2 x + 2 x < - 3
X x = -3
- x - 2 X > -3
y = -6
y=-4
y=-3
y = 0
y = 1
y = 3
-6, -4, -3, and 0 are the values which are within the range of the piecewise-defined function.
Correct options: a) y = -6, b) y = -4, c) y = -3, d) y = 0
Here, we have, to determine which values are within the range of the piecewise-defined function, we need to evaluate the function for each given value of y.
Given piecewise-defined function:
f(x) =
2x, x < -3
x, x = -3
-x - 2, x > -3
Let's evaluate the function for each value of y:
a) y = -6
For y = -6, we need to find x such that f(x) = -6.
-6 is in the range of the function if there exists an x such that f(x) = -6.
For x < -3: f(x) = 2x
2x = -6
x = -3
For x = -3: f(x) = x
x = -3
For x > -3: f(x) = -x - 2
-x - 2 = -6
x = 4
Since there is a value of x (-3) that satisfies f(x) = -6, option a) y = -6 is correct.
b) y = -4
For y = -4, we need to find x such that f(x) = -4.
-4 is in the range of the function if there exists an x such that f(x) = -4.
For x < -3: f(x) = 2x
2x = -4
x = -2
For x = -3: f(x) = x
x = -3
For x > -3: f(x) = -x - 2
-x - 2 = -4
x = 2
Since there is a value of x (-3) that satisfies f(x) = -4, option b) y = -4 is correct.
c) y = -3
For y = -3, we need to find x such that f(x) = -3.
-3 is in the range of the function if there exists an x such that f(x) = -3.
For x < -3: f(x) = 2x
2x = -3
x = -1.5
For x = -3: f(x) = x
x = -3
For x > -3: f(x) = -x - 2
-x - 2 = -3
x = 1
Since there is a value of x (-3) that satisfies f(x) = -3, option c) y = -3 is correct.
d) y = 0
For y = 0, we need to find x such that f(x) = 0.
0 is in the range of the function if there exists an x such that f(x) = 0.
For x < -3: f(x) = 2x
2x = 0
x = 0
For x = -3: f(x) = x
x = -3
For x > -3: f(x) = -x - 2
-x - 2 = 0
x = -2
Since there is a value of x (-3) that satisfies f(x) = 0, option d) y = 0 is correct.
e) y = 1
For y = 1, we need to find x such that f(x) = 1.
1 is in the range of the function if there exists an x such that f(x) = 1.
For x < -3: f(x) = 2x
2x = 1
x = 0.5
For x = -3: f(x) = x
x = -3
For x > -3: f(x) = -x - 2
-x - 2 = 1
x = -3
Since there is no value of x that satisfies f(x) = 1, option e) y = 1 is incorrect.
f) y = 3
For y = 3, we need to find x such that f(x) = 3.
3 is in the range of the function if there exists an x such that f(x) = 3.
For x < -3: f(x) = 2x
2x = 3
x = 1.5
For x = -3: f(x) = x
x = -3
For x > -3: f(x) = -x - 2
-x - 2 = 3
x = -5
Since there is no value of x that satisfies f(x) = 3, option f) y = 3 is incorrect.
Correct options: a) y = -6, b) y = -4, c) y = -3, d) y = 0
The correct values within the range of the piecewise-defined function are -6, -4, -3, and 0.
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Answer:
-6, -4, -3, 0
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P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
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563
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true
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