A beach ball has a radius of 9 inches what is the volume

Answers

Answer 1

Answer: V=4/3pir^3
r=9
V=4/3pi9^3
v=4/3pi729
V=972pi

if want, aprox pi=3.141592
V=3053.627424 in^3

Answer 2

Answer: Solutions

The volume of a sphere is given by the formula V = 4/3 πr³ , where V is the volume of the sphere and r is its radius. We know that the radius is 9 inches.

Calculations

Formula = V=4/3πr³

V=4/3πr³

v=4/3πr³ ( 9 ) = r

r³ = 9 x 9 x 9 = 729

V=972π

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In a poll of Mr. Briggs's math class, 67% of the students say that math is their favorite academic subject. The editor of the school paper is in the class, and he wants to write an article for the paper saying that math is the most popular subject at the school.

Answers

Mathematics is the subject that is most popular in the class and is liked by the students.

Explanation:

Among all the subjects that are added in the curriculum of the students in the school, Mathematics is the subject that is mostly liked by the students in the class and in the school.

To find this that mathematics was the favorite subject of the students, a a survey was conducted by the school people in the class of a professor and through that survey it was shown that Mathematics was a subject that was mostly liked by all the students.

the perimeter of a rectangle is 32 centimeters. The length is 1 cm more than twice the width. Find the dimensions of the rectangle.

Answers

Answer: length = 11cm , width = 5cm

Step-by-step explanation:

The formula for calculating the perimeter of a rectangle is given by :

P = 2 ( L + w )

The length is 1 cm more than twice the width implies:

L = 1 + 2w

substituting into the formula , we have

32 = 2 ( 1 + 2w + w )

32 = 2 ( 1 + 3w)

32 = 2 + 6w

32 - 2 = 6w

30 = 6w

Therefore :

w = 5

then

L = 1 + 2w

L = 1 + 2 ( 5 )

L = 1 + 10

L = 11

Therefore , the length is 11 cm and the width is 5cm

It is 10 3/5 miles from Alston to Barton and 12 1/2 miles from Barton to Chester. The distance from Alston to Durbin, via Barton and Chester is 35 miles. How far is it from Chester to Durbin?

Answers

see the picture attached to better understand the problem

Let
x----------> The distance from Chester to Durbin

we know that
$10 (3)/(5) = ((10*5+3))/(5) \n \n = (53)/(5) miles$

$12 (1)/(2) = ((12*2+1))/(2) \n \n = (25)/(2) miles$

$10 (3)/(5) +12 (1)/(2) +x=35$
subtitute

$(53)/(5) + (25)/(2) +x=35$

solve for x

$x=35-( (53)/(5)+ (25)/(2) ) \n \n x=35- ((2*53+5*25))/(10) \n \n x=35- (231)/(10) \n \n x=35-23.10 \n \n x=11.9$

$x=11 (9)/(10)$ miles

the answer is
$11 (9)/(10)$ miles

Answer:

Durbin is $11(9)/(10)\:miles$ far from Chester.

Step-by-step explanation:

Distance Between Alston and Barton = $10(3)/(5)\:miles$

Distance Between Barton and Chester = $12(1)/(2)\:miles$

Distance Between Alston and Durbin = $35\:miles$

Distance between Chester and Durbin = $35-10(3)/(5)-12(1)/(2)$

= $35-(53)/(5)-(25)/(2)$

= $(350-106-125)/(10)$

= $(119)/(10)$

= $11(9)/(10)\:miles$

Therefore, Durbin is $11(9)/(10)\:miles$ far from Chester.

Peggy completed 5/6 of the math homework and Al completed 4/5 of the math homework. Did Peggy or Al complete more of the math homework?

Answers

Peggy completed more because more equal parts that are smaller with more shaded means it has to be more.

Answer:

I would say that 4/5 is smaller than 5/6 So Al did less than Peggy Correct me if I'm wrong.

Step-by-step explanation:

For the 1st fraction, since 5 × 6 = 30,

/5= 4 × 6 = 24

5 × 6 = 30

Likewise, for the 2nd fraction, since 6 × 5 = 30,

5/6 = 5 × 5

=25

6 × 5 30

Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction

24 25 4 5

30 < 30

or 5 <6

Which of the following equations matches the graph?

Answers

Answer:

The answer closest to the graph is C. y= 5x-4

Step-by-step explanation:

If you graph the first answer (A. y= 1/5x+4), there is going to be a horizontal line above the x intercept. If you graph the second answer (B. y= 1/5x-4), there is going to be a horizontal line below the x intercept.

An iguana at a pet store is 5 feet long.measurements for iguana cages are given in inches.How many inches long is the iguana?

Answers

Given is :

The length of the iguana = 5 feet

But as the measurements for iguana cages are given in inches. So, we have to convert feet into inches.

1 foot = 12 inches,

5 feet = $12*5=60$

Hence, the length of iguana in inches is 60 inches.

60 inches long because, there are 12 inches to a foot and if the iguana is 5 feet that would mean to find the inches it would be 12*5=60

Enjoy!=)

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