²
Surface area=249.83 in²-------> 250 in²

the answer is
250 in²