Select all that apply.Which of the following are equivalent?

0.4
40%
4%
2/5

Answers

Answer 1

Answer: 4% is not equivalent to 40%
0.4 is equivalent to 40%. Just move the decimal two places to the right.
2/5 is equivalent to 0.4, which in turn is equivalent to 40%. 2 divided by 5=0.4
The answers are all but 4%

Answer 2

Answer:

Answer:

All but 4%

Step-by-step explanation:

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The value of Maggie's car decreased by 20% since last year, when she bought it. If the car is now worth $15,000.00, how much was the car worth when she bought it? A. $20,000.00 B. $17,647.06 C. $18,000.00 D. $18,750.00
I need help w this soon

Please help i need answers

Answers

Answer:

Step-by-step explanation:

the bottom one would be 12x27 shape

the middle one would be 8x18 shape

the top one would be 9x4 9x4 shape

Help please. what does x equal.

Answers

The answer would be 53

Write a solution in Interval Notation - (you don't have to help me on all, 1 or 2 is fine c: )1) | m | -2 > 0

2) | x - 4 | - 3 > 5

3) | 6 + 9x | ≤ 24

4) | 1 - 5a | > 29

Answers

QUESTION 1

The given inequality is

$|m|-2>0$

We group like terms to get,

$|m|>2$

This implies that,

$-m>2$ or $m>2$ .

We simplify the inequality to get,

$m<-2$ or $m>2$ .

We can write this interval notation to get,

$(-\infty,-2)\cup (2,+\infty)$ .

QUESTION 2

$|x-4|-3\:>\:5$ .

We group like terms to get,

$|x-4|\:>\:5+3$ .

$|x-4|\:>\:8$

We split the absolute value sign to get,

$-(x-4)\:>\:8$ or $x-4\:>\:8$

This implies that,

$x-4\:<\:-8$ or $x-4\:>\:8$

$x\:<\:-8+4$ or $x\:>\:8+4$

$x\:<\:-4$ or $x\:>\:12$

We can write this interval notation to get,

$(-\infty,-4)\cup (12,+\infty)$ .

QUESTION 3

The given inequality is

$|6+9x|\leq 24$

We split the absolute value sign to obtain,

$-(6+9x)\leq 24$ or $(6+9x)\leq 24$

This simplifies to

$6+9x\ge -24$ and $6+9x\leq 24$

$9x\ge -24-6$ and $9x\leq 24-6$

$9x\ge -30$ and $9x\leq 18$

$x\ge -(10)/(3)$ and $x\leq 2$

$-(10)/(3)\leq x\leq2$

We write this in interval form to get,

$[-(10)/(3),2]$

QUESTION 4

The given inequality is

$|1-5a|>29$

We split the absolute value sign to get,

$-(1-5a)>29$ or $1-5a>29$

This simplifies to,

$1-5a\:<\:-29$ or $1-5a\:>\:29$

This implies that,

$-5a\:<\:-29-1$ or $-5a\:>\:29-1$

$-5a\:<\:-30$ or $-5a\:>\:28$

$a\:>\:6$ or $a\:<\:-(28)/(5)$

We write this in interval notation to get,

$(-\infty,-(28)/(5))\cup (6,+\infty)$

A 91 square foot bathroom has a length of 13 feet. what is the width of the bathroom

Answers

91 divided by 13 is 7. if the bathroom is 91 feet square, and the length is 13 feet, then the width is 7 feet

Answer:

Step-by-step explanation:

well just go to brainly my my 67

It's not the 4th one:)

Answers

I believe that it is the second one. Intersection, union.

State the x-coordinate of the x-intercept in quadrant II for the function below.f(x)=x^3-x^2-x+1

Answers

The x-coordinate of the x-intercept in quadrant || for the given function is -1.

x = -1.

What are coordinates?

Coordinates are a set of values that helps to show the exact position of a point in the coordinate plane.

We have,

x-intercept in quadrant ||.

f(x) = x³ - x² - x + 1

x-intercept means y = 0 so,

f(x) = y

0 = x³ - x² - x + 1

We see that,

when x = -1 we get,

f(x) = -1 - 1 + 1 + 1 = 0

When x = 1 we get,

f(x) = 1 - 1 - 1 + 1 = 0

But we can not take x = 1 because in quadrant || x is a negative value.

Thus,

The x-coordinate of the x-intercept in quadrant || for the given function is -1.

Learn more about coordinates here:

brainly.com/question/721528

#SPJ2

ANSWER

The x-coordinate of the x-intercept of the function $f(x)=x^3-x^2-x+1$ is $-1$ .

EXPLANATION:

The x-intercept refers to the point where the function meets or cuts the x-axis.

At the x-intercept, $f(x)=0$ .

This means we have to equate the whole function to zero and solve for $x$ .

$x^3-x^2-x+1=0$

According to the rational roots theorem, the possible rational roots of the equation $x^3-x^2-x+1=0$ are $\pm 1$ .

We now plug in these possible rational roots to see which of them are real roots.

$f(1)=1^3-1^2-1+1$

$f(1)=1-1-1+1$

$f(1)=-1+1$

$f(1)=0$

Since $f(1)=0$ , $x=-1$ is a root.

By the factor theorem, $x+1$ is a factor of the function.

We now divide the polynomial function, $x^3-x^2-x+1=0$ by $x+1$ to find the remaining roots.

See long division in diagram.

This means that $f(x)=(x+1)(x^2-2x+1)$ .

$f(x)=(x+1)(x-1)^2$

$\Rightarrow (x+1)(x-1)^2=0$

Hence the roots are $x=1$ or $x=-1$

In the second quadrant the x-coordinate is negative

Therefore, the x-coordinate of the x-intercept of the function $f(x)=x^3-x^2-x+1$ is $-1$ .

See graph in attachment

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Select all that apply.Which of the following are equivalent? 0.4 40% 4% 2/5

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What are coordinates?

Select all that apply.Which of the following are equivalent?

0.4
40%
4%
2/5