Could someone show me the work for the answer?

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Answer 1

Answer: What’s the question?

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PLEASE HELP!!!!!The data set represents the heights of players on a soccer team. 5.75, 5.16, 6, 5.25, 5.5, 6.25, 5.66, 5.33, 5.33, 6, 5.75. 5.66, 5.16 What is the interquartile range (IQR) of the data set? A. 0.585 B. 1.09 C. 5.6 D. 5.875
Simplify 9b-5b ?? Pls help
What is the average of the following numbers: 3.2, 47/12,10/3?
A football is kicked toward an end zone with an initial vertical velocity of 30 ft/s. The function h(t) = -16+ 30t models the height h (in feet) of the football at time t (in seconds). Which statement about the height of the football is true?A. The football does not reach a height of 15 feet. B.The football reaches a height of exactly 15 feet. C. The football reaches a height that is greater than 15 feet.
1200+0.075x>=3300 what is the solution to the inequality

Pls help with question 3 and below

Answers

Step-by-step explanation:

now find the area of triangle and add with the area of square and subtract with the area of circle

hope it will help you

Nikki is participating in a charity walk thisweekend. She walks at a pace of 4.2 miles
per hour. How long will it take her to walk
35.7 miles?

Answers

Answer:

8.5 hours

Step-by-step explanation:

We know that it takes Nikki 1 hour to walk 4.2 miles.

We need to figure out how long it will take her to walk 35.7 miles.

This is our expression; 35.7 ÷ 4.2.

Let's go ahead and divide these two numbers.

(35.7 ÷ 4.2) = 8.5

So It will take Nikki 8.5 hours to walk 35.7 miles.

Feel free to give brainliest.

Have an excellent day!

Find the area of a sector of this circle that is intercepted by a central angle measuring 30°

Answers

The area of a sector of a circle can be calculated by using this formula:

A=(n/360)*pi*r^2

where n is the measure of the central angle of the sector in degrees. Since we are already given with the measurement of the central angle, we can substitute this to the above formula:

A=(30/360)*pi*r^2

Taking the value of pi as 3.14, then

A=(1/12)*3.14*r^2
A=0.2617*r^2

Just plug in the value of r. and you will get the area of the sector. Hope this helps!

Paul opened a bakery. The net value of the bakery (in thousands of dollars) ttt months after its creation is modeled by v(t)=2t^2-12t-14v(t)=2t 2 −12t−14v, left parenthesis, t, right parenthesis, equals, 2, t, squared, minus, 12, t, minus, 14 Paul wants to know what his bakery's lowest net value will be. 1) Rewrite the function in a different form (factored or vertex) where the answer appears as a number in the equation.

Answers

Given:

The net value of the bakery (in thousands of dollars) t months after its creation is modeled by

$v(t)=2t^2-12t-14$

Paul wants to know what his bakery's lowest net value will be.

To find:

The function in a different form (factored or vertex) where the answer appears as a number in the equation.

Solution:

Factor form is used to find the x-intercepts and vertex form is used to find the extreme values (maximum or minimum). So, here we need to find the vertex form.

We have,

$v(t)=2t^2-12t-14$

$v(t)=2(t^2-6t)-14$

Adding and subtract square of half of 6 in the parenthesis, we get

$v(t)=2(t^2-6t+3^2-3^2)-14$

$v(t)=2(t^2-6t+3^2)+2(-9)-14$

$v(t)=2(t-3)^2-18-14$ $[\because (a-b)^2=a^2-2ab+b^2]$

$v(t)=2(t-3)^2-32$

Vertex form:

$f(x)=a(x-h)^2+k$

where, (h,k) is vertex.

On comparing this equation with vertex form, we get the of the function is (3,-32).

Therefore, the vertex form is $v(t)=2(t-3)^2-32$ and the function has minimum value at (3,-32). It means, minimum net value of the bakery is -32 after 3 months.

The vertex form is v(t) = 2(t - 3)² - 32 and the function has a minimum value at (3,-32). It means the minimum net value of the bakery is -32 after 3 months.

Given that,

Paul opened a bakery.

The net value of the bakery (in thousands of dollars) t months after its creation is modelled by the equation v(t) = 2t²- 12t - 14.

Paul wants to determine the bakery's lowest net value.

To rewrite the function in a different form,

Find the vertex of the quadratic equation.

The vertex form of a quadratic equation is given by,

v(t) = a(t-h)² + k,

Where (h, k) represents the coordinates of the vertex.

Proceed, v(t) = 2t² - 12t - 14,

v(t) = 2(t² - 6t) - 14,

v(t) = 2(t² - 6t + 3² - 3²) - 14

v(t) = 2(t - 3)² - 32

Vertex form:

v(t) = a(t-h)² + k,

where, (h,k) is vertex.

On comparing this equation with vertex form, we get the function is (3,-32).

Therefore,

The vertex form is v(t) = 2(t - 3)² - 32 and the function has a minimum value at (3,-32). It means minimum net value of the bakery is -32 after 3 months.

To learn more about quadratic equations visit:

brainly.com/question/30098550

#SPJ3

What is the value of y?
3y2 − 6 = 42
±___

Answers

3•y•2-6=42 6y-6=42 6y=42+6 6y=48 y=8 I hope that is right !

What is the area of the trapezoid?

Answers

I hope this helps you

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