Sal connected four light bulbs in a parallel circuit. If Sal adds another light bulb, what is true about the current in each bulb?A) The current decreased when a fourth bulb was added.

B) The current in the four bulbs is much less than the current in three bulbs.

C) The current in each bulb remained the same even though another bulb was added.

D) The current in the fourth bulb is less than the current int he other three bulbs.

Answers

Answer 1
Answer:

Since all the bulbs are connected in parallel with each other

so here voltage across each bulb will remains the same

so here we will have

V = i R

now all bulbs are identical and we have same voltage source across all the bulbs

so we will have current in each bulb given by same equation

i = (V)/(R)

now we can say that correct answer will be

C) The current in each bulb remained the same even though another bulb was added.

Answer 2
Answer:

The answer is C) The current in each bulb remained the same even though another bulb was added.


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If the contents of a cell have a solute concentration of 0.04 percent which of these solutions would cause it to swell? A.) 10-percent solute concentration B.) 1-percent solute concentration C.) 0.1 percent solute concentration D.) 0.01 percent solute concentration.

Answers

If the contents of a cell have a solute concentration of 0.04 percent, the solution that would cause it to swell is D) 0.01 percent solute concentration.

An 81 kg stuntman jumps from the top of a building 29 m above a catching net. Assuming that air resistance exerts a 100 N force on the stuntman as he falls, determine his velocity just before he hits the net

Answers

In order to solve this, we can get all tangled up in acceleration,
or we can just add up the energy budget.

-- Gravitational potential energy = (mass) (grav accel) (height above something)

-- 29 m above the net, his potential energy is (81 x 9.8 x 29) = 23,020 joules

-- All the way down, air resistance exerts 100 N of force against him.
The energy burned up by air resistance is the work done = 100 x 29 = 2,900 joules.

-- The energy he has left when he hits the net is (23,020 - 2,900) = 20,120 joules.

-- When he hits the net, all of his energy is kinetic energy . . . (1/2) (m) (v²)

(1/2) (m) (v²) = 20,120

(40.5) (v²) = 20,120

v² = 20,120 / 40.5

v = square root of (20,120 / 40.5) = 22.3 meters per second (about 50 mph)

What is the energy of a photon whose frequency is 6.0x10^20 hz?

Answers

Energy of photon is given by formula

E = h\nu

here

h = Planck's constant

h = 6.6* 10^(-34)

\nu = frequency = 6 * 10^(20)Hz

now the energy is given by

E = 6.6*10^(-34) * 6 * 10^(20)

E = 3.96 * 10^(-13) J

give me some answer choices and i will be happy to help

An apple is placed 20.0 cm in front of a diverging lens of focal length 10.0 cm. Find the image distance and the magnification of the apple.

Answers

Answer:

Image distance of apple=-6.7 cm

Magnification of apple=0.33

Explanation:

We are given that an apple is placed 20.cm in front of a diverging lens.

Object distance=u=-20 cm

Focal length=f=-10 cm

Because focal length of diverging lens is negative.

We have to find the image distance and magnification of the apple.

Lens formula

(1)/(f)=(1)/(v)-(1)/(u)

Substitute the values then we get

-(1)/(10)=(1)/(v)+(1)/(20)

(1)/(v)=-(1)/(10)-(1)/(20)

(1)/(v)=(-2-1)/(20)=-(3)/(20)

v=-(20)/(3)=-6.7 cm

Image distance of apple=-6.7 cm

Magnification=m=(v)/(u)=(-(20)/(3))/(-20)

Magnification of apple=(1)/(3)=0.33

Hence, the magnification of apple=0.33

When the resultant force acting on a system is zero, the total momentum of the system...

Answers

When the resultant force acting on a system is zero, the total momentum of the system remains constant. This is known as the principle of conservation of momentum. In other words, if the net external force acting on a closed system is zero, the total momentum of that system will not change over time. This principle is commonly applied in physics, particularly in scenarios involving collisions and interactions between objects.

You have a very old service manifold and the high-pressure gauge on this service manifold set has a continuous scale, calibrated to read from 0 to 500 psig. TRUE or FALSE.

Answers

That statement is FALSE

the scale that calibrated to read from 0 to 500 is usually the standard used by the new kind of service

the older one usually only take up to 340

hope this helps