The direct sunlight at Earth's surface is about 1050 W/m2 . Compute mass lost by Sun in a thousand years as a fraction of Earth Mass? The lost Mass of sun/in a million yrs = ……?…..% of Earth Mass.

The amount of potential energy that was initially stored in the spring due to the wooden block is 65.3 joules.

What is potential energy?

Potential energy is the energy which body posses because of its position.

The potential energy of a body is given as,

Here, (m) is the mass of the body, (g) is the gravitational force and (h) is the height of the body.

The energy stored in the spring is the sum of all the potential energy, kinetic energy and the energy dissipated due to friction. Therefore, it can be given as,

Here, the mass of the wooden block is 1.05 kg . Angle of inclination is  35.0 degrees (point A). The distance from point B is 4.90m up the incline from A.

The speed of the block is 5.10 m/s and the coefficient of kinetic friction between the block and incline is 0.55. Therefore, put the values in the above formula as,

Hence, the amount of potential energy that was initially stored in the spring due to the wooden block is 65.3 joules.

Learn more about the potential energy here;

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Answer:

Explanation:

energy stored in spring initially

= kinetic + potential energy of block + energy dissipated by friction

= 1/2 mv² + mgh + μ mgcosθ x  d

m is mass , v is velocity at top position , h is vertical height , μ is coefficient of friction ,θ is angle of inclination of plane

= m (1/2 v² + gh + μ gcosθ x  d )

= 1.05 ( .5 x 5.1² + 9.8 x 4.9 sin35 + .55 x 9.8 cos35 x 4.9 )

= 1.05 ( 13.005 + 27.543 + 21.635)

= 65.3 J .

Answer:

300 clicks...

Explanation:

Output on 3 clicks = 10 dB

Increasing 10 by a factor of 100 equals 1000 dB so,

Its simple math, clicks will also increase in the same ratio and it shall take 300 clicks to increase the volume by a factor of 100.

Answer:

(a) %a, 10 A, 0.833 A

(b) 12 ohm

(c) $22.8

Explanation:

Power of toaster, P1 = 600 W

Power of iron, P2 = 1200 W

Power of bulb, P3 = 100 W

V = 120 V

As they are in household circuit, so they are connected in parallel, so the voltage is same for all.

(a) Use the formula P = V x i

Current in toaster, i1 = P1 / V = 600 / 120 = 5 A

Current in iron, i2 = P2 / V = 1200 / 120 = 10 A

Current in bulb, i3 = P3 / V = 100 / 120 = 0.833 A

(b) Resistance of heating element of iron is R2.

V = i2 x R2

120 = 10 x R2

R2 = 12 ohm

(c) Total energy consumed in 24 hours for 5 days

                              = (600 + 1200 + 100) x 24 x 5 = 228000 Wh = 228 KWh

Cost of 1 KWh = $0.1

Cost of 228 KWh = 0.1 x 228 = $22.8

_______________________________

Answer:

(a). Toaster = 5A

Iron = 10A

Bulb = 0.833A

(b). R2 = 12Ω

(c). $ 22.8

_______________________________

Explanation:

Given,

Power of Toaster, P1 = 600W

Power of Iron, P2 = 1200W

Power of Bulb, P3 = 100W

Potential difference = 120V

They all are connected in parallel combination because they all are household circuits so that the voltage is same for all appliances in the circuit.

★Solution of(a)

By using the formula of powerwe can find out the current.

P=V×I

Here, power is directly proportional to the potential difference and electric current flowing through the circuit.

[.°.I=P/V]

Here,electriccurrent is inversely proportional to the potential differenceandelectric currentisdirectly proportional topower.

Current in Toaster, I1 = P1/V = 600/120 = 5A

Current in Iron, I2 = P1/V = 1200/120 = 10A

Current in Bulb, I3 = P1/V = 100/120 = 0.833A

★Solutionof(b)

Resistance of Heating coil of Iron

By using theformula of Ohm's Law we can find out the resistance of heatingcoil of iron.

V=I×R

Here, the potential difference is directly proportional to the current carrying wire and potential difference is directly proportional to the resistance off the wire present in the Iron.

[.°.R=V/I]

Here, resistance is directly proportional to the potential difference and resistance is inversely proportional to the electric current.

R=V/I

=> R = 120/10

.°. R = 12Ω

★Solutionof(c)

Total consumption of Energy in 24 hours for 5 days = (600W + 1200W + 100W) × 24 hours × 5 days

= 228000Wh

= 228kWh

When the cost of 1kWh = $ 0.1

So,

The cost of 228 kWh = $ 0.1 × 228 = $ 22.8

_______________________________

Answer: 114.4 GJ

Explanation:

Heat loss Q=U×A×ΔT

Heat loss of size A is determined by the U value of materials and the difference in temperature.

From 10.9cm from the ice

50m= 5000cm

A= 5000×5000

Q== (10.9) (5000) (5000)(4.184)(1×4 + 80)

Q = 95,771,760,000J

Q≈ 95.8 GJ

Linear gradient from the bottom of the pond to the ice:

Q = (89.1)(5000)(5000)(4.184)(1*2)

Q = 18,639,720,000J

Q ≈ 18.6 GJ

Total heat loss:

Q= 95.8GJ + 18.6GJ

Q= 114.4 GJ

Answer:

a

Explanation:

a push or a pull that occurs when an object interacts with another object or field.

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Answer:

0.46Ω

Explanation:

The electromotive force (E) in the circuit is related to the terminal voltage(V), of the circuit and the internal resistance (r) of the battery as follows;

E = V + Ir                      --------------------(a)

Where;

I = current flowing through the circuit

But;

V = I x Rₓ                    ---------------------(b)

Where;

Rₓ = effective or total resistance in the circuit.

First, let's calculate the effective resistance in the circuit:

The effective resistance (Rₓ) in the circuit is the one due to the resistances in the two lightbulbs.

Let;

R₁ = resistance in the first bulb

R₂ = resistance in the second bulb

Since the two bulbs are both rated at 4.0W ( at 12.0V), their resistance values (R₁ and R₂) are the same and will be given by the power formula;

P =

=> R =             -------------------(ii)

Where;

P = Power of the bulb

V = voltage across the bulb

R = resistance of the bulb

To get R₁, equation (ii) can be written as;

R₁ =    --------------------------------(iii)

Where;

V = 12.0V

P = 4.0W

Substitute these values into equation (iii) as follows;

R₁ =

R₁ =

R₁ = 36Ω

Following the same approach, to get R₂, equation (ii) can be written as;

R₂ =    --------------------------------(iv)

Where;

V = 12.0V

P = 4.0W

Substitute these values into equation (iv) as follows;

R₂ =

R₂ =

R₂ = 36Ω

Now, since the bulbs are connected in parallel, the effective resistance (Rₓ) is given by;

= +       -----------------(v)

Substitute the values of R₁ and R₂ into equation (v) as follows;

= +

=

Rₓ =

Rₓ = 18Ω

The effective resistance (Rₓ) is therefore, 18Ω

Now calculate the current I, flowing in the circuit:

Substitute the values of V = 11.7V and Rₓ = 18Ω into equation (b) as follows;

11.7 = I x 18

I =

I = 0.65A

Now calculate the battery's internal resistance:

Substitute the values of E = 12.0, V = 11.7V and I = 0.65A  into equation (a) as follows;

12.0 = 11.7 + 0.65r

0.65r = 12.0 - 11.7

0.65r = 0.3

r =

r = 0.46Ω

Therefore, the internal resistance of the battery is 0.46Ω

Answer:

Explanation:

Internal resistance is a concept that helps model the electrical consequences of the complex chemical reactions that occur within a battery. When a charge is applied to a battery, the internal resistance can be calculated using the following equation:

Where:

As you can see, we don't know the exactly value of the . However we can calculated that value using the next simple operations:

The problem tell us that the power of each lightbulb is 4.0 W at 12.0 V, hence let's calculated the power at 11.7V using Cross-multiplication:

Solving for :

Now, the electric power is given by:

Where:

So:

Now, because of the lightbulbs are connected in parallel the equivalent resistance is given by:

Finally, now we have all the data, let's replace it into the internal resistance equation: