Can someone find me this quotient 0.77/-0.9

Answers

Answer 1

Answer: the answer is -0.856

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Roseanna did not pay last month's credit card bill in full. Her daily balances for her last billing cycle are listed. What was Roseanna's average daily balance to the nearest cent? (Hint: Find the average or mean of these numbers.)For seven days she owed $456.11

For three days, she owed $1,077.00

For six days, she owed $900.08

For nine days, she owed $2,113.15

For five days, she owed $2,310.15

Answers

Average daily balance = (456.11 + 1,077.00 + 900.08 + 2,113.15 + 2,310.15)/(7 + 3 + 6 + 9 + 5) = 6,856.49/30 = 228.55

Therefore, Roseanna's average daily balance = $228.55

Answer:

$228.54

Step-by-step explanation:

Given : Roseanna did not pay last month's credit card bill in full. Her daily balances for her last billing cycle are listed.

To Find: What was Roseanna's average daily balance to the nearest cent?

Solution:

For seven days she owed $456.11

For three days, she owed $1,077.00

For six days, she owed $900.08

For nine days, she owed $2,113.15

For five days, she owed $2,310.15

Mean = $\frac{\text{Sum of amount owned}}{\text{Total no. of days}}$

Mean = $(456.11+1077+900.08+2113.15+2310.15)/(7+3+6+9+5)$

Mean = $(6856.49)/(30)$

Mean = $228.5496$

Hence Roseanna's average daily balance to the nearest cent is $228.54

I need help lol....

Answers

The slope is 3/2x

Can you mark me brainleist

It’s so easy it’s 3/2x pls mark me as brainliest plssssss I’ll give u 30 points

Three fifths is__________pieces of the whole

Answers

60 pieces of the whole
3/5 = x/100
5*20 = 100
3*20 = 60

Give the nth term and the next term of this

8,13,18,23,28

Answers

so it's add 5 to each so the next term would be 33

so first term is 8 so
1st term=8
2nd term=8+5 so therefor the equation is
the nth term is 8+5n-5
so therfor first term is 8+5(1)-5=8+5-5=8

second term=8+5(2)-5=8+5=13

equation is nth term=8+5n-5

Your answer is going to be 33. All it is doing is adding up 5

Function f(x) = ax^{2}+bx+c, where a, b, and c are some constants. Define functions g and h as follows:g(x) = f(x+ 1)−f(x)
h(x) = g(x+ 1)−g(x)
Find algebraic form of h(x)
Can anyone explain how to make it step by step?

Answers

g(x) = f(x+1) - f(x)
=[ a(x+1)^2+b(x+1)+c ] - [ax^2+bx+c]
=[ a(x^2+2x+1) +bx + b + c ] - [ax^2 + bx + c]
=[ ax^2 + 2ax + a + bx + b + c ] - [ax^2 + bx + c]
= ax^2 + 2ax + a + bx + b + c - ax^2 - bx - c
= 2ax + a + b
Therefore g(x) = 2ax + a + b
h(x) = g(x+1) - g(x)
=2a (x+1) + a + b - [2ax+a+b]
=2ax + 1 + a +b - 2ax - a - b
Therefore h(x) = 1

Rachel draws a trend line through the following data
points. Did she draw the line correctly?

Answers

Answer:

i think its A but im not sure its correct

Step-by-step explanation:

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