Whats 30+30×b=100 please

Answers

Answer 1

Answer: First multiply

30 + 30 × b = 100
30b + 30 = 100

subtract 30 from each side

30b = 70

divide each side by 30

b = 70/30 = 7/3 = 2 1/3

Answer 2

Answer: 30 +30= 60
60b=100
B=40

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What decimal is represented by this expanded form?5 x 10,000 + 3 x 1,000 + 2 x 10 + 8 x 1 + 6 1/1,000 + 4 x 1/,000

Answers

5 x 10,000 + 3 x 1,000 + 2 x 10 + 8 x 1 + $6 (1)/(1000)$ + 4 x $(1)/(1000)$

you want to make the $6 (1)/(1000)$ into a whole number:
$6 (1)/(1000)$ = 6.001

new equation:
5 x 10,000 + 3 x 1,000 + 2 x 10 + 8 x 1 + 6.001 + 4 x $(1)/(1000)$
50,000 + 3 x 1,000 + 2 x 10 + 8 x 1 + 6.001 + 4 x $(1)/(1000)$
50,000 + 3,000 + 2 x 10 + 8 x 1 + 6.001 + 4 x $(1)/(1000)$
50,000 + 3,000 + 20 + 8 x 1 + 6.001 + 4 x $(1)/(1000)$
50,000 + 3,000 + 20 + 8 + 6.001 + 4 x $(1)/(1000)$
50,000 + 3,000 + 20 + 8 + 6.001 + .004
53,000 + 20 + 8 + 6.001 + .004
53,020 + 8 + 6.001 + .004
53,028 + 6.001 + .004
53,034 + .004
=53,034.005

Is 28/49=4/7 a ratio proportion

Answers

28 / 49
divide by 7 at top and bottom

(28/7) / (49/7)
4 / 7

Caitlin is 62 1/4 inches tall. Her older brother Jaime is 9 1/2 inches taller than Caitlin.Jaime is 2 1/4 inches shorter than their father. How tall is their father?

Answers

To do this you want to first add 9 1/2 to 62 1/4. 9 1/2 is changed to 9 2/4. 9 2/4 plus 62 1/4 is 71 3/4. Now you have to add 2/14 to 71 3/4 to find how tall their father is. 2/14 plus 71 3/4 is 74. Their dad is 74 inches tall which is equal to 6 feet 2 inches.

You would add Caitlin's height 62 1/4 (62.25) to 9 1/2 (9.5) to get Jaime's height which is 71 3/4 (71.75).Then you add 2 1/4 (2.25) to 71 3/4 (71.75) to get their father's height which is 74 inches.

What is -2 times -3?

Answers

Their making me type 20 characters. -_- but the answer is -6.

-2 x -3 is 6, because - x - = +, we multiply 2*3 then change the - to a +

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. The box plot compares the monthly average temperature (in degrees Fahrenheit) recorded in the towns of Springwood and Meadows from April to October. Match each phrase to its correct value. the median of the temperatures at Springwood _______

the median of the temperatures at Meadows: ______

the interquartile range of the temperatures at Springwood:_______

the interquartile range of the temperatures at Meadows:_______

the difference of the medians as a multiple of their average interquartile range:_______

Answers

Hello,

The median of the temperatures at Springwood is 86. (median is at the middle).

the median of the temperatures at Meadows is 73. (median is at the middle).

The (IQR) interquartile range of the temperatures at Meadows is 12. (You have to subtract both of the IQR left and right 80 - 68 = 12).

The (IQR) interquartile range of the temperatures at Springwood is 14. (You have to subtract both of the IQR left and right 91 - 77 = 14).

the difference of the medians as a multiple of their average interquartile range is 79.5 is average median and 13 average IQR.

Answer: The median of the temperatures at Springwood is 86.

The median of the temperatures at Meadows is 73.

The interquartile range of the temperatures at Meadows is 12.

The interquartile range of the temperatures at Springwood is 14.

The difference of the medians as a multiple of their average interquartile range as : Difference in medians = 13= 1 x 13

i.e. Difference in medians = 1 x (Average interquartile range)

Step-by-step explanation:

In a box - whisker plot , the vertical line in box represents the median value.

The left end of box denotes Lower quartile and the right end of the box Upper quartile.

By considering the given picture,

For Meadows ,

Median = 73

The median of the temperatures at Meadows is 73. (1)

Lower quartile = 68

Upper quartile = 80

Interquartile range = Upper quartile- Lower quartile

Interquartile range=80-68 = 12

The interquartile range of the temperatures at Meadows is 12. (2)

For Springwood,

Median = 86

The median of the temperatures at Springwood is 86. (3)

Lower quartile = 77

Upper quartile = 91

Interquartile range = Upper quartile- Lower quartile

= 91-77 = 14

The interquartile range of the temperatures at Springwood is 14. (4)

Difference in medians = 86-73 = 13 [From (1) and (3)]

Average interquartile range = $(12+14)/(2)=13$ [From (2) and (4)]

The difference of the medians as a multiple of their average interquartile range as : Difference in medians = 13= 1 x 13

i.e. Difference in medians = 1 x (Average interquartile range)

14. According to a recent government study, the average 15-year-old male gets 11.4% of his daily caloric intake from sugar drinks.If that 15-year-old consumes 2,400 calories each day, how many calories come from sugar drinks?

Answers

The calories come from sugar drinks = 269.76 calories

Step-by-step explanation:

Daily caloric intake from sugar drinks = 11.4%
Total calories consumed each day = 2400

Calories come from sugar drinks = 11.4% of 2400

⇒ (11.4/100) $*$ 2400

⇒ 11.4 $*$ 24

⇒ 269.76 calories.

∴ Calories come from sugar drinks is 269.76 calories.

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