Liver cells require a great deal of energy which cell organelles would you except to appear in large number as a result

Answers

Answer 1

Answer: Mitochondria are the powerhouses of the cell, so mitochondria is the answer

Answer 2

Answer:

Final answer:

Liver cells, which require a high amount of energy, contain large numbers of mitochondria, the organelles responsible for energy production in the form of ATP.

Explanation:

The cell organelles that you would expect to appear in large numbers in liver cells, which require a great deal of energy, are mitochondria. Mitochondria, often referred to as the 'powerhouses of the cell, are responsible for producing a molecule called adenosine triphosphate (ATP), which is the main source of cellular energy. Therefore, cells that require a lot of energy, like liver cells, tend to have many mitochondria in order to meet their energy demands.

Learn more about mitochondria here:

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A chemist burns 160.0 g of Al in O to produce Al2O3. She produces 260.0 g of Al2O3. Calculate the theoritical yield and percent yield

Answers

Answer:

86.04 %

Explanation:

Data given:

mass of Al = 160.0 g

actual yield Al₂O₃= 260 g

Theoretical yield = ?

percent yield ofAl₂O₃ = ?

Solution:

First we have to find theoretical yield.

So,

we Look at the balanced reaction

4Al + 3O₂ -----—> 2Al₂O₃

4 mol 2 mol

As 4 mole of Al give 2 mole of Al₂O₃

Convert moles to mass

molar mass of Al = 27 g/mol

molar mass of Al₂O₃ = 2(27) + 3(16)

molar mass of Al₂O₃ = 54 + 48

molar mass of Al₂O₃ = 102 g/mol

Now

4Al + 3O₂ -----—> 2Al₂O₃

4 mol (27g/mol) 2 mol (102 g/mol)

108 g 204 g

108 grams of Al produce 204 g of Al₂O₃

if 108 grams of Al produce 204 g of Al₂O₃ so how many grams of Al₂O₃will be produced by 160 g of Al.

Apply Unity Formula

108 grams of Al ≅ 204 g of Al₂O₃

160 grams of Al ≅ X of Al₂O₃

Do cross multiply

mass of Al₂O₃= 204 g x 160 g / 108 g

mass of Al₂O₃ = 302.2 g

So the Theoretical yield of Al₂O₃ = 302.2 g

Now Find the percent yield of Al₂O₃

Formula Used

percent yield = actual yield /theoretical yield x 100 %

Put value in the above formula

percent yield = 260g / 302.2 g x 100 %

percent yield = 86.04 %

percent yield of Al₂O₃ = 86.04 %

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Answers

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Answers

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A scientist is observing onion cells and human cheek cells under a microscope.Which observation does she most likely make?

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Answers

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Explanation: I took the test and I love the topic. Hope it helps!!!

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