Which of the following statements is always true? A. Acute triangles are scalene. B. Scalene triangles are acute. C. Acute triangles are equilateral. D. Equilateral triangles are acute.

Answers

Answer 1

Answer: D.) equilateral triangles are acute.
- In an equilateral triangle, the 3 angles are always 60 degrees.

Answer 2

Answer:

Final answer:

None of the given options in the question are true. Not all acute, scalene or equilateral triangles are the other types. They have distinct characteristic which defines them.

Explanation:

The subject matter of this question is about the different types of triangles, namely acute triangles, scalene triangles, and equilateral triangles.

An acute triangle is a triangle in which all three angles are less than 90 degrees. A scalene triangle is a triangle where all sides and angles are different. An equilateral triangle is a triangle where all sides and angles are equal, with each angle being 60 degrees.

Looking at these definitions, we can see that none of the given options are true. Not all acute triangles are scalene (they can be isosceles or equilateral), not all scalene triangles are acute (they can be obtuse or right), not all acute triangles are equilateral (they can be scalene or isosceles), and not all equilateral triangles are acute (they are, by definition, always acute).

Learn more about Triangles here:

brainly.com/question/34963952

#SPJ6

Related Questions

The number of professors in a college is p and the number of students is s, there are 16 times as many students as professors write an algebraic expression that shows the relationship.
I need some help with this problem
Answer pls i need bring grades up
C) The determinant of 2 x 2 matrix A is 3. If you switch the rows and multiply the first row by 6 and the second row by 2, explain how to find determinant and provide the answer
The student council is selling cookies.They buy the cookies from the store for .55 cents each.They sell the cookies for $1 each.What is the percent of markup

A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about the graph is true?A.) The graph of the function is positive on (–6, –2).
B.) The graph of the function is negative on (negative infinity symbol, 0).
C.) The graph of the function is positive on (–2, 4).
D.) The graph of the function is negative on (4, infinity symbol).

Answers

The correct answer for the question that is being presented above is this one: "C.) The graph of the function is positive on (–2, 4)." A polynomial function has a root of –6 with multiplicity 1, a root of –2 with multiplicity 3, a root of 0 with multiplicity 2, and a root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, then C.) The graph of the function is positive on (–2, 4).

Answer:

C -2,4

Step-by-step explanation:

i got it right on edge

Solve this problem: –282 – (+1,017) =

Answers

This question more or less tries to trick you with the positive number in parentheses, as you would carry out subtraction as normal. However, since the number you are subtracting from is also negative, it would be easier to think about it as adding two positives, and setting aside the negative symbol for the answer.

-282 - 1017 = -(282 + 1017) = -(1299) = -1299

which is your final answer.
-282 - (+1017) = -1299.
Hope that helped! =)

-7 - 7 ( 8x - 7 ) = - 19 + 5x

Answers

-7 - 7( 8x - 7 ) = -19 + 5x
⇔ -56x + 49 = -12 + 5x
⇔ -61x = -61
⇔ x = 1

Write the equation of the hyperbola that has a center at (4, - 1), a focus at (11, - 1), and a vertex at (0, - 1).

Answers

Answer: 56

Step-by-step explanation:

Final answer:

Given the center, focus, and vertex of a hyperbola, the equation of the hyperbola can be determined using the standard formula for a hyperbola and calculations for the values of a and b. For the hyperbola with center (4, -1), focus (11, -1), and vertex (0, -1), the equation is (x - 4)²/16 - (y + 1)²/33 = 1.

Explanation:

The subject of the question is to write the equation of the hyperbola given the center, focus, and vertex. In general, the equation of a horizontal hyperbola is (x - h)²/a² - (y - k)²/b² = 1 where the (h, k) is the center, a is the distance from the center to a vertex, and b is the distance from the center to a co-vertex. In this case, the center is (4, -1), the focus is (11, -1), the and vertex is (0, -1).

To determine a, calculate the distance from the center to a vertex. With the center at (4, -1) and vertex at (0, -1), a = 4. To determine b, apply the hyperbola's relationship of c² = a² + b², where c is the distance from the center to a focus. Given that the distance to the focus (from (4, -1) to (11, -1)) is 7 (so, c = 7) and a = 4, solve for b to get b = sqrt(c² - a²) = sqrt(49-16)= sqrt(33). Therefore, the equation of the hyperbola is (x - 4)²/16 - (y + 1)²/33 = 1.

Learn more about Hyperbola here:

brainly.com/question/19989302

#SPJ11

Which is greater 1yd or 4ft

Answers

4 feet is bigger because there is only 3 feet in 1 yard

Which sequence is modeled by the graph below?coordinate plane showing the points 2, 1; 3, 3; and 4, 9

an = one third(27)n − 1

an = 27(one third)n − 1

an = one third(3)n − 1

an = 3(one half)n − 1