CHEMISTRY HIGH SCHOOL

Your sense of touch is based in your _____.
bones
muscles
skin
tissues

Answers

Answer 1
Answer: umm tissues , because it is caused by receptors .
Answer 2
Answer:

Answer:

Skin

Explanation:

Hope this helps   :)

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As the number of effective collisions between reacting particles increases the rate of reaction
Based on enthalpy of formation data species ∆H◦ f H2S(g) −20.63 kJ/mol O2(g) 0 kJ/mol H2O(ℓ) −285.83 kJ/mol SO2(g) −296.83 kJ/mol calculate ∆Hrxn for 2 H2O(ℓ) + 2 SO2(g) ←→ 2 H2S(g) + 3 O2(g) 1. 562 kJ · mol−1 2. −562 kJ · mol−1 3. −1124 kJ · mol−1 4. 1124 kJ · mol−1

Which of the following compounds will experience dipole-dipole forces of attraction? Cl2
NaCl
H2S
C2H4

Answers

NaCl and H2S will experience dipole-dipole interaction because they are permanently polarized.
NaCl and H2s are the answers

What is the purpose of interphase in the eukaryotic cell cycle?

Answers

The correct answer is cell growth. Basically, during the interphase, the cell grows and the genetic material, the DNA, is multiplied as the cell becomes more and more ready for mitosis. After it's done with interphase, the cell moves into mitosis and cell division continues. The cell spends most of its life in this phase.

active growth and metabolism of the cell  

Correct answer

calculate the molar mass of a gas if 3.30 grams of the has occupies 660 ml at 735mmHg and 27 degrees C

Answers

The molar mass of the gas that occupies the given volume is 127.4 g/mol.

The given parameters;

  • mass of the gas, m = 3.3 g
  • volume of the gas, V = 660 ml = 0.66l
  • pressure of the gas, P = 735 mmHg
  • temperature of the gas, T = 27 ⁰C = 273 + 27 = 300 K

The number of moles of the gas is calculated form ideal gas law as follows;

PV = nRT

where;

  • n is the number of moles
  • R is the gas constant = 62.36 L.mmHg/mol.K

n = (PV)/(RT) \n\nn = (0.66 * 735)/(62.36 * 300) \n\nn = 0.0259 \ mole

The molar mass of the gas is calculated as follows;

no. \ mole = (reacting \ mass)/(molar \ mass) \n\nmolar \ mass = (reacting \ mass)/(no.\ mole) \n\nmolar \ mass =(3.3)/(0.0259) \n\nmolar \ mass = 127.4 \ g/mol

Thus, the molar mass of the gas that occupies the given volume is 127.4 g/mol.

Learn more here:brainly.com/question/24542515
Use the ideal gas law PV = nRT and manipulate it to solve for n. PV/RT = n.Convert to SI units:660ml -> 0.660 L27 degrees -> 300 KLeave Pressure as isUse 62.36368 for R becuase you are using mmHg for Pressure.Now plug into the equation to get about 0.025928 mols. Divide the 3.30 grams by the mols to get about 127 g/mol.

Joel weighs a basket containing 7 peaches.Each peach weigh 200g. How many kilograms does the basket weigh​

Answers

Answer:

Explanation:

1 kg is 1000 grams

1 peach is 200 grams

7 peaches are 200*7 = 1400 grams

Therefore the number of kg = 1400 grams // 1000 grams /kg

The number of kg = 1.4 kg.

Answer:

Explanation:

7 times 200 is 1400 grams but thats not the question it asks in kilo's so i got a converter and the correct answer is 1.4 kilograms

Have a nice day :)

please give me brainiest lol

What is released when the chemical bond is broken between the second and third phosphates of an atp?

Answers

The question was "What is realesed when the chemical bond is broken between the second and third phosphates of an atp?" The answer is hydrolysis.

Final answer:

The breaking of the chemical bond between the second and third phosphates of ATP (Adenosine triphosphate) releases significant energy, transforming ATP into adenosine diphosphate (ADP) and an inorganic phosphate group. The energy released powers various biological processes and reactions within cells. This cycle of breaking and reforming ATP, often referred to as hydrolysis, is crucial to cellular function.

Explanation:

Adenosine triphosphate (ATP) is a high-energy molecule that powers cellular processes. When the chemical bond between the second and third (or beta and gamma) phosphates of ATP is broken, it releases significant energy. This reaction, known as hydrolysis, transforms ATP into adenosine diphosphate (ADP) and an inorganic phosphate group (P;), both of which have lower free energy than the reactants. Here is the specific reaction: ATP + H₂O → ADP + P¡ + free energy.

The breaking of phosphates' strong bonds (phosphoanhydride bonds) releases enough energy to power various cellular reactions and processes. These bonds are considered 'high-energy' due to the amount of energy they release upon breaking.

This continuous cycle of ATP breaking down into ADP and phosphate, followed by their recombination, effectively powers the life processes within cells.

Learn more about Hydrolysis here:

brainly.com/question/31132313

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1 point14. Which factor is not needed hen calculating the velocity of a satellite
orbiting a planet?
the mass of the satellite
the orbital radius of the satellite
the mass of the planet
the universal gravitational constant
Pls help I will give extra points

Answers

The mass of the satellite is not required when calculating the velocity of a satellite  orbiting a planet.

Given that the centripetal force on the satellite is;

F = mv^2/r

Where;

F = centripetal force that keeps the satellite in its orbit

m = mass of the satellite

r = radius of the satellite

Since the force of gravity and the centripetal force both act on the satellite and they are exactly balanced;

F = GMm/r^2

Where;

G = gravitational constant

M = mass of the planet

m = mass of the satellite

r = radius of the satellite

Hence;

F = GMm/r^2 = mv^2/r

GMm/r^2 = mv^2/r

v = √GM/r

Thus, the mass of the satellite is not required when calculating the velocity of a satellite  orbiting a planet.

Learn more: brainly.com/question/21454806

Answer:

i. the mass of the satellite will not be required in this calculation

Explanation:

When a satellite is orbiting a planet, it experiences two forces. The centripetal force and the gravitational force that the planet exerts on the satellite. In order for the satellite to keep in orbit, the centripetal force and the gravitational force must be equal.

The expression for the centripetal force is:

F_c = (m_s)v² / R

where

m_s is the mass of the satellite

R is the radius of the satellite's orbit

v is the velocity that the satellite travels with around the planet

The expression for the Gravitational force is:

F_g = (G M_p m_s) / R²

where

G is the universal gravitational constant

M_p is the mass of the planet

m_s is the mass of the satellite

R is the radius of the satellite's orbit

Thus, equating the two forces together, we get:

(G M_p m_s) / R² = (m_s)v² / R

We can cancel out m_s since it is a common factor on both sides.

Thus,

(G M_p) / R² = v² / R ⇒ M_p = v²R / G

Therefore, the mass of the satellite is not required to calculate the mass of the planet.

Explanation:

Hope this helps:)
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