How many moles is 1.50 x 1023 molecules of NH3

Answers

Answer 1
Answer: 1 mole ------ 6.02 x 10²³ molecules
? mole ------ 1.50 x 10²³ molecules

moles = 1.50 x 10²³ * 1 / 6.02 x 10²³

moles = 1.50 x 10²³ / 6.02 x 10²³

= 0.249 moles  

hope this helps!


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Which type of extremophile is characterized by thriving in very hot and salty conditions? a) Halophile b) Psychotroph c) Mesophile d) Acidophilic

Answers

Answer:

a) Halophile

Explanation:

Halophiles are extremophiles characterized by their ability to thrive in very hot and salty conditions, such as salt flats, salt mines, or hypersaline environments. They have adapted to high levels of salt and can withstand extreme salinity.

PLSSSSSSSSSSSSSSSSSSSSSSSSSS HELP Which of the following best describes physical weathering? (4 points)
A series of chemical changes that wears away at rocks
The movement of rocks from one area to another
Any large-scale event such as volcanic eruptions or earthquakes
A process that breaks down large rocks into smaller piec

Answers

Answer:

D. A process that breaks down large rocks into smaller pieces.

Explanation:

Physical weathering if referred to the process of rocks breaking apart without changing their chemical composition. If you look at the other answers, none of them match the description of physical weathering.

Answer:

A process that breaks down large rocks into smaller pieces.

Upwelling is a proccess in which warm, nutrient rich water from the deep ocean rises to the surface. TRUE or FALSE.

Answers

The statement about “Upwelling is a process in which warm, nutrient rich water from the deep ocean rises to the surface” is false. It must be the cold, nutrient rich water from the deep ocean that must rise to the surface and replaces warm surface water. The cause of upwelling is when the local wind patterns blow along the northwest coast of South America causing local surface currents to move away. The warm water is then replaced by the deep cold water

Answer:

false

Explanation:

Which is true about fossil fuels? A.
Coal and natural gas came from swamp environments, while oil came from open oceans.

B.
Coal came from swampy environments, while oil and natural gas came from open ocean environments.

C.
Coal, oil, and natural gas came from swamp environments.

D.
Natural gas and oil came from swamp environments, while coal came from open oceans.

Answers

Which is true about fossil fuels? The statement that is true about fossil fuels is Coal came from swampy environments, while oil and natural gas came from open ocean environments. The answer is letter B. The rest of the choices is not true for fossil fuel 

Express in scientific notation. Make sure your answer has the same number of significant figures as the starting value. 0.01325 = _____

Answers

0.01325 = 1.325x10^-2 or 13.25 x 10^-3 or 132.5 x 10^ - 4 or 1325 x 10^-5. Scientific notation is the standardized way to represent any number as the product of a real number and a power of ten.

Final answer:

The number 0.01325 is expressed in scientific notation as 1.325 x 10^-2. The number of significant figures remains the same.

Explanation:

The starting value 0.01325 can be converted to scientificnotation by first moving the decimal place. In this case, the decimal moved to the right by 2 places, making the number 1.325. So the number in scientific notation becomes 1.325 x 10^-2. Notice that there are still the same 4 significant figures (1, 3, 2, 5) in the number 1.325 as in the original number 0.01325.

Learn more about Scientific Notation here:

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The reaction A→B has been experimentally determined to be second order. The initial rate is 0.0100M/s at an initial concentration of A of 0.300M. Determine the initial rate at [A]=0.900M.

Answers

Answer:

0.09 M/s is the initial rate when concentration of reactant A is 0.900 M.

Explanation:

A → B

1) Initial concentration of A = [A] =0.300 M

Rate constant of the reaction , k = ?

Rate equation for the second order kinetic is given as:

R=k[A]^2

0.0100M/s=k[0.300 M]^2

k=(0.0100M/s)/([0.300 M]^2)=0.1111 M^(-1) s^(-1)

2) Rate of the reaction when initial concentration of A was 0.900M be R'.

[A] = 0.900M

R'=k[A]^2

R'=0.1111 M^(-1) s^(-1)* [0.900 M]^2

R'=0.09 M/s