What is the geometric mean of 6 and 96

Answers

Answer 1

Answer: Hi,
the geometric mean of 6 and 96 is √(6*96)=24

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You add two numbers together, and the total is 122. If you triple the smaller number and subtract 34, it will equal the larger number. What are the two numbers?

Answers

Answer: 39 and 83

Step-by-step explanation:

Let's assume the smaller number is represented by 'x' and the larger number is represented by 'y'.

According to the given information, we have two equations:

Equation 1: x + y = 122

Equation 2: 3x - 34 = y

We can solve this system of equations to find the values of 'x' and 'y'.

Substituting Equation 2 into Equation 1, we get:

x + (3x - 34) = 122

Combining like terms:

4x - 34 = 122

Adding 34 to both sides:

4x = 122 + 34

4x = 156

Dividing both sides by 4:

x = 39

Substituting the value of 'x' back into Equation 1:

39 + y = 122

Subtracting 39 from both sides:

y = 122 - 39

y = 83

Therefore, the smaller number is 39 and the larger number is 83.

A dolphin jumped from 5 feet below the surface of the sea. Jane wrote −5 to represent the depth from which the dolphin jumped. What does 0 represent in this situation?the floor of the sea
the surface of the sea
the level to which the dolphin jumped
the level from which the dolphin jumped

Answers

The surface of the sea.

If -5 means that the dolphin was 5 feet below the surface, then represents the surface of the sea. And, for instance, if the dolphin jumped 5 feet above the surface of the sea, 5 would represent that.

Answer:

Answer: surface of the sea

hope this helps :)

What expression is not equivalent to 1/343 A. 7-1 x 7-2
B.77 x 7-10
C. 7-2 x 7-5
D. 7-5 x 72
(All expressions have an Integer either negative or positive u just can't type it correctly here and B and D or not 77 or 72 it's 7 and positive 7 and D is 7 positive 2

Answers

1 / 343
This is just equal to
1 / 7^3 = 7^-3

A. 7^-1 * 7^-2 = 7^(-1 + -2) = 7^-3
B. 7^7 * 7^-10 = 7^( 7+ -10) = 7^-3
C. 7^-2 * 7^-5 = 7^(-2 + -5) = 7^-7
D. 7^-5 * 7^2 = 7^(-5 + 2) = 7^-3

So the correct answer is letter C. 7^-2 * 7^-5

Using the laws of indices, simplify the following:-

√h × √h³ =

Answers

$\sqrt h\cdot√(h^3)=\nh^{(1)/(2)}\cdot \left(h^3\right)^{(1)/(2)}=\nh^{(1)/(2)}\cdot h^{(3)/(2)}=\nh^{(1)/(2)+(3)/(2)}=\nh^{(4)/(2)}=\nh^2$

or other way

$\sqrt h\cdot√(h^3)=\n √(h^4)=\n √((h^2)^2)=\n |h^2|=\n h^2$

Solve.

$√(x-1)+3=x$

Answers

$√(x-1)+3=x;\ Domain:x-1\geq0\ \wedge\ x\geq3\to x\geq1\ \wedge\ x\geq3\nD:x\in[3;\ \infty)\n\n√(x-1)=x-3\ \ \ \ |square\ both\ sides\n\nx-1=(x-3)^2\ \ \ \ |use\ of\ the\ formula:(a-b)^2=a^2-2ab+b^2\n\nx-1=x^2-6x+9\n\nx^2-6x+9=x-1\n\nx^2-6x-x+9+1=0\nx^2-7x+10=0\ \ \ \ |use\ quadratic\ formula$

$a=1;\ b=-7;\ c=10\n\n\Delta=b^2-4ac\to\Delta=(-7)^2-4\cdot1\cdot10=49-40=9\n\nx_1=(-b-\sqrt\Delta)/(2a);\ x_2=(-b+\sqrt\Delta)/(2a)\n\n\sqrt\Delta=\sqrt9=3\n\nx_1=(7-3)/(2\cdot1)=(4)/(2)=2\notin D\n\nx_2=(7+3)/(2\cdot1)=(10)/(2)=5\in D\n\nSolution:x=5$

$√(x-1)+3=x\n √(x-1)=x-3\n D:x-1\geq0 \wedge x-3\geq0\n D:x\geq1 \wedge x\geq3\n D:x\geq3\n x-1=(x-3)^2\n x-1=x^2-6x+9\n x^2-7x+10=0\n x^2-2x-5x+10=0\n x(x-2)-5(x-2)=0\n (x-5)(x-2)=0\n x=5 \vee x=2\n 2\not \in D \Rightarrow x=5$

Simplify completely the quantity 3 times x to the 4th power plus 5 times x to the 2nd power plus 2 times x all over x.the quantity 3 times x to the third power plus 5 times x plus 2 all over x
3x3 + 5x + 2
3x2 + 5x2 + 2x
3x5 + 5x3 + 2x2