Answers
Answer:
Sodium and potassium.
Explanation:
Aldosterone hormone is produced by the adrenal cortex (zona glomerulosa ) cells of the kidney. This is the main mineralocorticoid and the steroidal hormone.
Aldosterone is mainly involved in the regulation of sodium and potassium ions. The sodium ions are reabsorbed and potassium ions is secreted by the influence of aldosterone hormone.
Thus, the correct answer is option (a).
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Answers
Answer:
0.549 is the frequency of the F allele.
0.495 is the frequency of the Ff genotype.
Explanation:
FF or Ff genotypes determine freckles, ff determines lack of freckels.
In this class of 123 students, 98 have freckles (and 123-98= 25 do not).
If the class is in Hardy-Weinberg equilibrium for this trait, then the genotypic frequency of the ff genotype is:
q²= 25/123
q²=0.203
q=
q= 0.451
q is the frequency of the recessive f allele.
Given p the frequency of the dominant F allele, we know that:
p+q=1, therefore p=1-q
p=0.549 is the frequency of the F allele.
The frequency of the Ff genotype is 2pq. Therefore:
2pq=2×0.549×0.451
2pq=0.495 is the frequency of the Ff genotype.
Final answer:
The frequency of the dominant allele, F, in this class is 0.55. The frequency of the heterozygous genotype, Ff, is 0.495. This is calculated using Hardy-Weinberg equilibrium and observed phenotype frequencies.
Explanation:
To start, we need to calculate the frequency of the recessive allele, f, which is easily calculated as those who do not have freckles. From a total of 123 students, 98 have freckles, leaving 25 students with no freckles, which represents individuals who are homozygous for the recessive trait (ff). As these are the only individuals we can be sure of, we take the square root of their frequency to get the frequency of the recessive allele, q. In this case, q = sqrt(25/123) = 0.45. To find the frequency of the dominant allele, p, we subtract q from 1 (because p + q = 1), so p = 1 - q = 0.55.
Next, we'll calculate the frequency of the heterozygous genotype Ff.
Using Hardy-Weinberg equilibrium, we know this is represented by 2pq. Hence, the frequency of genotype Ff would be 2 × 0.55 × 0.45 = 0.495.
This process offers an example of applying the principles of population genetics and Hardy-Weinberg equilibrium to determine the likely genotype frequencies in a given group of individuals based on observed phenotype frequencies.
Learn more about Genetic Frequencies here:
#SPJ11
2) Tetany
3) relaxation
4) repolarization
Answers
Answer:
Tetany
Explanation
The refractory period in the heart refers to the shortest interval between consecutive contraction conducted impulses out of the cardiac muscle.
It is important because it allows adjustments to stimuli and limits amount of action potential sent per minute.
Without a plateau extending the refractory period in the cardiac muscles.
Sarcomeres might be stimulated to contract instead of relaxing leading to sustained contraction also called Tetany.
Tetany is an involuntary muscle cramp or contraction caused by overly stimulated nerves.
B. Red headed females in a population will only breed with red headed males. The yellow headed females will only breed with yellow headed males. The red and yellow populations live on separate continents and rarely met in nature. The red and yellow could breed and produce fertile offspring but they normally do not. This would be an example of sympatric speciation.
C. Sympatric speciation does not require geographic isolation.
D. Red headed females in a population will only breed with red headed males. The yellow headed females will only breed with yellow headed males. This population lives in the same geographic area. The red and yellow individuals could breed and produce fertile offspring but they normally do not. This would be an example of sympatric speciation.
E. Sympatric speciation can be due to sexual(mate) selection
Answers
Answer: Options A, C and E are correct
A) Sympatric speciation is best described as a random event that disrupts the allele frequencies in a population
C) Sympatric speciation does not require geographic isolation.
E) Sympatric speciation can be due to sexual(mate) selection
Explanation:
Sympatric speciation is the situation whereby organisms of the same species:
- live in the same territory or nearby territories ( i.e not living in isolation)
- DO NOT interbreed, but select a sexual mate from a much diverse territory which results in an uneven gene flow or disruption of alleles in new species or offsprings of such parents organisms.
Answers
Answer:
Vermicast.
Explanation:
Vermicast are worm castings, worm manure, or worm faeces.
Answer:
Vermicast.
Explanation:
lol I copied his answer to get points LOL
Answers
Answer:
40,000 + 5,000 + 600 + 10 + 7
Answer: 40,000 5,000 600 10 7
"hope this helps"
Explanation:
Answers
Answer:
Hope this will help you... And please mark me as Brilliant
Explanation:
Permineralization. Permineralization is a process of fossilization that occurs when an organism is buried. The empty spaces within an organism (spaces filled with liquid or gas during life) become filled with mineral-rich groundwater. ... Small-scale permineralization can produce very detailed fossils.