CHEMISTRY MIDDLE SCHOOL

A tank has 30 gallons of gasoline how many liters of gasoline are there in the tank

Answers

Answer 1

Answer:

Answer:

$113.55 l$

Explanation:

1 gallon equals 3,785 liters.

How many liters are in 30 gallons?

We apply a simple rule of three to solve it

$1 gallon \longrightarrow 3.785 l\n 30 gallons \longrightarrow x \n x=((30 gallons)(3.785l))/(1 gallon)= 113.55 l.$

Answer 2

Answer:

Answer: I think it is: 113.5624 Liters of gas

Explanation:

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How many atoms of hydrogen are in 24.4 g of methane?

Answers

Answer:

The number of atom is 3.67*10^24 atoms

Explanation:

Molar mass of methane CH4 is 16.0g/mol

Using this to divide the mass

24.4g/16.0 = 1.525mol

1 mol CH4 contains 1 mol of Carbon C and 4 mol of hydrogen H, so 1.525mol contains 4(1.525)=6.1 molH

Using avogadro number : (6.1mol)(6.02*10^23)

= 3.67*10^24 atoms

Final answer:

There are 3.66 × 10^24 hydrogen atoms in 24.4 g of methane (CH4). This is calculated by first finding the number of moles of CH4 and then using Avogadro's number to determine the total number of molecules, which is finally multiplied by 4 (the number of hydrogen atoms per CH4 molecule).

Explanation:

The question asks how many atoms of hydrogen are in 24.4 g of methane (CH4). Methane has a molecular formula of CH4, indicating that each molecule contains 4 hydrogen atoms. The molar mass of methane is 16.04 g/mol (12.01 g for carbon + 4 × 1.008 g for hydrogen).

First, calculate the number of moles of methane:

24.4 g CH4 × (1 mol CH4 / 16.04 g CH4) = 1.52 mol CH4

Then, multiply by Avogadro's number to find the total number of methane molecules:

1.52 mol CH4 × (6.022 × 1023 molecules/mol) = 9.15 × 1023 molecules of CH4

Since each molecule of methane has 4 hydrogen atoms, we get:

9.15 × 1023 molecules CH4 × (4 H atoms/molecule) = 3.66 × 1024 hydrogen atoms.

Match the numbers and alphabets.1. Inertia a. amount of matter in an object
2. mass b. sum of all forces acting on an object
3. force c. tendency to resist a change in motion
4. unbalanced forces d. push or pull
5. balanced forces e. can change an objects motion
6. net force f. will not change an object's motion

Thank you!

Answers

1 C
2 A
3 D
4 F
5 E
6 B

These are the answers

a cadillac escalade has a mass of 2.569 kg if it acceleratesat 4.65m/s what is the net force on the car

Answers

The Net Force is equal to the mass of the Object multiplied by the amount of Acceleration. Therefore, this creates an equation which looks like this:

F = Mass * Acceleration
F = 2.569 kg * 4.65 m/s
F = 11.95 N

Hopes this helps!

1. What is the volume of 0.900 moles of an ideal gas at 25.0° C and a pressure of 950.0 mm Hg?1.50 liters
17.6 liters
18.0 liters
34.2 liters

2. What is the pressure, in mm Hg, of 2.50 moles of an ideal gas if it has a volume of 50.0 liters when the temperature is 27.0° C?
84.2 mm Hg
289 mm Hg
617 mm Hg
936 mm Hg

3. When 12.4 grams of KBr are dissolved in enough water to create a 170-gram solution, what is the solution's concentration, expressed as a percent by mass?
6.2% KBr
6.8% KBr
7.3% KBr
7.9% KBr

Answers

1. Using the ideal gas law, which states that PV = nRT, and remembering that absolute temperature must be used:
(950.0 mmHg)(V) = (0.900 moles)(R)(25.0 + 273.15 K)
The most convenient value of R is 0.08206 L-atm/mol-K, so we convert the pressure of 950.0 mmHg to atm by dividing by 760: 1.25 atm
(1.25 atm)(V) = (0.9)(0.08206)(298.15)
V = 17.6 L

2. Again using the ideal gas law, and converting temperature to Kelvin: 27 + 273.15 = 300.15 K
PV = nRT
P(50.0 L) = (2.50 moles)(0.08206 L-atm/mol-K)(300.15 K)
P = 1.23 atm
Then we multiply by 760 mmHg / 1 atm = 936 mmHg. This is the fourth of the choices.

3. If the complete solution has a mass of 170 grams, and 12.4 grams of it is the dissolved KBr, we simply have to divide the mass of solute (KBr) by the total mass of the solution: This gives us 12.4 grams / 170 grams = 0.0729. Multiplying by 100% gives 7.29% or approximately 7.3% KBr, which is the third of the choices.

1. The volume of the ideal gas is $\boxed{{\text{17}}{\text{.6 L}}}$ .

2. The pressure of the ideal gas is $\boxed{{\text{936 mm Hg}}}$ .

3. The concentration of the solution, expressed as mass percent is $\boxed{{\text{7}}{\text{.3 \% }}}$ .

Further Explanation:

An ideal gas is a hypothetical gas that is composed of a large number of randomly moving particles that are supposed to have perfectly elastic collisions among themselves. It is just a theoretical concept and practically no such gas exists. But gases tend to behave almost ideally at a higher temperature and lower pressure.

Ideal gas law is the equation of state for any hypothetical gas. The expression for the ideal gas equation is as follows:

${\text{PV}} = {\text{nRT}}$ .......(1)

Here,

P is the pressure of ideal gas.

V is the volume of ideal gas.

T is the absolute temperature of the ideal gas.

n is the number of moles of the ideal gas.

R is the universal gas constant.

1. Rearrange equation (1) to calculate the volume of the ideal gas.

${\text{V}}=\frac{{{\text{nRT}}}}{{\text{P}}}$ ......(2)

The pressure of the ideal gas is 950 mm Hg.

The temperature of the ideal gas is ${\text{25}}\;^\circ{\text{C}}$ .

The number of moles of the ideal gas is 0.9 mol.

The universal gas constant is 0.0821 L atm/K mol.

Substitute these values in equation (2).

$\begin{aligned}{\text{V}}&=\frac{{\left( {{\text{0}}{\text{.9 mol}}} \right)\left( {0.0821{\text{ L atm/K mol}}} \right)\left( {25 + 27{\text{3}}{\text{.15}}}\right){\text{K}}}}{{\left( {950{\text{ mm Hg}}}\right)\left( {\frac{{{\text{1 atm}}}}{{760{\text{ mm Hg}}}}}\right)}}\n&= 17.624{\text{ L}}\n&\approx {\text{17}}{\text{.6 L}}\n\end{aligned}$

Therefore the volume of the ideal gas is 17.6 L.

2. Rearrange equation (1) to calculate the pressure of ideal gas.

${\text{P}} =\frac{{{\text{nRT}}}}{{\text{V}}}$ ......(3)

The volume of the ideal gas is 50 L.

The temperature of the ideal gas is ${\text{27}}\;^\circ {\text{C}}$ .

The number of moles of the ideal gas is 2.5 mol.

The universal gas constant is 0.0821 L atm/K mol

Substitute these values in equation (3).

$\begin{aligned}{\text{P}}&= \frac{{\left( {{\text{2}}{\text{.5 mol}}} \right)\left( {0.0821{\text{ L atm/K mol}}} \right)\left( {27 + 27{\text{3}}{\text{.15}}} \right){\text{K}}}}{{{\text{50 L}}}}\n&= 1.2321{\text{ atm}}\n&\approx 1.232{\text{ atm}}\n\end{aligned}$

The pressure is to be converted into mm Hg. The conversion factor for this is,

${\text{1 atm}} = {\text{760 mm Hg}}$

So the pressure of ideal gas can be calculated as follows:

$\begin{aligned}{\text{P}} &= \left({{\text{1}}{\text{.232 atm}}}\right)\left( {\frac{{{\text{760 mm Hg}}}}{{{\text{1 atm}}}}}\right)\n&= 936.3{\text{2 mm Hg}} \n&\approx 93{\text{6 mm Hg}}\n\end{aligned}$

Therefore the pressure of the ideal gas is 936 mm Hg.

3. The formula to calculate the mass percent of KBr is as follows:

${\text{Mass}}\;{\text{percent}}=\left( {\frac{{{\text{Mass of KBr}}}}{{{\text{Mass of solution}}}}}\right)\left( {100} \right)$ ......(4)

The mass of KBr is 12.4 g.

The mass of the solution is 170 g.

Substitute these values in equation (4).

$\begin{aligned}{\text{Mass}}\;{\text{percent}}&= \left( {\frac{{{\text{12}}{\text{.4 g}}}}{{{\text{170 g}}}}} \right)\left( {100} \right)\n&= 7.294\;\% \n&\approx 7.{\text{3 \% }}\n\end{aligned}$

Therefore the concentration of the solution is 7.3 %.

Learn more:

1. Which statement is true for Boyle’s law: brainly.com/question/1158880

2. Calculation of volume of gas: brainly.com/question/3636135

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Mole Concept

Keywords: P, V, n, R, T, ideal gas, pressure, volume, 17.6 L, 936 mm Hg, 7.3 %, 0.9 mol, 950 mm Hg, 50 L, 2.5 mol, 12.4 g, 170 g, KBr

Is the element CH4 a metal or non metal

Answers

non metal i believe let me know if i helped

Meteorologists in New York City are tracking a hurricane that is approaching the city. What type of instrument or system are these meteorologists most likely using?a ground station

a weather buoy

a ship

a satellite

Answers

A satellite because you have a better view

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