Which of the following has the greatest effect on colligative properties?A. Epsom salt (MgSO4)
B. Calcium chloride (CaCl2)
C. Potassium Iodide (KI)
D. Glucose (C6H12O6)
Answers
Answer:
- Option B. Calcium chloride (CaCl₂)
Explanation:
The colligative properties depend on the concentration of particles (molecules or ions) of solute dissolved and not on the identity of the solute.
For your reference the colligative properties are: i) boiling point increase, ii) freezing point depression, iii) vapor pressure lowering, and iv) osmotic pressure.
When the solute is a ionic compound the ionization yields several ions, so for ionic solutes you must predict first the number or ions formed per unit of compound and then predict the effect on the colligative properties: the greater the number of ions per unit of compound the greater the effect on colligative properties.
So, just set the ionization equations for each compound:
- MgSO₄ (aq) → Mg²⁺ (aq) + SO₄²⁻ (aq): 2 ions
- CaCl₂ (aq) → Ca²⁺ (aq) + 2Cl⁻ (aq) : 3 ions
- KI (aq) → K⁺ (aq) + I⁻ (aq): 2 ions
- C₆H₁₂O₆ is a molecular compound, not a ionic one, so it remains s 1 molecule.
Then, since calcium chloride, CaCl₂, produces the greater number of ions it is the solute that productes the greatest effect on colligative properties.
Answer:
D. Calcium chloride (CaCl2)
Explanation:
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Mg - 3 times 24.31 g= 72.93 g
N - 2 times 14.01 g= + 28.02 g
Molar Mass= 100.95 g/mol Mg3N2
The molar mass of magnesium nitride ) is 100.91 g/mol.
How do we calculate?
To calculate the molar mass, we need to add up the atomic masses of each atom in the molecule. The atomic masses of the elements in are:
Magnesium: 24.31 g/mol
Nitrogen: 14.01 g/mol
The molar mass ofmagnesium nitride is calculated as follows:
Molar mass of magnesium nitride = 3 * 24.31 g/mol + 2 * 14.01 g/mol
= 100.91 g/mol
Therefore, the molar mass of magnesium nitride is 100.91 g/mol.
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Which of the following shows the equation balanced?
A. 3 O2 + CS2 → CO2 + 2 SO2
B. 3 O2 + CS2 → 2 CO2 + SO2
C. O2 + CS2 → CO2 + SO2
D. 4 O2 + 4 CS2 → 4 CO2 + 4 SO2
Answers
Answer:
Look at the equation below.
→
The equation balanced is:
A. →
Explanation:
The equation balanced is:
→
This can be proved with the amount of atoms of each element in reagents and products:
Reagents:
O=6
C=1
S=2
Products:
O=6
C=1
S=2
The option that shows the that the equation is balanced is:
3O₂ + CS₂ → CO₂ + 2SO₂ (option A)
How to balance the equation?
The equation O₂ + CS₂ → CO₂ + SO₂ can be balanced as shown below:
O₂ + CS₂ → CO₂ + SO₂
There are 2 atoms of S on the left side and 1 atom on the right. It can be balanced by writing 2 before SO₂ as shown below:
O₂ + CS₂ → CO₂ + 2SO₂
There are 2 atoms of O on the left side and a total of 6 atoms on the right. It can be balanced by writing 3 before as shown below:
3O₂ + CS₂ → CO₂ + 2SO₂
Now, we can see that the equation is balanced. Thus, the correct answer to the question is 3O₂ + CS₂ → CO₂ + 2SO₂ (option A)
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Answers
Option (b)
Zirconium belongs to group IV and 5th period of the periodic table. The electronic configuration is here, Kr belongs to 18th group (noble gas) with atomic number 36 and electrons per shell is 2, 8, 18, 8.
Since, atomic number is equal to number of protons and number of electrons, atomic number of zirconium will be 36+2+2=40.
Thus, atomic number of zirconium is 40.
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Answer:
The arrow means "yield" or "react to form".
Explanation: The arrow means "yield" or "react to form".