A radioactive nuclide is used to detect eye tumors. An atom of this radionuclide contains 15 protons, 15 electrons, and 17 neutrons. Which is symbol of this radionuclide?

Answers

Answer 1

Answer: The answer is phosphorus-32.

We know that the atom contains 15 protons, 15 electrons, and 17 neutrons.
To conclude of which element this radionuclide is, we need to know an atomic number of the element. The atomic number of the element is the number of proton in the nucleus of the atom. If the number of protons is 15, then the atomic number is 15. The element with atomic number 15 is phosphorus (according to the periodic table).
To conclude which phosphorus isotope this radionuclide is we need to know the mass number of the element. The mass number of the element is the sum of the number of protons and number of neutrons in the nucleus of the atom. If the number of protons is 15 and the number of neutrons is 17, then the mass number is 17 + 15 = 32.
Thus, this radionuclide is phosphorus-32.

Answer 2

Answer: Knowing that the number of protons of an element is equivalent to its atomic number, it can be determined from the periodic table of elements that this radionuclide is phosphorus. Since the number of its neutrons is 17, it can also be determined that its atomic mass is n + p = 15 + 17 = 32. This means the isotope is phosphorus-32.

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What element is found in amino acid that isn’t found in simple sugars like glucose or fructose?

Answers

Nitrogen is the major atom that is present in amino acids that are not present in carbohydrates.

Calculate the change of enthalpy for the reaction CH4 (g) + NH3 (g) --> HCN (g) +3H2 (g) from the following reactions: Reaction 1: N2 (g) + 3H2 (g) --> 2NH3 (g) Change in enthalpy: -91.8 kJ/mol

Reaction 2: C (s, graphite) + 2H2 (g) --> CH4 (g) Change in enthalply: -74.9 kJ/mol

Reaction 3: H2 (g) + 2C (s, graphite) + N2 (g) --> 2HCN (g) Change in enthalpy: +270.3 kJ/mol

Include the following:

The numerical answer with correct units.
State which reactions, if any, you had to "Flip".
State which reactions you had to multiply, if any, to get the correct amount of the compound.

Answers

The enthalpy for the reaction, ΔH rxn is 255.95 kJ/mol

From the question,

We are to calculate the change in enthalpy for the reaction

CH₄(g) + NH₃(g) → HCN(g) +3H₂(g)

From the given reactions

Reaction 1: N₂(g) + 3H₂(g) → 2NH₃(g) Change in enthalpy: -91.8 kJ/mol

Reaction 2: C(s, graphite) + 2H₂(g) → CH₄(g) Change in enthalply: -74.9 kJ/mol

Reaction 3: H₂(g) +2C(s, graphite) +N₂(g) → 2HCN (g) Change in enthalpy: +270.3 kJ/mol

First, flip reactions 1 and 2 to get reaction 4 and 5 respectively

Reaction 4: 2NH₃(g) → N₂(g) + 3H₂(g) ΔHo : 91.8 kJ/mol

Reaction 5: CH₄(g) → C(s, graphite) + 2H₂(g) ΔHo : 74.9 kJ/mol

Now, multiply reactions 4 and 3 by half (1/2) to get 6 and 7 respectively

Reaction 6: NH₃(g) → ¹/₂N₂(g) + ³/₂H₂(g) ΔHo : 45.9 kJ/mol

Reaction 7: ¹/₂H₂(g) +C(s, graphite) +¹/₂N₂(g) → HCN (g) ΔHo : +135.15 kJ/mol

Now,

Add reactions 5, 6, and 7 together

Reaction 5: CH₄(g) → C(s, graphite) + 2H₂(g) ΔHo : 74.9 kJ/mol

Reaction 6: NH₃(g) → ¹/₂N₂(g) + ³/₂H₂(g) ΔHo : 45.9 kJ/mol

Reaction 7: ¹/₂H₂(g) +C(s, graphite) +¹/₂N₂(g) → HCN(g) ΔHo : +135.15 kJ/mol

-------------------------------------------------------------------------------------------------------------

CH₄(g) + NH₃(g) → HCN(g) + 3H₂(g) ΔH rxn = 255.95 kJ/mol

Hence, the enthalpy for the reaction, ΔH rxn is 255.95 kJ/mol

Learn more here: brainly.com/question/13779366

Answer:

255.8 kj/mol

Explanation:

So this is a Hess' Law problem, the CH₄ (g) + NH₃ (g) --> HCN (g) + 3H₂ (g) is what we want the other reactions to reflect. I usually set up problems like these like this in order to determine which reaction needs a coefficient change:

N₂ + 3H₂ --> 2NH₃ (ΔH=-91.8)

C + 2H₂ --> CH₄ (ΔH=-74.9

H₂ + 2C + N₂ --> 2HCN (ΔH=270.3)

CH₄ + NH₃ --> HCN + 3H₂

(I left out the states because it'll make the math easier) So, we want things to cancel out, meaning some of the reactants and products need to change places in order to do so. For the first reaction, we'd want to multiply the coefficients by $(1)/(2)$ in order to have it cancel out with the other reactions. For the third reaction, we'd want to we'd want to switch the products/reactants and multiply the coefficients by $(1)/(2)$ . Keep in mind whatever we do to the equation, we do to the ΔH. Should look like:

$(1)/(2)$ N₂ + $(3)/(2)$ H₂ --> NH₃ (ΔH=-45.9)

C + 2H₂ --> CH₄ (ΔH=-74.9)

HCN --> $(1)/(2)$ H₂ + C + $(1)/(2)$ N₂ (ΔH=-135)

CH₄ + NH₃ --> HCN + 3H₂

Everything cancels, so that means we can add all the ΔH, which should be -255.8 kj/mol, but we also change the sign in order to reflect what's happening in the reaction. (Sorry this is so long)

A yellow element stinks when burned

Answers

The yellow element that stinks when burned is sulfur.

Sulfur is a chemical element with the symbol S and atomic number 16. It is a non-metal that is a member of the chalcogen group in the periodic table. Sulfur is a yellow solid at room temperature. It is insoluble in water but soluble in carbon disulfide. When sulfur is burned, it produces a foul-smelling gas called sulfur dioxide.

Sulfur dioxide is a colorless gas with a pungent, irritating odor. It is a major air pollutant and can cause respiratory problems. Sulfur is used in a variety of applications, including the production of sulfuric acid, gunpowder, and rubber. It is also used in the vulcanization of rubber. Sulfur dioxide is a highly reactive gas. Sulfur dioxide has a low boiling point. Sulfur dioxide is heavier than air.

To know more about the Element, here

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Sulfur smells like rotten egg and is yellow...

Which of the following has the most electrons?A) Sr^{2+}
B) Rb
C) Cl^{-}
D) Kr