(2) The atom absorbs energy, and one or more electrons move to a lower electron shell.
(3) The atom releases energy, and one or more electrons move to a higher electron shell.
(4) The atom releases energy, and one or more electrons move to a lower electron shell.
1) The atom absorbs energy, and one or more electrons move to a higher electron shell.
So all the statements except 1) are false.
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(1) average potential energy of the particles of
the sample
(2) average kinetic energy of the particles of the
sample
(3) total nuclear energy of the sample
(4) total thermal energy of the sample
N,Br
To calculate the molecular formula, convert the mass ratio into molar ratio as follows:
mass ratio of O:C=2:1
molar mass of carbon is 12 g/mol and that of oxygen is 16 g/mol thus, number of moles can be calculated as follows:
n=\frac{m}{M}
calculating ratio,
O:C=\frac{2 g}{16 g/mol}:\frac{1 g}{12 g/mol}=\frac{1}{8}:\frac{1}{12}=12:8=3:2
thus, molecular formula will be C_{2}O_{3}
If the ratio of oxygen to carbon by mass is 2.00:1.00, the formula of the oxide of carbon is CO₂ (carbon dioxide). This is because CO₂ has twice as much oxygen per amount of carbon as compared to CO (carbon monoxide). This situation adheres to the law of multiple proportions.
This question revolves around the concept of stoichiometry in chemistry, particularly in relation to the law of multiple proportions and finding the formula of an oxide of carbon given specific mass ratios.
Firstly, in carbon monoxide (CO), the ratio of oxygen to carbon by mass is 1.33:1.00.
However, when the ratio of oxygen to carbon by mass increases to 2.00:1.00, we are now dealing with a compound that contains twice as much oxygen per amount of carbon. In essence, this would be carbon dioxide (CO₂). The mass ratio of oxygen to carbon in CO₂ is indeed 2:1 (32 g/mol oxygen: 12 g/mol carbon).
This situation illustrates the law of multiple proportions - in this case, the two oxides of carbon (CO and CO₂) contain elements combined in ratios of small whole numbers.
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Answer:
0.00496
Explanation:
on edg i just did the assignment teehee
A rate equation can be written based on the rate constant k, concentration of reactants and half life time t1/2 of reactant if given. [A⁰] is the initial concentration of reactant A and [A]t be the final concentration.
Rate of a reaction is the rate of decrease in concentration of reactants or rate of increase in concentration of products. Rate of the reaction written in terms of molar concentration of reactants is called the rate law.
Consider the simplest reaction A gives B. Here the only one reactant is A. The molar concentration of A is written as [A]. The rate constant k is then,
k = [B] / [A]
If any coefficients attached with them it is written as power of the concentration term. Now, the rate of the above reaction is written as follows:
rate r = k [A]
Sometimes the initial and final concentrations of A can be considered. Where, [A⁰] is the initial concentration and [A]t be the final concentration.
The half life t1/2 is the time taken to consume half of the reactants concentration.
To find more about rate law, refer the link below:
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