Cathy has 10 feet of ribbon that she wants to use to make bows. She needs 2/3 foot of ribbon for each bow. She also needs to use 16 inches of the ribbon for another project. How many bows will she able to make with the amount of ribbon that is left?

Answers

Answer 1

Answer: 13 bows is the correct answer because:

10 feet=120 inches
2/3 foot= 8 inches
so 120-16 is 104 and that divided by 8 is 13.

Answer 2

Answer:

Answer:

Step-by-step explanation:

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What is the slope and y-intercept of this equation?
2x+4y=14

Answers

Equations don't have slopes or y-intercepts, but their graphs might.
Let's solve this equation for 'y', and see whether its graph has them.

2x + 4y = 14

Subtract 2x from each side: 4y = -2x + 14

Divide each side by 4 : y = -1/2x + 7/2 .

In this form, we can look at the equation, and see immediately that
if we were to draw its graph, then the graph would be a straight line
with slope= -1/2 and y-intercept= 7/2 .

How to factor out the coefficient of the variable : 1/2m + 1/2 = ??

Answers

$(1)/(2)m+(1)/(2)=(1)/(2)(m+1)$

1/2m+1/2

=1/2(m+1)

*Research the "distributive property" to simplify such problems.

Below is an example of how the distributive property functions:

a(b+c+d)

=ab+ac+ad

A pile of newspapers in Ms. McGrath’s art class was 17 3/4 inches high. Each consecutive week, for the next 5 weeks, the height of the pile of newspapers increased by 8 7/12 inches. What was the height, in inches, of the pile after 3 weeks?

Answers

If you would like to know what was the height, in inches, of the pile after 3 weeks, you can calculate this using the following steps:

17 3/4 inches + 3 * 8 7/12 inches = 71/4 + 3 * 103/12 = 213/12 + 309/12 = 522/12 = 87/2 = 43 1/2 inches

The correct result would be 43 1/2 inches.

Let

x--------> the number of weeks

y--------> the height of a pile of newspapers in inches

we know that

$17(3)/(4)=(17*4+3)/(4) =(71)/(4)$

$8(7)/(12)=(8*12+7)/(12) =(103)/(12)$

$y=(103)/(12)x+(71)/(4)$

To find the height after $3$ weeks

Let

$x=3\ weeks$ and substitute in the equation

$y=(103)/(12)*3+(71)/(4)$

$y=(174)/(4)$

$y=43.5\ in$

$y=43(1)/(2) \ in$

therefore

the answer is

the height, in inches, of the pile after $3$ weeks is $43(1)/(2) \ in$

Ok so read over this like 5 times and i still dont get what to do .

Answers

Answer:

Graph the points, first number along x-axis & second number along the y- axis.

Answer: First number along x-axis & Second number along the y- axis.

Step-by-step explanation:

Which of these numbers 420, 654, 1246, 5721, 74082, 18465 are multiples of 2 and 3 but not 5?

Answers

Answer:

The answers are 654 and 74082.

Let f(x)=2x+2. Solve f^-1(x) when x=4

Answers

f⁻¹(x) stands for the invers of function f(x). The inverse of f(x) is equal to x. We need to solve for x.

solve for x
f(x) = 2x + 2
2x + 2 = f(x)
2x = f(x) - 2
x = $(f(x)-2)/(2)$
f⁻¹(x) = $(x-2)/(2)$

Determine the value of f⁻¹(x) when x = 4
f⁻¹(x) = $(x-2)/(2)$
f⁻¹(4) = $(4-2)/(2)$
f⁻¹(4) = $(2)/(2)$
f⁻¹(4) = 1
When x = 4, the value of f⁻¹(x) is equal to 1

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