MATHEMATICS HIGH SCHOOL

What is the factored form of 6x^2 + 13x + 6?A.) (x + 4)(x + 9)
B.) (2x + 3)(3x + 2)
C.) (2x + 6)(3x + 1)
D.) (6x + 1)(6x + 1)

Answers

Answer 1
Answer: The answer would be B.first you would have to multiply the first coefficient,6 with the last term. being 6,                                                                                                   6·6 = 36.Now there is a few factors such as 1,2,3,4,6,9,12,18,36, and the negatives of these numbers, but i wont list them,i will just use the numbers i need for this problem.so i will replace the number 13 in this equation.              [6ײ+4×]+[9×+6]. then i will factor the GCF 2 into the first group and then factor 3 in the second group. 2×[3×+2]+3·[3×+2]. then i would have to factor out the two numbers out of the term 3×+2 then combine the like terms making the equation [2×+3]·[3×+2] making the answer B. Hope i helped bye.
Answer 2
Answer:

The correct answer is option B.) (2x + 3)(3x + 2).

Given that the factored form of 6x^2 + 13x + 6 is equivalent to which of the following.

A.) (x + 4)(x + 9)

B.) (2x + 3)(3x + 2)

C.) (2x + 6)(3x + 1)

D.) (6x + 1)(6x + 1)

To determine the factored form of the quadratic expression 6x^2 + 13x + 6, we can apply the factoring technique. We are looking for two binomials in the form (px + q)(rx + s) that, when multiplied, result in the original expression.

To factor the expression, we need to find two numbers whose product is equal to 6 * 6 = 36 and whose sum is equal to 13.

The numbers that satisfy these conditions are 4 and 9.

Therefore, the factored form of the expression is:

(2x + 3)(3x + 2)

So, the correct answer is option B.) (2x + 3)(3x + 2).

Learn more about factoring quadratic expressions click here: brainly.com/question/14680354

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Answers

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