A candy maker buys a bar of chocolate weighing 162 ounces. about how many pounds does the bar weigh?

Answers

Answer 1

Answer: the answer is about 10 pounds

Answer 2

Answer: I don't get your question but other people might but it don't say someone 162

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Fiecare dintre cei 26 de baieti si 14 fete care au participat la excursia de la Bran au adunat câte 5 pietricele pentru acvariul clasei.Cate pietricele sunt in total?Calculează în două moduri.

Answers

26+14=40
40*5=200 pietricele
Sau
26*5=130
14*5=70
130+70=200pietricele

the answer is 35 of whatever u said

Pls help Find the sum.3
5+−
1
5
3
5+−
1
5=two fifths
2
5 (Type an integer or a fraction.)

Answers

Answer:

Calculator soup has a calculator that can do that

Step-by-step explanation:

2/5
Just subtract the numerators

I do not get please help!!

Answers

Dominic: $2(3)/(4)$
Rachel : $1 (1)/(3)$ as long
How long Rachel worked:

$2(3)/(4) = (11)/(4)$
$1 (1)/(3)$ = $(4)/(3)$

$(11)/(4)$ × $(4)/(3)$
$(44)/(12)$ = $3 (2)/(3)$

The answer is C. $3(2)/(3)$

The first five terms of a sequence are 7,10, 13 , 16 and 19. which of the following functions define this sequence for all integers n>or equal to 1?A. f[n]= 3n=7
B.f[n]= 4+3n
C. f[n]= 4[3]^n-1
D.f[n]=7[3]^n-1

Answers

The correct option is D) f(n) = 4 + 3n.

Step-by-step explanation:

Given :

Arithmetic Sequence -- 7,10,13,16,19

Solution :

The explicit formula of arithmetic sequence is given by,

$T_n = a+(n-1)d$ ------- (1)

where, common difference (d) = 10 - 7 = 3

first term (a) = 7

So from equation (1),

$T_n = 7+(n-1)3 = 7+3n-3$

$T_n = 4 + 3n$

Therefore, the correct option is D) f(n) = 4 + 3n.

For more information, refer the link given below

brainly.com/question/15412619?referrer=searchResults

Answer:

Option B is correct

For $n\geq 1$ , the function for the given sequence is defined as; $f[n] = 4 +3n$

Step-by-step explanation:

An arithmetic sequence is a sequence in which the difference between each consecutive term is constant.

An explicit formula for this arithmetic sequence given by;

$a_n = a+(n-1)d$ where a represents first term

Since, the given sequences; 7 , 10 , 13 , 16 and 19

⇒ common difference(d) = 3 and a = 7

Since.

10 -7 = 3

13- 10 = 3 ....

The function which defined this sequence is;

$f[n]=a_n = 7 +(n-1)(3)$

using distributive property:

$f[n] = 7 + 3n -3$

$f[n] = 4 +3n$

therefore, the function for the given sequence for all integers $n\geq 1$ is; $f[n] = 4 +3n$

Why is 12 (m+n) equivalent to 12m + 12n

Answers

because 12(m=n) means that you are multiplying 12 times m and 12 times n. So if there is a number outside of parenthesis it gets multiplied by all the nu,beds in the parenthesis.
12(1+2)
36 either way. that is proof. if you want more proof use any number in replace of n and m

Because of the distributive property. You multiply the outside number (12) by the variables inside the parentheses (m and n). Then you add them together, so you get 12m+12n.
You can check it by plugging in numbers for m and n, then solving it both ways. You will get the same answer.

at a track meet,Jacob and daniel compete in 220 m hurdles. Daniels finishes in 3/4 of the a min.Jacob finishes with 5/12 of a min remaining.who ran the race in faster time?

Answers

Answer:

Jacob finished the race faster than Daniel.

Step-by-step explanation:

We have that,

Daniel completed the hurdle in $(3)/(4)$ of a minute i.e. 75% of a minute.

Jacob completed the hurdle with $(5)/(12)$ remaining of a minute i.e. 41.7% remaining of a minute.

Now, as we have that,

75% of a minute = 45 seconds

41.7% of a minute = 25 seconds

Since, Jacob had $(5)/(12)$ time remaining.

Thus, Jacob had = 60 - 25 = 35 seconds remaining.

So, Daniel ran in 45 seconds and Jacob ran in 35 seconds.

Hence, we get that, Jacob finished the race faster than Daniel.

Jacob

Further explanation

Given:

At a track meet, Jacob and Daniel compete in 220 m hurdles.

Daniels finishes in $(3)/(4)$ of the a min.

Jacob finishes with $(5)/(12)$ of a min remaining.

Question:

Who ran the race in faster time?

The Process:

Let us see the denominators. The least common multiple (LCM) of 4 and 12 is 12.

Let us draw the diagram that represents a minute.

$\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}$ 12 units represent in one minute.

Daniels finishes in $(3)/(4)$ of the a min.

$(3)/(4) = (9)/(12)} \rightarrow \boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}$ or 9 of 12 units.

Jacob finishes with $(5)/(12)$ of a min remaining, or 5 of 12 units. This means Jacob finishes in $(7)/(12)$ or 7 of 12 units, that is $\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}$

And now we conclude who ran the race in a faster time.

Daniels: $\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}$

Jacobs: $\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}$

Because Jacob took the race in a shorter time, he was who ran the race in a faster time.

- - - - - - - - - -

Quick Steps

Daniels: in $\boxed{ \ (3)/(4) = (9)/(12) \ }$ of the a min.

$\boxed{(9)/(12) * 60 \ minutes = 45 \ seconds}$

Jacob: in $\boxed{ \ 1 - (5)/(12) = (7)/(12) \ }$ of the a min.

$\boxed{(7)/(12) * 60 \ minutes = 35 \ seconds}$

Jacob's time is shorter, so he's the fastest.

- - - - - - - - - -

Calculate the speed

Recall $\boxed{speed = distance / time}$

Daniels: $\boxed{speed = 220 \ m / 45 \ seconds = 4(8)/(9) \ m/s \ }$

Jacob: $\boxed{speed = 220 \ m / 35 \ seconds = 6(2)/(7) \ m/s \ }$

Thus, Jacob's speed proved greater than Daniels's speed.

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Keywords: at a track meet, Jacob and Daniel, compete in 220 m hurdles, Daniels, finishes, in 3/4 of the a min, Jacob, finishes, with 5/12 of a min, remaining, who, ran, the race, in faster time, diagram

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