Choose the polynomial that is written in standard form.−3x5y2 + 4x3y + 10x2
−8xy2 + 4x4y2 + 3x3
x4y2 + 4x3y5 + 10x4
x6y2 + 4x3y8 + 10x7

Answers

Answer 1
Answer:

Answer:

Option A is the correct option.

Step-by-step explanation:

Polynomials given in the question are

1) -3x^(5)y^(2)+4x^(3)y+10x^(2)

2) -8xy^(2)+4x^(4)y^(2)+3x^(3)

3) x^(4)y^(2)+4x^(3)y^(5)+10x^(4)

4) x^(6)y^(2)+4x^(3)y^(8)+10x^(7)

In a standard form of a polynomial term with the highest degree should be written first, then second highest degree term and similarly other terms should be written.

Here 1st polynomial is in the standard form only in which degree of terms are as followed.

1 term 3x^(5)y^(2) degree of term = (5 +2) = 7

2nd term 4x^(3)y degree of term = (3 +1) = 4

3rd term 10x² degree of term = 2

So the answer is option A.

Answer 2
Answer: The polynomial that is written in standard form is:

-3x^5^2 + 4x^3y + 10x^2

As you can see, the terms are arranged based on the value of the exponents. From the largest exponent x^5 to the smallest exponent x^2.

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Solve. 6 × r = 42

Please help. :(

Answers

Answer:

r = 7

Step-by-step explanation:

42 ÷ 6 = 7

Cheyanne plans to put $150 into a savings account. she can place her money into an account represented by f(x)=5x+150, or into another account represented by g(x)=150(1.03)^x. which account has the highest value in 3 years? which account has the highest value in 10 years?1. f(x) has the highest value in 3 years; g(x) has the highest value in 10 years

2. g(x) has the highest value in 3 years; f(x) has the highest value in 10 years

3. f(x) has the highest value in 3 years; f(x) has the highest value in 10 years

4.g(x) has the highest value in 3 years; g(x) has the highest value in 10 years

Answers

Answer: 1. f(x) has the highest value in 3 years; g(x) has the highest value in 10 years


Step-by-step explanation:

Given:- Principal amount= $150

First account represented by the function=f(x)=5x+150→Linear function

Second account represented by the function=g(x)=150(1.03)^x→Exponential function

where x is the time period in years.

When x=3 years

f(3)=5(3)+150=15+150=\$165

g(3)=150(1.03)^3=\$163.90

here, f(x) has the highest value .

When x=10 years

f(10)=5(10)+150=50+150=\$200

g(10)=150(1.03)^(10)=\$201.58

g(x) has the highest value.

Therefore, f(x) has the highest value in 3 years; g(x) has the highest value in 10 years


20pts What is the distance between (7, 3, 4) and (5, 2, 9)?


Really need help!!!

Answers

To find the distance between two 3d pointssquare the difference of the x, y, and z points. Then, sum them and take the square root.
Distance=(x2x1)^2+(y2y1)^2+(z2z1)^2

Replace x^1,x^2,y^1,y^2,z^1, and z^2 with the corresponding values.
Distance=((5)−(7))^2+((2)−(2))^2+((9)−(4))^2

Simplify 
√((5)−(7))^2+((2)−(2))^2+((9)−(4))^2
calculator....

Distance= √29


The distance between (7,2,4) and (5,2,9) is 29.

√29≈5.38516481

Four times the sum of a number and two increased by three is at least twenty seven

Answers

4(x + 2) + 3 >= 27

4x + 8 + 3 >= 27

4x + 11 >= 27

4x >= 16

x >= 4

Answer:

I can help with Aleks!

Step-by-step explanation:

x>4

I hope this helps!



 log6 (x+1)− log6 x =log6 29 


Answers

log_6(x+1)-log_6x=log_629;\ D:x+1 > 0\ \wedge\ x > 0\Rightarrow x\in\mathbb{R^+}\n\nlog_6(x+1)/(x)=log_629\iff(x+1)/(x)=29\n\n29x=x+1\n\n29x-x=1\n\n28x=1\ \ \ \ /:28\n\nx=(1)/(28)\in D\leftarrow solution
D:x+1>0 \wedge x>0\n D:x>-1 \wedge x>0\n D:x>0\n \log_6(x+1)-\log_6 x=\log_6 29\n \log_6(x+1)=\log_6 29+\log_6x\n \log_6(x+1)=\log_6 29x\n x+1=29x\n 28x=1\n x=(1)/(28)

Is 2/3 greater than 2/4

Answers

2/3=0.666666666666........

1/2=0.500000000000........

Therefore:

2/3 > 1/2

The answer is yes because the fraction 2/3 is greater than 2/4.

Is 2/3 greater than 2/4?

To compare 2/3 and 2/4, we need to find a common denominator.

The least common multiple (LCM) of 3 and 4 is 12. So, we can rewrite the fractions with a common denominator:

2/3:

= (2/3) * (4/4)

= 8/12

2/4:

= (2/4) * (3/3)

= 6/12

Therefore, the answer is yes because the fraction 2/3 is greater than 2/4.

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